Deeper than primes

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Not even close. The first is not even well-formed. It is gibberish--something you are so good at generating. The second isn't well-formed, either, but if accepted under the most likely interpretation, it purports the existence of something without restriction (since the condition beginning with the for-all is vacuous).

Let us see some of HatRack's expressions for the axiom of the empty set ( http://www.internationalskeptics.com/forums/showpost.php?p=6603001&postcount=12769 ):
HatRack said:
Let {} be the set such that if X is an element of {} then X ≠ X and if X ≠ X then X is an element of {}.
HatRack said:
Let {} be the set of ONLY those elements X where X ≠ X

Instead of {} let's use Z.

Let Z be the set such that if X is an element of Z then X ≠ X and if X ≠ X then X is an element of Z.

Since I am not a skillful user of latex syntax, then please formally express HatRack's axiom (by using Z instead of {}).
 
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Since I am not a skillful user of latex syntax, then please formally express HatRack's axiom (by using Z instead of {}).

Neither of the two things you quoted are axioms, they are definitions. I have been using the exact same axiom of the empty set the whole time, only I have stated it in countless informal variations: some with the definition given separately, some with it integrated, some much more explicit than necessary. But, they all have the same formal representation:

[latex]$$$\exists x \, \forall y \, \lnot (y \in x)$$$[/latex]​

It has nothing to do with your Latex skills and everything to do with your terrible logic skills. Since you BS your way around informal statements of logical propositions, we're just sticking to formal logic from now on.
 
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EDIT:

Let {} be the set of ONLY those elements X where X ≠ X

Instead of {} let us use z, and instead of X let use use x.

In that case HatRack's axiom of the empty set is:

Let z be the set of ONLY those elements x where xx

and its latex version is:

[latex]$$$\exists z\, \forall (x \ne x \,) ((x \ne x) \in z)$$$[/latex]​

Latex or not latex, HatRack's emty set exists only if it is the one and only one existing thing of a given mathematical universe.

Neither of the two things you quoted are axioms, they are definitions.

Nonesense!

[latex]$$$\exists z\,$$$[/latex] can be any set without its definition, and by your definition it is the one and only one exisintg (and empty) thing of your given mathematical universe.

jsfisher said:
(since the condition beginning with the for-all is vacuous).

This is exactly what we get by HatRack's emty set's axiom: a single existeng empty set, which is the one and only one existing object of a given mathematical univerese.
 
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Instead of {} let us use z, and instead of X let use use x.

...

Doron, this statement is still not well-formed:

[latex]$$$\exists z\, \forall (x \ne x \,) ((x \ne x) \in z)$$$[/latex]​

But, I'm going to accept its most common valid interpretation, which is:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​

This well-formed formal statement lines up precisely with what "Let z be the set of ONLY those elements x where x ≠ x" is communicating, if you assume that this statement is also declaring the existence of z.

Take the contrapositive:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​

Since the premise of the implication (x = x) is always valid, it simplifies to

[latex]$$$\exists z \, \forall x \, (x \notin z)$$$[/latex]​

Or:

[latex]$$$\exists z \, \forall x \, \lnot(x \in z)$$$[/latex]​

Thus, I have shown formally that my informal statement is logically equivalent to the Axiom of the Empty Set.

Now that we have cleared up your misunderstanding as to what I was communicating in a formal and rigorous manner, can we please move on to you answering this question:

In the following full and completely expressed axiom, what premise implicitly or explicitly assumes the proposition:

[latex]$$$\exists x \, \forall y \, \lnot (y \in x)$$$[/latex]​

Is that too much to ask?
 
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Doron,

How's that definition for "at the domain of" coming along? We are all waiting with bated breath for your revelation.

And there is also this:

Just out of interest, which of the following would constitute circular reasoning in doronetics:

[latex]$$$
\exists x \, \lnot (x \in x) \\
\exists x \, \forall y \ne x \, \lnot (y \in x) \\
\exists x \, \forall y \, (y \ne x) \wedge \lnot (y \in x) \\
\exists x \, \forall y \, y \preceq x \\
\exists x \, \forall y \, \lnot (y \succ x)
$$$[/latex]​

(The odd-looking relational operators in the last two deal with height.)
 
Doron, this statement is still not well-formed:

[latex]$$$\exists z\, \forall (x \ne x \,) ((x \ne x) \in z)$$$[/latex]​

But, I'm going to accept its most common valid interpretation, which is:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​

This well-formed formal statement lines up precisely with what "Let z be the set of ONLY those elements x where x ≠ x" is communicating, if you assume that this statement is also declaring the existence of z.

