Sorry, I'm not going to aim at a moving target.
Sorry, I'm not going to aim at a moving target.
So why you are using the nonsense of "dragging a point" in order to define a line?doronshadmi said:He does seem to have a propensity for introducing more errors when trying to make a correction.Nonsense. You don't use the point as a co-ordinate, the co-ordinates tell you where the point is.This reasoning has infinitely many errors.By dragging the point, you are defining, for example, a line, which is 1-dimensional.
The right reasoning is this:
A point is an existing dimensional space that has 0 degrees of freedom (no coordinates are related to points).
A line is an existing dimensional space that has 1 degrees of freedom (singletons of ordinates are related to points).
A plan is an existing dimensional space that has 2 degrees of freedom (pairs of coordinates are related to points).
A sphere is an existing dimensional space that has 3 degrees of freedom (triples of coordinates are related to points).
Etc... ad infinituum.
Domain is "that is researched".
What is researched?
Define researched.
A measurable realm.
What is "a measurable realm"?
A realm where the measured and the measurer are interacted.
You went back and edited several posts and you had problems understanding the word "I" so I ask the same questions without using the word I.So after several times of you having to clarify what your previous answer is, we're at the point where your definition of a domain is "A realm where the measured and the measurer are interacted". Clear as mud.
Define "interacted".
If I use a tool to measure the measured, what/who is the measurer? For example, I have a book with a unknown weight. When I place the book (the measured object) the scale will give me a measurement. Who is the measurer?
Since you want to play little games.
Your mom has an apple. She wants to know the weight of the apple. She places the apple on the scale. When she places the apple (the measured object) on the scale, it will give her a measurement. Who is the measurer?
Let's do it clearer
You still miss it.
If a set that containing a point has cardinality 1 it means that the contained is not nothing even if the considered universe is Dimension.
Who ever said a point or a set containing a point it was “nothing”?
The set that containing no apples has cardinality 0 if the considered universe is Apples.
In other words, “0 apples” is equivalent to “0 points”, but “0 points” is not equivalent to “0 dimension”, so your “0 apples” argument does not hold water.
So please tell us how many dimensions you have when your have “0 points”?
That is why a point is an existing thing that has 0 dimension.
Since 0 dimensional element and 1 dimensional element are both existing things under the universe of Dimensions, then 1 dimensional element is included NXOR excluded w.r.t 0 dimensional element under that universe, and 0 dimensional element is included XOR excluded w.r.t 1 dimensional element under that universe.
Furthermore, there is a difference between “element”, which is a non-composed thing, and “object” that can be a composed thing (in both cases we are talking about existing things, where contained existing things of some set is resulted by cardinality > 0 of the considered set).
A line segment is a composed result of 0 and 1 non-composed dimensional spaces.
Your “direct perception” has failed you yet again.You simply can’t grasp the notion of existing and non-composed things, because you do not understand differences that are based on magnitudes.
The one who enables to get differences that are based on magnitudes (where Magnitude is defined according to “How much?” question, which is essentially different than “How many?” question) , immediately grasps the difference of the existing 0 dimensional element and 1 dimensional element w.r.t each other.
No, I am claiming that a point is an existing element and the cardinality of a set that includes it as a member, clearly demonstrates it.
Start by fixing your reasoning's abilities (for example: the difference between “How much?” and “How many?” questions).
Start by gaining some reasoning abilities yourself and stop just fixating on your OM fantasies.
Some exercises:
So please tell us how many dimensions you have when your have “0 points”?
Again if you think just a point has dimension then give us a set of the ordinate or coordinates to locate that point in itself and give us the cardinality of that set (and thus the dimensionality of your "point" with dimension)
How much size a point has?
Does an element that has 0 size exists?
What is the cardinality of a set that have at least a point as its member?
Nope.
There is a difference between “How many?” (apples) and “How much?” (size).
A point is an existing element with 0 size, and if it is the only thing that included in some set, then the cardinality of that set is at least 1.
This is not the case with no apples because no apples is not an existing thing, so if no apples are the only thing that is included in a given set, then the cardinality of that set is 0.
Yes, a point is an existing element exactly a line is an existing element, and both of them are exiting things under the concept of Dimension.
