Deeper than primes

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Again, all there is in this case is "<" between real numbers.

What you call interval is nothing but an illusion that is based on manipulations with notations without any notion.

So the answer to your question is d, such that 0<d<x and 0 is not an immediate predecessor of any real number x of the interval (0,1].

You still did not get it, so here it is again:

Let us play the game of the intervals like this:

X>0

[0,0]<[X,X]

Now, it does not matter what X is, [0,0] is not an immediate predecessor of X because no real number is an immediate predecessor of another real number.

Things do not change also in the case of [0,0]<(0,X]. Also in this case [0,0] is not an immediate predecessor of any X.

You may claim that in the case of [0,0]<[X,X] d of the expression 0<d<X is not in [0,0] interval and not in [X,X] interval, and as a result [0,0] is not an immediate predecessor of [X,X].

Then you may claim that in the case of [0,0]<(0,X] d of the expression 0<d<X is an element of the interval (0,X] and therefore [0,0] is an immediate predecessor of (0,X] interval.

But this claim is nothing but a manipulation with notations without notions, because "<" relation has a meaning only between the elements of the intervals, where the intervals have nothing to do with "<" relation.

At the moment that you get the simple notion that "<" has a meaning only between the elements of the intervals, you immediately understand that 0<d<X has exactly the same meaning in [0,0]<[X,X] and in [0,0]<(0,X].

You still do not ‘get it’ simply because of your ignorance or simply lying to yourself

You have already stated..

[0,0] is < (0,1] if you disagree …

I agree. <snip>

So [0,0] is < (0,1], the only other requirement for an immediate predecessor is that no other real numbers or intervals are between [0,0] and (0,1]. So again please show a real number or interval between [0,0] and (0,1].
 
So [0,0] is < (0,1], the only other requirement for an immediate predecessor is that no other real numbers or intervals are between [0,0] and (0,1]. So again please show a real number or interval between [0,0] and (0,1].

Hmmm... There's definitely no rational number between them.

Maybe the answer is ((1) - (0.999...)) = ?
 
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That's pretty much what I had in mind by difference. So lets say you have two intervals: [1, 5] and [7, 10]. By difference I mean distance between them which would be: (7) - (5) = 2. So the difference between the two intervals is two. But you have the really odd issue of adjacent intervals, like the one brought up by doron.

It is not that odd or different from what you have just said in discrete math (like with integers). However, in a continuous frame work it can get confusing unless you are very specific and consistent in the definitions and relationships.

So what if you had [1, 5] and (6, 10]? What would be the difference then? Maybe 0.99999...., with an infinite number of nines or something? :confused:

.99999.. Is still just 1 unless one wants to claim that 3 times 1/3 does not equal 1. In this last example we can assert the interval (5,6] as between the two you referenced succeeding one and proceeding the other. This is the primary reason immediate successors or predecessors are not defined using differences even in discrete math.

Seems the more specific I try to get with this the more my eyes cross :boggled:

That is completely understandable, but at least you note your eyes crossing. While Doron ascribes his poor vision as an aspect of the math itself.
 
It is not that odd or different from what you have just said in discrete math (like with integers). However, in a continuous frame work it can get confusing unless you are very specific and consistent in the definitions and relationships.

Yea, I've heard that there have been mathematicians who literally went nuts over stuff like this. Some people take their numbers too seriously :D



.99999.. Is still just 1 unless one wants to claim that 3 times 1/3 does not equal 1. In this last example we can assert the interval (5,6] as between the two you referenced succeeding one and proceeding the other. This is the primary reason immediate successors or predecessors are not defined using differences even in discrete math.

Uhm...ionno.

Wouldn't (0.999...) only be considered the same as (1) if you rounded it? I mean, sure, they are virtually allllllmost the same but I think its just that our notation system doesn't have a means of writing out the answer to stuff like ((1) - (0.999...)). This continuum stuff is really freaky *_*
 
Yea, I've heard that there have been mathematicians who literally went nuts over stuff like this. Some people take their numbers too seriously :D





Uhm...ionno.

