The Man
Unbanned zombie poster
Again, all there is in this case is "<" between real numbers.
What you call interval is nothing but an illusion that is based on manipulations with notations without any notion.
So the answer to your question is d, such that 0<d<x and 0 is not an immediate predecessor of any real number x of the interval (0,1].
You still did not get it, so here it is again:
Let us play the game of the intervals like this:
X>0
[0,0]<[X,X]
Now, it does not matter what X is, [0,0] is not an immediate predecessor of X because no real number is an immediate predecessor of another real number.
Things do not change also in the case of [0,0]<(0,X]. Also in this case [0,0] is not an immediate predecessor of any X.
You may claim that in the case of [0,0]<[X,X] d of the expression 0<d<X is not in [0,0] interval and not in [X,X] interval, and as a result [0,0] is not an immediate predecessor of [X,X].
Then you may claim that in the case of [0,0]<(0,X] d of the expression 0<d<X is an element of the interval (0,X] and therefore [0,0] is an immediate predecessor of (0,X] interval.
But this claim is nothing but a manipulation with notations without notions, because "<" relation has a meaning only between the elements of the intervals, where the intervals have nothing to do with "<" relation.
At the moment that you get the simple notion that "<" has a meaning only between the elements of the intervals, you immediately understand that 0<d<X has exactly the same meaning in [0,0]<[X,X] and in [0,0]<(0,X].
You still do not ‘get it’ simply because of your ignorance or simply lying to yourself
You have already stated..
[0,0] is < (0,1] if you disagree …
I agree. <snip>
So [0,0] is < (0,1], the only other requirement for an immediate predecessor is that no other real numbers or intervals are between [0,0] and (0,1]. So again please show a real number or interval between [0,0] and (0,1].