By understanding this fact a point is included XOR excluded w.r.t a line and a line is included NXOR excluded w.r.t a point.
You seem to be ignoring the obvious fact that a point is not the building-block of a line and as a result a point and a line are different and existing magnitudes that have different properties if compared w.r.t each other, and they are comparable under the concept of Dimension.
Nothing was shifted. A point is an existing element under the concept of Dimension, and if some set includes elements of that concept,
then |{.}| = 1 where cardinality 1 indicates the existence of a point as an element of the concept of Dimension.
A point is an existing element under the universe of Dimensions exactly as some apple is an existing element under the universe of apples.
If the universe of apples has no apples, then we deal with the empty set.
If the universe of dimensions has no elements (where a point is one of the elements of this universe) then we deal with the empty set.
EDIT:
There is no element that lacks the property of apple under the universe of apples.
There is no element that lacks the property of dimension under the universe of dimensions.
Since a point is an element under the universe of dimensions that has exactly "0 dimension", then "0 dimension" is not the same as "no dimension", because an element that has "no dimension" is not under the universe of dimensions.
Do you have any evidence to support your claim? (The notorious Q. LOL.)Doron, “How much” is just a question of “How many” of some unit representation.
It doesn't go like that. The number of dependent variables defines the dimensionality of drawn objects:This reasoning has infinitely many errors.
The right reasoning is this:
A point is an existing dimensional space that has 0 degrees of freedom (no coordinates are related to points).
A line is an existing dimensional space that has 1 degrees of freedom (singletons of ordinates are related to points).
A plan is an existing dimensional space that has 2 degrees of freedom (pairs of coordinates are related to points).
A sphere is an existing dimensional space that has 3 degrees of freedom (triples of coordinates are related to points).
Etc... ad infinituum.
EDIT:The Man said:See there you go again you specifically claim if your “universe of apples has no apples, then we deal with the empty set” yet for your “universe of dimensions” you do not specifically state if it “has no” dimension“, then we deal with the empty set”. Once again you are simply trying to infer no point from no dimension when a point is specifically defined as having no dimensions.
A pair of coordinates is related to 0 dimensional space under 2 dimensional space, so?f(x,y) = 0 draws a 2D object:
A single ordinate is related to 0 dimensional space under 1 dimensional space (where the term "horizontal" is insignificant), so?f(x) = 0 draws a 1D object -- a horizontal line
A pair of coordinates is related to 0 dimensional space under 2 dimensional space, so?
A single ordinate is related to 0 dimensional space under 1 dimensional space (where the term "horizontal" is insignificant), so?
The Man said:Yet “no apples” is under your “universe of apples” as the empty set. Once again you are simply ignoring “no dimension" as the empty set in your “universe of dimensions”.
a point is just an imaginary reference point
You can't use the word "point" as a part of its definition ("a point is just an imaginary reference point"), because you get a circular reasoning, which is invalid.
You'll be the expert on what constitutes a definition, then?
Yes, you are correct, a different word should be used; I was quoting epix, and missed the reuse of the word. Does that stop you from understanding what a point is, though, or a co-ordinate?
Domain is "that is researched".
What is researched?
Define researched.
A measurable realm.
What is "a measurable realm"?
A realm where the measured and the measurer are interacted.
So after several times of you having to clarify what your previous answer is, we're at the point where your definition of a domain is "A realm where the measured and the measurer are interacted". Clear as mud.
Define "interacted".
If I use a tool to measure the measured, what/who is the measurer? For example, I have a book with a unknown weight. When I place the book (the measured object) the scale will give me a measurement. Who is the measurer?
Since you want to play little games.
Your mom has an apple. She wants to know the weight of the apple. She places the apple on the scale. When she places the apple (the measured object) on the scale, it will give her a measurement. Who is the measurer?
A point is an existing dimensional space that has 0 degrees of freedom (no coordinates are related to points).
Who is I that asks the same questions without using the word I?so I ask the same questions without using the word I.
Some details that support your "No", please.
Some details that support your "No", please.
Maybe you tell us.What would be the point?
ANDSorry, I'm not going to aim at a moving target.
is a contradiction.By dragging the point, you are defining, for example, a line, which is 1-dimensional.
