Your response, coupled with a link to an irrelevant post, ...
According to the current agreement about ZFC, which is totally depends on the current subjective level of thoughts among traditional mathematicians like you, the notion of set is not a tautological existence within ZFC, so?There is no such notion within ZFC according to its axiomatic foundation.
[And now, for something completely different...]
According to the current agreement about ZFC
It is a good example of how your subjective level of thoughts can't comprehend that the current ZFC axiomatic system is derived from your subjective level of thoughts.It is not an agreement. It is an axiomatic system.
You are completely ignore what I posted and all of its surrounding context
Yes, 100% discount of http://www.internationalskeptics.com/forums/showpost.php?p=10114474&postcount=4162 or http://www.internationalskeptics.com/forums/showpost.php?p=10114571&postcount=4164.You continue to get that wrong. Not ignore, discount. I discount your posts.
So you are using the notion of set in order to define the rules of WFF, which are used to define sets.You have yet to show that. All well-formed formulae, by their very definition, can be constructed from a small set of rules. ∃x cannot be constructed from those rules, and so ∃x is not a well-formed formula.
Yes. You seem to be beginning to understand.
So you are using the notion of set in order to define the rules of WFF, which are used to define sets.
No, I'm using colloquial language to express an idea.
Time does not change the fact that your colloquial language maneuvers are not impressive.Are you really so starved for attention you are dredging up all these old posts?
Shouldn't you be aware of the fact that 100% discount of X is no more than a colloquial language that is equivalent to ignoring X?Shouldn't you be off opening a TM clinic to save the Middle East from mass destruction?
It is not an agreement. It is an axiomatic system.
Time does not change the fact that your colloquial language maneuvers are not impressive.
colloquial language maneuvers
Let's use baby steps in order to rebuild the communication between us.Doron please don't take offense but after 10,000+ posts it appears that you have failed to impress the great majority of posters on this board.
Let's use baby steps in order to rebuild the communication between us.
I say: "Wars start and end in people's minds, so the solution is profoundly related to people's minds".
Do you agree/disagree about that?
I take it as an axiom (where axioms do not need proves).Off-topic BS. Please prove your claims.
I take it as an axiom (where axioms do not need proves).
If you disagree that "Wars start and end in people's minds" then air your detailed view about it.
...
So here the draft of my idea:
[0,1] is a non-empty closed interval that includes all the real numbers between 0 and 1 (including 0 and 1).
Let X be the set of closed intervals of R members that are included in [0,1], as follows:
X={[0,x1],[x1,x2],[x2,x3],[x3,x4],[x4,x5],…}, where |X|=|X={[0,x1],[x1,x2],[x2,x3],[x3,x4],[x4,x5],…}|
...
The closed interval of the form [x|N|,1] is equivalent to the mathematical expression |N|<|R|.
Thank you jsfisher for your remarks.That's a matter of definition. No need to restate it.
This lacks clarity. Based on how the rest of your post goes, I assume you mean something more like:
Let P be the ordered sequence 0 < a < b < c < d < ... < z < 1 and X = { [0,a], [a,b], [b,c], [c,d], ..., [z,1] }.This works fine for finite sequences, but if you intend to extend P to be an infinite sequence, it doesn't work so well. There is no last element, z, you can reference by its index.
So that's one problem you will need to resolve. Another is that an infinite sequence could have the same cardinality as R. Later in your post you assumed it to be limited to |N|.
This does not follow from anything you posted. Moreover, it is unlikely you will be able to show equivalence of any interval to an order relationship.
Thank you jsfisher for your remarks.
Let's start form some particular example, and try to develop it without loss of generality.
First there is [0,1]
Ok, let's put the infinite sequence 1/2, 1/4, 1/8, 1/16, ... along [0,1], by using the convergent series 1/2+1/4+1/8+1/16+...
Please correct me if I am wrong, but as I understand it |{1/2, 1/4, 1/8, 1/16, ...}| = |N|
First, I have tried to express this sequence in terms of set of closed intervals along [0,1], as follows:
X =
{
[x1,x2], (is [0.0,0.5])
[x2,x3], (is [0.5,0.75])
[x3,x4], (is [0.75,0.875])
[x4,x5], (is [0.875,0.9375])
[x5,x6], (is [0.9375,0.96875])
...
}
Since there is a bijection form X to {1/2, 1/4, 1/8, 1/16, ...}, then |X| = |N|
Any X member is a closed interval of the general form [xn,xn+1] that includes its own |R| amount of unique R members.
There is [x1,x2] which has only one overlap,
and the other closed interval which has only one overlap is [x?,1].
It must be stressed that without [x?,1] as a member of X, X members can't fully cover [0,1].
So what is the index of [x?,1]?
In order to get [1,1]...
...
So we have proved that only finitely many closed intervals (where each one of them has |R| R members can actually fully cover [0,1]
...
I know that Cantor set has |R| members , but is it also a convergent sequence?
Generally, as I get it, the number of R members along a given closed interval > 0, has no impact on its length.
jsfisher, I am sorry, I have edited my post during your reply.
So, if you wish, please refresh your screen in order to see the edited version.
Sorry again and thank you.
Sorry, maybe I have missed something.Really? You proved that? What about Y = X union {[1,1]}. Isn't Y an infinite set? Do the members of Y not fully cover the interval, [0,1]?