Wouldn't (0.999...) only be considered the same as (1) if you rounded it? I mean, sure, they are virtually allllllmost the same but I think its just that our notation system doesn't have a means of writing out the answer to stuff like ((1) - (0.999...)). This continuum stuff is really freaky *_*

1/3 is 0.33333..., three times 1/3 is 0.9999..., it is in fact exactly 1 without rounding unless you have to round 3/3 to get to 1. The only difference is that 0.9999... is an infinite decimal notation of one, while 1.00 is a finite decimal notation.
 
1/3 is 0.33333..., three times 1/3 is 0.9999..., it is in fact exactly 1 without rounding unless you have to round 3/3 to get to 1. The only difference is that 0.9999... is an infinite decimal notation of one, while 1.00 is a finite decimal notation.

Okey, good. I got some other questions :)

Once, I asked my HS geometry teacher "If there are two rods that are infinitely long but one is 2 ft wide and the other only 1ft wide, is one bigger than the other?" He just kinda shook his head and said that was a question for philosophers >_<

Got a more satisfactory answer for me?

And my other questions are: How many points are there in a line segment 3 units long? And does a line segment with more than 3 units have more points?
 
the only other requirement for an immediate predecessor is that no other real numbers

No, "<" has a meaning only between real numbers, in this case.

Since this is the simple fact in this case, and since "[0,0]" and "0" are two notations of the same element, which is a real number, then 0 is not an immediate predecessor of any other real number, and it does not matter if this real number is gathered by a name called "interval", because "<" relation has a meaning only if it used between real numbers, in this case.

Any other thing that is not this simple straightforward fact, is simply an illusionary game with notations and extra names like "intervals", which leads to complicated and trivial game with names and notations, without any notion at the basis of it.

Too many minds were twisted down along the past 300 years by this complicated and trivial game with names and notations that are nothing but sterile and mechanical manipulations with symbols.
 
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No, "<" has a meaning only between real numbers, in this case.


Such linear thinking. Doron, why do you restrict things so arbitarily? Can't the symbol "<" be used as an ordering relation? Can't we adopt -- with full disclosure, of course -- a concise definition for that ordering relation different from the simple less-than relation? Doron, we are aghast that you, of all people, would be so stuck in you in-the-box thinking.

We are disappointed.
 
Such linear thinking. Doron, why do you restrict things so arbitarily? Can't the symbol "<" be used as an ordering relation? Can't we adopt -- with full disclosure, of course -- a concise definition for that ordering relation different from the simple less-than relation? Doron, we are aghast that you, of all people, would be so stuck in you in-the-box thinking.

We are disappointed.

You can do it in this case only if you ignore the numbers that are included in or exist between the intervals, but then you have exactly nothing to order.

So you can't adopt -- even with full disclosure -- a concise definition for that ordering relation different from the simple less-than relation, in this case.

Your inability to get this fact is closely related to your inability to get the ford-circle part of http://www.internationalskeptics.com/forums/showpost.php?p=4840972&postcount=3923 post.

Who is exactly this We, are you more than a one person?

In general jsfisher, your school of thought adopts notions instead of first understand them.
 
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Who is exactly this We, are you more than a one person?
If you're upset about jsfisher's use of the plural: I agree wholeheartedly with his post. That makes it plural. I guess there are a lot more posters in this thread who agree with it.
 
If you're upset about jsfisher's use of the plural: I agree wholeheartedly with his post. That makes it plural. I guess there are a lot more posters in this thread who agree with it.
Yes, I know you are many machines that make the same sound, and you are very proud of it.
 
Yes he signed up, and he waits for account verification (it takes 24 to 48 hours).

That would mean he's using one of the following user names: garybooker, Maklu G, McL, Richard S, or tuoni. Come on, Doron. You can tell us. Which did he use?
 
Yes he signed up, and he waits for account verification (it takes 24 to 48 hours).

Good. I'll save my question so that I can get his response as well.

Also I'd like to see how he would present Organic Numbers to Anthony Fremont or any other grade schooler.
 
One of the newest members of the Forums is MosheKlein. Welcome, MosheKlein.
 
Now I am in ..

Thank you jsfisher !

