How would you know? Your analogy has not been discussed at all except for a side reference you completely failed to understand. So, the only evidence available so far is that you are the only one lacking some understanding of the red photon analogy.
The red photon is equivalent to a finite case that is used in order to conclude something about a non-finite case.
It is obvious that we can't used notions taken from a finite collection and use them in order to conclude something about a non-finite collection.
Standard Math fails exactly because of this reason, as follows:
By this assumption we get Z as the largest element of the set.
In this case you are based on the finite case of the comparison between distinct X and distinct Z, which are the two (where two is a finite cardinal) extreme cases of [X,Z] interval, such that X < Z < Y.
It has to be noticed that Z is the smallest element of the interval [Z,Y), so we are still under a,b construction , where in this case Z is the smallest distinct element and Y is the largest distinct element.
Also in this case we deal with the finite case of two (where two is a finite cardinal) distinct values, that can't be used in order to conclude anything about the non-finite collection of all elements of [Z,Y) interval.
In other words, no matter what you do, you are closed under
the finite case of a,b construction, and cannot use it in order to conclude anything about
the non-finite case of a,b construction (whether it is (X,Y) , (X,Y] , [X,Y) or [X,Y], it does not matter).
It means that you are stacked at the first row of your "proof" (under the finite case of a,b construction) and never reach to the second row of your "proof".
As a result, there is no proof, and there is no conclusion that is derived from this proof.
You are right about this. Your "proof" is not even born.