For example [0,0.5] and [0,1] have the same cardinality (|R|) but not the same length.I don't know what you mean by this.
Yes, I noticed the additions, but it really doesn't change things. Your interval set construction leaves out one point, [1,1].
Sorry, maybe I have missed something.
How exactly [1,1] which is a single point, can fully cover [0,1], in terms of length?
(Also, as I get it, the number of R members along a given closed interval > 0, has no impact on its length, and please correct me if I am wrong, as I get it convergent sequence is about length (including length 0)).
Yes, but please show how you construct [0,1] by the series 1/2+1/4+1/8+1/16+... , such that [1,1] is included?Do you accept that the members of your set of intervals, X, cover [0,1)? Then X union [1,1] would cover [0,1], no?
Yes. So what mathematical definition makes the difference?Your wording is awkward and hard to follow. Are you trying to say that the length of two intervals may be different even though the "number" of points on each interval is the cardinality of the continuum?
Yes, but please show how you construct [0,1] by the series 1/2+1/4+1/8+1/16+... , such that [1,1] is included?
Yes. So what mathematical definition makes the difference?
Jsfisher,
Please explain how exactly
X =
{
[x1,x2], (is [0.0,0.5])
[x2,x3], (is [0.5,0.75])
[x3,x4], (is [0.75,0.875])
[x4,x5], (is [0.875,0.9375])
[x5,x6], (is [0.9375,0.96875])
...
}
is different than Y = {1/2, 1/4, 1/8, 1/16, ...} ?
Thank you.
Thank you for your explanation.I already did. You just didn't like the construction. I used your set, X, which was in fact constructed from the original sequence then added the singleton, [1,1], to make the set Y.
It seems like you are asking me to show where 0.999... occurs in the sequence, 0.9, 0.99, 0.999, 0.9999, .... It doesn't.
Please rigorously define how [0,0.999...) (which has cardinality |R| and length 0.999...) is actually length 1 by adding 0 length to length 0.999... if there is no impact on length, from the point of view of cardinality of the points along the interval [0,0.999...) ?I'm not sure where you are trying to go with this. Length makes the difference. Two intervals can differ in length. If [a,b] is an interval, then b-a is its length. (The same measure works for open and half-open intervals, too.)
Length is one measure than can be applied to an interval. Cardinality of the points along the interval would be another (although considerably less interesting).
Ok, thank you for the clarification.First, lest there be any confusion, that's not my set, Y.
I do not understand this part.With your sets X and Y as given (and assuming the natural ordering and the generator function discussed earlier), there is a simple relationship between the two sets, and so they are, in that sense, equivalent.
Equivalent does not mean identical. Clearly X and Y are different because their memberships are disjoint. E.g., 1/2 is an element of Y but not of X.
Thank you for your explanation.
I do not ask you to show where 0.999... occurs in the sequence, 0.9, 0.99, 0.999, 0.9999 .
I ask you to show where 0 occurs in the sequence 0.9, 0.09, 0.009, 0.0009, ..., or more precisely, in the series 0.9+0.09+0.009+0.0009+... ?
And even if 0 is added to the length of the series 0.9+0.09+0.009+0.0009+... , how this series has length 1 by adding length 0 to it?
As I understand it, adding 0 length to finite or infinite series, has no impact on its length
...exactly as adding the closed interval [1,1] (which has the finite cardinality |1| = |{1}|) to a sequence of closed intervals (where each one of them has cardinality |R|) has no impact on cardinality |R| (after all |R|+|1| = |R| , by transfinite arithmetic).
So I still do not understand how {[0,1),[1,1]} (which has the finite cardinality |2|), and {[0,1)} (which has the finite cardinality |1|), has any impact on cardinality |R| (after all |R|+|2| = |R|+|1| = |R| , by transfinite arithmetic).
Please rigorously define it, in order to help me to understand it (whether I dislike it, or not).
Please rigorously define how [0,0.999...) (which has cardinality |R| and length 0.999...) is actually length 1 by adding 0 length to length 0.999... if there is no impact on length, from the point of view of cardinality of the points along the interval [0,0.999...) ?
Ok, thank you for the clarification.
I do not understand this part.
Please rigorously explain the difference between [0,0.5] and 1/2 .
After all both of them are essentially the same mathematical thing (known as length) by simply using different notations (and even if you think that cardinality is "considerably less interesting" |{[0,0.5]}| = |{1/2}| = |1|).
jsfisher, thank you for the last two posts.
This is what I understand according to them:
A value is an abstract mathematical expression that its meaning is given according to a given context.
For example, 1 is an abstract and general mathematical expression, where one of its possible meanings is understood in terms of length, for example, the expression [1,1] is one of infinitely many possible ways in order to define length 0, where 0 is another example of an abstract and general mathematical expression.
What is called the real line, is a collection of such abstract and general mathematical expression.
One of the possible meanings of the real line is defined in terms of length, and one carefully has to distinguish between the real-line as an abstract and general mathematical expression, and one of its possible meanings (where length is an example of some particular meaning.
jsfisher said:On the other hand, were you able to demonstrate some inconsistency or contradiction arising from the definition of limits or from 0.999... = 1, that might be worth discussing.