I think that the main new idea for us here is to begin with is to observe a number n as a superposition of its partitions Pr(n). Recently I have develop an algorithm to calculate the number of distinctions of a number Or(n) . The sequences started with 1,2,3,9,24,76,236,785, …( we calculate it until or(12))

I made some correction following your remarks – thank you !

Do you have some more remarks?

Moshe Klein

Sorry for my English..:(
 
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Don't you mean the results of your function are 1,2,3,9,24,76,236,785?

Most of the mathematical function equations are above me, but why doesn't the number 5 produce six results? According to doronshamdi, I can "write" the number five like so:
1+1+1+1+1 or 2+1+1+1 or 2+2+1 or 3+1+1 or 3+2 or 4+1

This is based on the "way" he provides the permiutations of 4: 1+1+1+1, 2+2, 1+3, 2+1+1.
 
Welcome Mr. Klein!

Pehaps tomorrow I'll be asking you a simple question about "sets" in OM just to gauge if I'm on the right track with a point Doron has made a number of times and to see what your way of explianing things is like.

I'm also very interested in how you'd go about presenting Organic Numbers to an elementary school kid.
I've very much need that kind of simple approach, as I am not a mathematician but a word slinger.
 
Don't you mean the results of your function are 1,2,3,9,24,76,236,785?

Most of the mathematical function equations are above me, but why doesn't the number 5 produce six results? According to doronshamdi, I can "write" the number five like so:
1+1+1+1+1 or 2+1+1+1 or 2+2+1 or 3+1+1 or 3+2 or 4+1

This is based on the "way" he provides the permiutations of 4: 1+1+1+1, 2+2, 1+3, 2+1+1.


Yes , here is all what we calculate until today

1, 2, 3, 9, 24, 76, 236, 785, 2634, 9106, 31870, 113371 ,...


as you understand we don't use for calculation the partition n=n

but 2=1+1 bring two distinctions

2=(1)+(1) we don't know the identity of the two elements.
2= (1)+1 we know the identity of the two elements.

so it is more complicate then the known partition function.
and much dipper then the primes..:boxedin:
 
Hi Apathia,

A very basic different in OM concerning set theory is that we permit an element to appear several of times.

Ex: A= { 1,2,2,3,4,4,5}

Since I am a new member here, I can't sent you yet the link to a sort You Tube movie
of myself working with preschool childrens with Organic Mathematics ideas.

Maybe Doron will do that.

Best
Moshe

p.s : I like your moving fingers :o
 
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First of all, welcome, MosheKlein!

Yes , here is all what we calculate until today

1, 2, 3, 9, 24, 76, 236, 785, 2634, 9106, 31870, 113371 ,...
And it goes on like this?

Or(1) = 1
Or(2) = 2
Or(3) = 3
Or(4) = 9
Or(5) = 24
Or(6) = 76
Or(7) = 236
Or(8) = 785
Or(9) = 2634
Or(10) = 9106
Or(11) = 31870
Or(12) = 113371
Or(13) = 407438
Or(14) = 1479526
Or(15) = 5415700
Or(16) = 19970119
Or(17) = 74096864
Or(18) = 276466199
Or(19) = 1036598162
Or(20) = 3903844089

when I read your formulae right?

In post #3906 in this thread, Doron posted an explanation of yours how the formulae work.

as you understand we don't use for calculation the partition n=n
That's clear. But why do you ignore it?

And shouldn't, then, in point (5), the definition of D, the product go up to n-1 instead of n?

but 2=1+1 bring two distinctions

2=(1)+(1) we don't know the identity of the two elements.
2= (1)+1 we know the identity of the two elements.
So what does this "distinction" mean? The partition part is clear, function g is clear, but then you define D and Or, mutually recursive, and I have no idea what is going on here. I can calculate it all right, but what is the meaning behind these formulae? What does it signify. The above two lines don't really help me.
 
Since I am a new member here, I can't sent you yet the link to a sort You Tube movie
of myself working with preschool childrens with Organic Mathematics ideas.

Just put some spaces in the URL and then you fool the newbie filter, like this:

www . youtube . com / ...
 
Hi ddt,

1) Very nice calculation ! How did you made it so fast. Did you use a computer?
I let you know that there is a sequences named A056198 ( you can find it in the internet) which being exactly like Or. So I check with Or(20) as in your calculation and it's fit but I am not sure that it will be so forever.