Since you want to play little games.
Your mom has an apple. She wants to know the weight of the apple. She places the apple on the scale. When she places the apple (the measured object) on the scale, it will give her a measurement. Who is the measurer?
Not answering your ever changing posts (That is what zooterkin is referring to in the second quoted message) and dragging a point (the third quoted message) is not a contradiction.Maybe you tell us.
Also be aware of the fact that
AND
is a contradiction.
EDIT:
Let us get it this way:
An element of a given universe has the most basic property of that universe.
The property can be "Apple", "Dimension", … etc …
------------------------
By following your argument:
If "no apples" is not the lack of the most basic property of the universe of apples (because, afrer all, the term "apples" is used), then this universe has an empty set as one of its members, known as "no apples".
If "no dimension" is not the lack the most basic property of the universe of dimensions (because, afrer all, the term "dimension" is used), then this universe has an empty set as one of its members, known as "no dimension".
--------------------------
In that case there is an exclusive empty set for each given universe, which is a false claim, because empty set is not an exclusive element of any given universe.
--------------------------
Let us follow your argument about a point:
An element that has "no dimension" is equivalent to empty set under the universe of dimensions, and a point is such an element.
--------------------------
But this is a false claim because empty set is not an exclusive element of any given universe, and since "no dimension" is an exclusive element then a point is not equivalent to empty set.
A point (which is not equivalent to empty set) and a line are elements of the universe of dimensions, where a point is a dimensional element that has 0 degrees of freedom and a line is a dimensional element that has more than 0 degrees of freedom.
Again if you think just a point has dimension then give us a set of the ordinate or coordinates to locate that point in itself and give us the cardinality of that set (and thus the dimensionality of your "point" with dimension)
By getting this simple fact, a point is located XOR not-located w.r.t to a given line, where a line is located NXOR not-located w.r.t a given point.
The Man, in addition to post http://www.internationalskeptics.com/forums/showpost.php?p=6270709&postcount=11327 :
{} is not equivalent to {no apples}
{} is not equivalent to {no dimension} is equivalent to {.}
It doesn't go like that. The number of dependent variables defines the dimensionality of drawn objects:
f(x,y) = 0 draws a 2D object:
[qimg]http://a.imageshack.us/img693/2578/2dplane.jpg[/qimg]
f(x) = 0 draws a 1D object -- a horizontal line
Now, which function would draw the 0-D object, which the point?
It's a function with no dependent variable. But such a function doesn't exist and therefore a point cannot be drawn at a specified location, coz there is no function to do so. But a point can be located by a set of two functions. A point of intersection, for example, is a a solution of f(x) - g(x) = 0. Points are just imaginary reference points.
You need to be careful though when you go the other way. Remember that
y = f(x)
z = f(x,y)
and so on.
When you start to manipulate the independent variables the dimensional objects will respond according to the dependent variable y, z, and so on. The changes can be detected with the help of co-ordinates y, z, and so on. Here is an example:
[qimg]http://a.imageshack.us/img834/5913/ekklund1.jpg[/qimg]
Looks familiar?
If you rewrite the equation in the graph to satisfy certain conditions that exist in the Gamma-Rho phase space, then . . .
[qimg]http://a.imageshack.us/img227/7767/ekklund2.jpg[/qimg]
Yep. It's the four-legged mischievous demon Ekklund.
The higher dimensions are virtually infested with deities of peculiar varieties, so be careful -- unless you are an atheist with limited, local-only reasoning that is closed to the isomorphic algebra of multi-dimensional manifolds.
I don't think so. That universe, as any other universe, develops a very dense objects that generate such a strong gravitational pull that even the photon cannot overcome, so the very dense object is invisible. But there is no black juice, is there?EDIT:
Let us get it this way:
An element of a given universe has the most basic property of that universe.
The property can be "Apple", "Dimension", … etc …
A pair of coordinates is related to 0 dimensional space under 2 dimensional space, so?
A single ordinate is related to 0 dimensional space under 1 dimensional space (where the term "horizontal" is insignificant), so?
You’re still just jerking yourself around claiming apples aren’t the same as oranges.
