Originally Posted by Tony Szamboti
Uh, no, YOU are wrong. Have you ever drawn free body diagrams? This is not that complex an item.
Down is mg, call the force up N. Call up positive and down negative.
If there is no deceleration, then sum of forces = 0. So -mg+N=0, and N = mg.
If there is a deceleration it must be UPWARDS deceleration (because downwards g makes things go faster not slow down). So -mg+N=ma, and
N = ma + mg.
Therefore, if a = g, then N = 2(mg)
which is twice static load.
Don't tell me I'm wrong, Tony. I teach this stuff.
If you ignore this, I will take it as recognition that you were previously incorrect.