[an open problem in OM..]

2) The case n=n will lead to problem and infinite recursion

3) Since we add with GAMA- ( all partition without n=n) it's good also

4) The distinction answer to the question how the number appear in the mind of the observer so its a kind of Quantum theory inspiration in the base of OM.

If you understand/ agree with n=2 it can be really great.

2=(1)+(1)
2=(1)+1


5) Thank you for the idea. So I can add the link to the you tube Movie ( I will do that later )


Best regards
Moshe :)
 
Welcome to the forum, MosheKlein.

Thank you catbasket !

I will do my best here to share my understanding of OM
I have B.A in Mathematics ( 1980), MA in education of Mathematics ( 1998) and quite long experience in Kindergarten education ( 1988 - today )

Moshe:blush:
 
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ddt asked
So what does this "distinction" mean? The partition part is clear, function g is clear, but then you define D and Or, mutually recursive, and I have no idea what is going on here. I can calculate it all right, but what is the meaning behind these formulae? What does it signify. The above two lines don't really help me.


MosheKlein answered:
4) The distinction answer to the question how the number appear in the mind of the observer so its a kind of Quantum theory inspiration in the base of OM.

If you understand/ agree with n=2 it can be really great.

2=(1)+(1)
2=(1)+1

This upstages the question I was going to ask, because it is by far the most important one.
So, we are going to keep asking you it till there is a clear answer.
I'm afraid your answer above simply says it's all an answer to another question.
Now we not only don't have an answer to ddt's question, but there's an added question we don't know.

What concept or meaning does an organic number express that a traditional number doesn't?
Perhaps the formula you've created has some structural similarities to aspects of quantum behavior. But the big question is what the asperagus is an organic number?
What is "Distinction?"
 
Thank you jsfisher !

I think that the main new idea for us here is to begin with is to observe a number n as a superposition of its partitions Pr(n). Recently I have develop an algorithm to calculate the number of distinctions of a number Or(n) . The sequences started with 1,2,3,9,24,76,236,785, …( we calculate it until or(12))

I made some correction following your remarks – thank you !

Do you have some more remarks?

Moshe Klein

Sorry for my English..:(

Hello my dear friend,

:welcome4 to the forum.
 
Okey, good. I got some other questions :)

Once, I asked my HS geometry teacher "If there are two rods that are infinitely long but one is 2 ft wide and the other only 1ft wide, is one bigger than the other?" He just kinda shook his head and said that was a question for philosophers >_<

Got a more satisfactory answer for me?

Satisfaction is not guaranteed, but I'll give it a shot.

Clearly one rod is bigger in width (or diameter for a rod) thus cross sectional area, yet both would encompass an infinite volume. Were we to create sets containing the locations of a specific finite volume element for each rod. Both sets would be infinite, but there would not be a one to one correspondence (bijection) between the sets and thus they would have a different cardinality (the relative size of sets). Alternatively if we make the finite volume elements proportional to the rods there would be a one to one bijection between the sets of the locations of those volume elements. However since the elements are scaled from one rod to the other again the difference in size or volume of the elements is clear. Finally we can use specific finite area elements of infinite length thus infinite volume elements. Of which one rod would have more such elements then the other. So no matter how you slice it one rod is bigger then the other, more clearly seen in width and cross sectional area then length or volume.


And my other questions are: How many points are there in a line segment 3 units long? And does a line segment with more than 3 units have more points?

There are always an infinite number of points in any finite length. Thus a line segment with more then three units does not have more points then one of just three units.


Please see cardinality.

http://en.wikipedia.org/wiki/Cardinality

Cardinal arithmetic can be used to show not only that the number of points in a real number line is equal to the number of points in any segment of that line, but that this is equal to the number of points on a plane and, indeed, in any finite-dimensional space. These results are highly counterintuitive, because they imply that there exist proper subsets and proper supersets of an infinite set S that have the same size as S, although S contains elements that do not belong to its subsets, and the supersets of S contain elements that are not included in it.