Who? The mischievous demon Ekklund?Say, that guy does look familiar. Wasn’t he in that movie “Pirates of the Caribbean Plain: The Curse of the Buckled Surface“?
No Doron the set of an ordinate or coordinates locating a point, when the space is that point, is the empty set.
Here it is:Doron “{no dimension}” or “{.}” are still not a set of the ordinate or coordinates needed to locate a point in that point.
Let me stop you there. You appear to be still confused about what co-ordinates are. They tell you where the point is, not its size or extent. The number of (co-)ordinates needed to specify where a point (or anything else) is depends on the number of dimensions of the space it is located in, not the number of dimensions the point has.No The Man, you ignore the fact that a point is an existing element of the set of dimensional spaces, where the amount of its coordinates is 0.
Let me stop you there. You appear to be still confused about what co-ordinates are. They tell you where the point is, not its size or extent. The number of (co-)ordinates needed to specify where a point (or anything else) is depends on the number of dimensions of the space it is located in, not the number of dimensons the point has.
Co-ordinates are called "degrees of freedom" in phase space, which is a geometry concept that enables engineers to better understand the mechanics of object assembly -- among other things. The purpose of drawing co-ordinates is to locate a point. But in phase space, co-ordinates are basically lines to be followed. In 3-D space, you have 3 degrees of freedom to move along. So what would you do?EDIT:
You appear to be still confused about what co-ordinates are.…
No The Man, you ignore the fact that a point is an existing element of the set of dimensional spaces, where the amount of its coordinates is 0.
This set looks like this:
{0,1,2,3,4,5,..}, where each value is the number of ordinates or coordinates that is related to each existing dimensional space.
Before you jump and replace each number by a set ( for example: {{},{{}},{{},{{}}}, …} ) be aware that according to OM each dimensional space is a non-composed element (or ur-element, if you wish) which is not a set, so the whole idea of Membership as defined among sets, is changed to Membership as defined among ur-elements, where this membership is based on sharing a common property ("Dimension", in this case).
EDIT:
A point and a line are ur-elements that shares the proprty of Dimension.
By understanding the Membership among ur-elements, which is based on shared property, a point is included XOR excluded w.r.t a line and a line is included NXOR excluded w.r.t a point (where no one of them is the component of the other).
A point is an existing dimensional space that has 0 degrees of freedom (0 coordinates are related to points).
A line is an existing dimensional space that has 1 degrees of freedom (singletons of ordinates are related to points).
A plan is an existing dimensional space that has 2 degrees of freedom (pairs of coordinates are related to points).
A sphere is an existing dimensional space that has 3 degrees of freedom (triples of coordinates are related to points).
Etc... ad infinituum.
So please tell us how many dimensions you have when your have “0 points”?
Here it is:
{0, ...} , where 0 ( which is a member of {0,1,2,3,4,5,..} ) is the number of ordinates or coordinates needed to locate a point in 0 dimensional space.
The dimensional spaces can be also represented as { . , __ , ... } but we have a problem to represent dimensional spaces > 3 in this way.
By the way, by understanding a dimensional space and its related coordinates, we are able to get the notion of Mutual Independency, because each value of pair of, triple of (or any greater finite amount of) coordinates can be changed independently of each other, and yet they are all related to given dimensional spaces (which is the property of mutuality), which have 2 or more degrees of freedom (where a point and its related values under a given dimensional space, is the local aspect of this dimensional space).
EDIT:
You appear to be still confused about what co-ordinates are. A dimensional space that has 0 degrees of freedom has an amount of coordinates that are derive from the difference of degrees of freedom that each dimensional space has w.r.t it.
But this is the particular case that is derive from the difference of dimensional spaces with more than 0 degrees of freedom w.r.t a dimensional space that has 0 degrees of freedom.
The arithmetic of this case is very simple:
Abs (0 degrees of freedom – 0 degrees of freedom) = 0 amount of (co-)ordinates.
Abs (1 degrees of freedom – 0 degrees of freedom) = 1 amount of (co-)ordinates.
Abs (2 degrees of freedom – 0 degrees of freedom) = 2 amount of (co-)ordinates.
Abs (3 degrees of freedom – 0 degrees of freedom) = 3 amount of (co-)ordinates.
