You still do not get it do you?
So let us improve the proof without words, by using Koch's fractal.
1) Take a straight 1-dim with length X.
2) Bend it and get 4 equal sides along it.
3) Since the length between the opposite edges is changed to the sum of only 3 sides, and since the number of the sides after the first bending is 4 sides, we have to multiply the bended 1-dim element by 1/(the number of the bended sides), in order to get back length X.
As a result the bended 1-dim element has length X, but the length between its opposite edges becomes smaller (it converges).
In general, this convergent series of 1/(the number of the bended sides) is resulted by 1/1+1/4+1/16+1/64+1/256+... , where X is subtracted by (2a+2b+2c+2d+…)
Here is the result:
[qimg]http://farm5.static.flickr.com/4015/4430320710_daf5b36c0f_o.jpg[/qimg]
4) By Standard Math X – (2a+2b+2c+2d+…) = 0
5) (4) is false because (2a+2b+2c+2d+…) can be found as long as X is found.
6) Since X is found upon infinitely many scale levels then (2a+2b+2c+2d+…) must be < X , and as a result X - (2a+2b+2c+2d+…) > 0.
7) Conclusion: (2a+2b+2c+2d+…) does not have sum X.