The difference between the infinite rods and the finite line segments examples is that one is infinite and refers to size while the other finite and refers to the number of points. You will note the use of finite dimensional volumes or finite dimensional areas in comparing the relative ‘sizes’ of the rods. While the segments are already of finite dimension thus directly comparable and in one to one correspondence with the real number line.

I hope that is satisfactory.
 
Oh and by the way, welcome to the forum MosheKlien.

I'm sorry to say that I have some errands to run right now, but I look forward to your input on this thread.
 
ddt asked



MosheKlein answered:


This upstages the question I was going to ask, because it is by far the most important one.
So, we are going to keep asking you it till there is a clear answer.
I'm afraid your answer above simply says it's all an answer to another question.
Now we not only don't have an answer to ddt's question, but there's an added question we don't know.

What concept or meaning does an organic number express that a traditional number doesn't?
Perhaps the formula you've created has some structural similarities to aspects of quantum behavior. But the big question is what the asperagus is an organic number?
What is "Distinction?"

Let us take number 2, and let us use only whole numbers and * or + operations in order to calculate it.

Under these restrictions Standard Math cares only about the quantitative result.

So by Standard Math 1*2=1+1=2

This is not the only case under OM framework if the distinction of the elements is not ignored, for example:

We use 1*2 only if the elements are identical: = 1*2 = 2

We use 1+1 only if the elements are not identical: = 1+1 = 2
 
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Let us show my calculations that stand at the basis of Moshe's Or(n) function.

1) Organic Number n is the all possible states of Distinction between n elements, where order has no significance.

2) In n=1 there is only one state of distinction, so Or(n)=1.

3) In n=2 the are two possible states of distinction, for example: and , so Or(n)=2.

4) From n=3 and further Or(n) value is based on the following:

a) First we take the partitions of n which are not of the form n+0, for example:

If n=3 we take 1+1+1, 2+1 and ignore 3+0
If n=4 we take 1+1+1+1, 2+1+1, 2+2, 3+1 and ignore 4+0
Ect. …

b) Now we are using the recursion function D on each partition of some n (the case n+0 is ignored), for example let us take n=3:

The calculated partitions of n=3 are D(1+1+1) and D(2+1) (D(3+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1)=2

So, Or(3)=D(1+1+1)+D(2+1)=3

The calculated partitions of n=4 are D(1+1+1+1), D(2+1+1), D(2+2) and D(3+1) (D(4+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1+1)=2
The case of any partition of the form (2,2,2,…) is calculated by D as the result of the amount of the repetitions of number 2 in the partition+1, for example:
D(2+2)=3, D(2+2+2)=4, D(2+2+2+2)=5 , etc. …
So in the case of n=4 the result of the recursion D on partition (2+2) is D(2+2)=3
Since 3 has only three cases of distinction, then D(3+1)=3

So, Or(3)=D(1+1+1)+D(2+1+1)+ D(2+2)+ D(3+1)=9

5) The further calculations of D that are not based on (2+2+…) partitions, are as follows:

a) If the elements of a given partition are distinct - for example partition (3+2) of n=5 – then the value of D(3+2) = Or(3)*Or(2)=6. In general D(n1,n2,n3,…)= Or(n1)*Or(n2)*Or(n3)* …

b) If the elements of a given partition are non-distinct - for example partition (3+3) of n=6 – then the value of D(3+3) = (Or(3)+(Or(3)-1)+Or(3)-2)+(Or(2)+Or(2)-1)+(Or(1)) = (3+2+1)+(2+1)+(1)=10. D(3+3+3) = ((3+2+1)+(2+1)+(1)) + ((2+1)+(1)) + ((1)) = 15 (partition (3+3+3) belongs to n=6)

6) The partition is a mixing of distinct and non-distinct elements (for example partition (3,3,2) of n=8) the we first calculate 3 according (b) and then multiply the result of (b) with the result of Or(2).

In the case of partition (3,3,2,2) of n=10, we first calculate 3 and 2 cases according to (b) and then we mutably the results.

I hope that I did not make mistakes here, but it there are mistakes, I'll fix them later.
 
Let us take number 2, and let us use only whole numbers and * or + operations in order to calculate it.

Under these restrictions Standard Math cares only about the quantitative result.