Etc … at infinitum …
In general, the amount of (co-)ordinates is derive from the absolute difference among the degrees of freedom of dimensional spaces.
Another particular case defines the number of (co-)ordinates of dimensional spaces w.r.t themselves, and as we see the result is 0 amount of (co-)ordinates.
Also the arithmetic of this case is very simple:
Abs (0 degrees of freedom – 0 degrees of freedom) = 0 amount of (co-)ordinates.
Abs (1 degrees of freedom – 1 degrees of freedom) = 0 amount of (co-)ordinates.
Abs (2 degrees of freedom – 2 degrees of freedom) = 0 amount of (co-)ordinates.
Abs (3 degrees of freedom – 3 degrees of freedom) = 0 amount of (co-)ordinates.
Etc … at infinitum …
No, I claim that a point has 0 degrees of freedom, and any measured case that has 0 degrees of freedom does not have any (co-)ordinates that are related to it.The Man said:So now you’re now claiming a point has no dimension(s) since you claim it has no coordinates?
One way is to work in a first-order theory with two sorts, sets and urelements, with a ∈ b only defined when b is a set. In this case, if U is an urelement, it makes no sense to say
X ∈ U
The Man, you are stuck with the notion of sets, and can't get any reasoning which goes beyond it.The Man said:Absolutely ridiculous, this superfluous subtracting nonsense of yours did not work for you before and it is no different now that you have just substituted the words “degrees of freedom” for your “k_X - k_Y” designations.
Your own absolutely ridiculous and superfluous subtracting nonsense still shows no coordinates (in both of your ‘cases’) for just a point and thus no dimension(s). Your really are without a clue when even your own absolutely ridiculous and superfluous subtracting nonsense still proves you wrong.
OM's reasoning.
So by your logic, since a point has no co-ordinates, it cannot be at any location?No, I claim that a point has 0 degrees of freedom, and any measured case that has 0 degrees of freedom does not have any (co-)ordinates that are related to it.
What does the empty set have to with the location of a point?Yet it is not equivalent to the empty set because any given dimensional space is non-composed (also known as ur-element), where the Membership among ur-elements is not based on being sub-elements, but by sharing a common property, where in the case of dimensional spaces, the common property is being a dimension.
By the difference of degrees of freedom among dimensional spaces.The Man said:“related to points”, how, specifically?
Any dimensional space w.r.t itself in not local AND not non-local.So by your logic, since a point has no co-ordinates, it cannot be at any location?
The co-ordinates are the result of the difference of degrees of freedom among dimensional spaces.the co-ordinates tell you ...
The dimensional spaces can be also represented as { . , __ , ... } but we have a problem to represent dimensional spaces > 3 in this way.
No, I claim that a point has 0 degrees of freedom, and any measured case that has 0 degrees of freedom does not have any (co-)ordinates that are related to it.
Yet it is not equivalent to the empty set because any given dimensional space is non-composed (also known as ur-element), where the Membership among ur-elements is not based on being sub-elements, but by sharing a common property, where in the case of dimensional spaces, the common property is being a dimension.
Traditional Math gets the concept of Membership only in terms of sets, and as a result the member must be a component (sub-set) of a given set, which is a limitation of the concept of Membership.
On the contrary, OM enables to deal with both cases of Membership, where the traditional Membership deals with complexities, and the novel aspect deals with non-composed elements that share a common property.
The novel aspect of Membership goes beyond the limitations of the traditional approach of the concept of Membership.
Here is the part that clearly shows how the traditional approach can't deal with Membership among ur-elements (which is something that OM enables to do, in addition to the standard Membership among sets):
http://en.wikipedia.org/wiki/Urelemen
The Man, you are stuck with the notion of sets, and can't get any reasoning which goes beyond it.
The ridiculous and superfluous nonsense is a direct result of forcing your limited reasoning (which is stuck with the notion of sets) on OM's reasoning.
The fact is this:
1) Dimensional spaces do not need (co-)ordinates in order to be defined.
2) Dimensional spaces need degrees of freedom in order to be defined and here is the set of degrees of freedom of dimensional spaces:
{0,1,2,3,4,5,...}
By the difference of degrees of freedom among dimensional spaces.