So by Standard Math 1*2=1+1=2

This is not the only case under OM framework if the distinction of the elements is not ignored, for example:

We use 1*2 only if the elements are identical: = 1*2 = 2

We use 1+1 only if the elements are not identical: = 1+1 = 2

OK, I'm trying to get this.
OM shows the aspect of a number as a distinct entity independent of quantification.

Can the concept of number be independent of quantity?

Are "+" and "*" arithmetic opperations? (If so, we have quantities.)

But I think get your drift in this example:

We have a series of two pictures of a banana.
if we regard this as the self same banana repeated, copied, or cloned, we must exclusively use the times opperator.
If we take regard the bananas as different objects (albeit both of the same class of object), we must exclusively use the addition opperator.

Ordinary math throws both these regards into the same intellectual pot,
But in OM, depending on how an element is being regarded,
1*2 may not necessarily equal 1+1, because we may or may not have the mere instance of the self same unique object.
 
Let us show my calculations that stand at the basis of Moshe's Or(n) function.

1) Organic Number n is the all possible states of Distinction between n elements, where order has no significance.

2) In n=1 there is only one state of distinction, so Or(n)=1.

3) In n=2 the are two possible states of distinction, for example: and , so Or(n)=2.

4) From n=3 and further Or(n) value is based on the following:

a) First we take the partitions of n which are not of the form n+0, for example:

If n=3 we take 1+1+1, 2+1 and ignore 3+0
If n=4 we take 1+1+1+1, 2+1+1, 2+2, 3+1 and ignore 4+0
Ect. …

b) Now we are using the recursion function D on each partition of some n (the case n+0 is ignored), for example let us take n=3:

The calculated partitions of n=3 are D(1+1+1) and D(2+1) (D(3+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1)=2

So, Or(3)=D(1+1+1)+D(2+1)=3

The calculated partitions of n=4 are D(1+1+1+1), D(2+1+1), D(2+2) and D(3+1) (D(4+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1+1)=2
The case of any partition of the form (2,2,2,…) is calculated by D as the result of the amount of the repetitions of number 2 in the partition+1, for example:
D(2+2)=3, D(2+2+2)=4, D(2+2+2+2)=5 , etc. …
So in the case of n=4 the result of the recursion D on partition (2+2) is D(2+2)=3
Since 3 has only three cases of distinction, then D(3+1)=3

So, Or(3)=D(1+1+1)+D(2+1+1)+ D(2+2)+ D(3+1)=9

5) The further calculations of D that are not based on (2+2+…) partitions, are as follows:

a) If the elements of a given partition are distinct - for example partition (3+2) of n=5 – then the value of D(3+2) = Or(3)*Or(2)=6. In general D(n1,n2,n3,…)= Or(n1)*Or(n2)*Or(n3)* …

b) If the elements of a given partition are non-distinct - for example partition (3+3) of n=6 – then the value of D(3+3) = (Or(3)+(Or(3)-1)+Or(3)-2)+(Or(2)+Or(2)-1)+(Or(1)) = (3+2+1)+(2+1)+(1)=10. D(3+3+3) = ((3+2+1)+(2+1)+(1)) + ((2+1)+(1)) + ((1)) = 15 (partition (3+3+3) belongs to n=6)

6) The partition is a mixing of distinct and non-distinct elements (for example partition (3,3,2) of n=8) the we first calculate 3 according (b) and then multiply the result of (b) with the result of Or(2).

In the case of partition (3,3,2,2) of n=10, we first calculate 3 and 2 cases according to (b) and then we mutably the results.

I hope that I did not make mistakes here, but it there are mistakes, I'll fix them later.

The math people may find some details to correct, but I get the purpose.
I also think I get your Redundancy/Uncertainty thing now.

While I'm waiting for Mosheklein to give his answers, I'll offer a little theatre to focus in on the kindergarten scene.

Somewhere in County Cork:

Sister Mallory shows Little Paddy a page in his coloring book.
Typically it shows a series of three drawings of a potato that all look the same.

Sister Mallory: How many potatoes are there, Paddy?
Paddy: One.
Sister Mallory: Wrong! (She whacks his fingers with her ruler.)
Paddy: But it's the same potato!
Sister Mallory: (she whacks him again.)

Somewhere in County Cork after Sister Mallory is packed off to foreign monastery:

Sister Goodwin: Paddy, How many potatoes are there?
Paddy: One
Sister Goodwin: Right. Same Potato, huh? How many pictures of the potato are there?
Paddy: Three.
Sister Goodwin: Excellent!

Now what will happen when Moshe Kline comes to County Cork?
And green bagels, anyone?
 
Some corrections of http://www.internationalskeptics.com/forums/showpost.php?p=4849130&postcount=4035 typo mistakes:

Let us show my calculations that stand at the basis of Moshe's Or(n) function.

1) Organic Number n is the all possible states of Distinction between n elements, where order has no significance.

2) In n=1 there is only one state of distinction, so Or(n)=1.

3) In n=2 there are two possible states of distinction, for example: and , so Or(n)=2.

4) From n=3 and further Or(n) value is based on the following:

a) First we take the partitions of n which are not of the form n+0, for example:

If n=3 we take 1+1+1, 2+1 and ignore 3+0
If n=4 we take 1+1+1+1, 2+1+1, 2+2, 3+1 and ignore 4+0
etc. …

b) Now we are using the recursion function D on each partition of some n (the case n+0 is ignored), for example let us take n=3:

The calculated partitions of n=3 are D(1+1+1) and D(2+1) (D(3+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1)=2

So, Or(3)=D(1+1+1)+D(2+1)=3

The calculated partitions of n=4 are D(1+1+1+1), D(2+1+1), D(2+2) and D(3+1) (D(4+0) is not calculated, because if we calculate D(n+0) we enter into a non-finite loop of recursion).

Since 1 has only one case of distinction, then D(1+1+1)=1
Since 2 has only two cases of distinction, then D(2+1+1)=2
The case of any partition of the form (2,2,2,…) is calculated by D as the result of the amount of the repetitions of number 2 in the partition+1, for example:

D(2+2)=3, D(2+2+2)=4, D(2+2+2+2)=5 , etc. …
So in the case of n=4 the result of the recursion D on partition (2+2) is D(2+2)=3
Since 3 has only three cases of distinction, then D(3+1)=3

So, Or(4)=D(1+1+1)+D(2+1+1)+ D(2+2)+ D(3+1)=9

5) The further calculations of D that are not based on (2+2+…) partitions, are as follows:

a) If the elements of a given partition are distinct - for example partition (3+2) of n=5 – then the value of D(3+2) = Or(3)*Or(2)=6.
In general, D(n1,n2,n3,…)= Or(n1)*Or(n2)*Or(n3)* …

b) If the elements of a given partition are non-distinct - for example partition (3+3) of n=6 – then the value of
D(3+3) = (Or(3)+(Or(3)-1)+Or(3)-2)+(Or(2)+Or(2)-1)+(Or(1)) = (3+2+1)+(2+1)+(1)=10.
D(3+3+3) = ((3+2+1)+(2+1)+(1)) + ((2+1)+(1)) + ((1)) = 15 ( (3+3+3) is a partition of n=9 ).

6) If the partition is a mixing of distinct and non-distinct elements (for example partition (3,3,2) of n=8) then we first calculate 3 according (b) and then multiply the result of (b) with the result of Or(2).

In the case of partition (3,3,2,2) of n=10, we first calculate 3 and 2 cases according to (b) and then we *multiply\add the results.

*(I still have to check if in a case like (3,3,2,2) we multiply the results of 3,3 with the results of 2,2, or we add the results of 3,3 with the results of 2,2).

EDIT: I'v chacked it, it is multiply, so D(3,3,2,2)=30
 
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The partical example starts at the moment that you get that Number is the result of Memory\Object interaction, exactly as explained in http://www.geocities.com/complementarytheory/OMPT.pdf pages 18-20.
Well I get the idea, as Apathia explained it, and, as I already said, it seems to fit with what's in the document, but I would like to see a worked example of a real-world situation to which this language has been applied to analyse and/or resolve a mathematical/scientific problem with its moral and ethical implications.

Again: I would like to see a worked example of a real-world situation to which this language has been applied to bridge science and ethics.

It's surely not much to ask, as this is exactly the task the language is designed for?
 
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