Take the contrapositive:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​

Since the premise of the implication (x = x) is always valid, it simplifies to

[latex]$$$\exists z \, \forall x \, (x \notin z)$$$[/latex]​

Or:

[latex]$$$\exists z \, \forall x \, \lnot(x \in z)$$$[/latex]​

Thus, I have shown formally that my informal statement is logically equivalent to the Axiom of the Empty Set.

Now that we have cleared up your misunderstanding as to what I was communicating in a formal and rigorous manner, can we please move on to you answering this question:

EDIT:

The weak version of the empty set:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​

By this axiom there exists z such that for all x, x is a member of z only if x does no exist.

In other words, since z exists, then nothing else exists.



The strong version of the empty set:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​

By this axiom there exists z such that for all x, x exists only if x is not a member of z.

In other words, since z exists, and also all x exist (because no given x is a memeber of z), then one of the x that are not members of the empty set z, is the empty set z.

In this case the conclusion that the empty set z exists, is based on the premise that the empty set z is one of the existing things that are not the members of the empty set z.

Since a thing can't be a part of the definition that defines that thing, and since a thing can't be determined without a definition ("z exists" is not a unique deceleration), then we can't avoid the conclusion that the strong version of the empty set is based on circular reasoning.
 
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The weak version of the empty set:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​
The strong version of the empty set:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​

Doron, those two are EQUIVALENT. Un-******-believable.
 
This thread has been going on for over two years, which I find to be absolutely amazing. As someone who hasn't studied set theory in over ten years, I'm obviously not able to follow the mathematical discussion as closely as I would like. My question to my fellow observers of this (epic) thread - not to the OP, because I'm interested in hearing other peoples opinions besides his:

Does this "discovery" - assuming it can one day be put into formal language - and assuming that what Doron is saying is true, which I realize is not the current prevailing opinion amongst 99% of people here, and flies in the face of most mathematics - does this discovery actually perform any useful purpose?

I don't have the quote handy, but earlier Doron claimed he has been working on this theory for 30 years. Surely, in 30 years, there has been a demonstrable purpose given for this discovery? I've worked in science (chemistry) for the last fifteen years, and I rarely go into a project without some final purpose in mind, whether it be a new catalyst or a new drug candidate, etc. Even when doing very basic, non-applied research, those types of projects fizzle out after no more than a year if the results cannot be applied to some "real world" issue.

Maybe I'm more ignorant of mathematics than I thought, but in my field (organic chem), if I worked on a project for 30 years and had nothing to show for it in the end - if I couldn't even express my idea properly to other trained chemists - I'd be the laughing stock of my entire profession. I want to give doron the benefit of the doubt, and I'm truly curious...what does this "new system of math" really do for us? (What could it do, I mean - it obviously doesn't do much at the moment).
 
This thread has been going on for over two years, which I find to be absolutely amazing. As someone who hasn't studied set theory in over ten years, I'm obviously not able to follow the mathematical discussion as closely as I would like. My question to my fellow observers of this (epic) thread - not to the OP, because I'm interested in hearing other peoples opinions besides his:

Does this "discovery" - assuming it can one day be put into formal language - and assuming that what Doron is saying is true, which I realize is not the current prevailing opinion amongst 99% of people here, and flies in the face of most mathematics - does this discovery actually perform any useful purpose?

I have asked Doron that same question several times just to be ignored.

I don't have the quote handy, but earlier Doron claimed he has been working on this theory for 30 years. Surely, in 30 years, there has been a demonstrable purpose given for this discovery? I've worked in science (chemistry) for the last fifteen years, and I rarely go into a project without some final purpose in mind, whether it be a new catalyst or a new drug candidate, etc. Even when doing very basic, non-applied research, those types of projects fizzle out after no more than a year if the results cannot be applied to some "real world" issue.

Maybe I'm more ignorant of mathematics than I thought, but in my field (organic chem), if I worked on a project for 30 years and had nothing to show for it in the end - if I couldn't even express my idea properly to other trained chemists - I'd be the laughing stock of my entire profession. I want to give doron the benefit of the doubt, and I'm truly curious...what does this "new system of math" really do for us? (What could it do, I mean - it obviously doesn't do much at the moment).

Thing is, Doron is not a mathematician, AFAIK. He doesn't even get basic first order logic for crying out loud. He uses Direct PerceptionTM...
 
This thread has been going on for over two years, which I find to be absolutely amazing. As someone who hasn't studied set theory in over ten years, I'm obviously not able to follow the mathematical discussion as closely as I would like. My question to my fellow observers of this (epic) thread - not to the OP, because I'm interested in hearing other peoples opinions besides his:

Does this "discovery" - assuming it can one day be put into formal language - and assuming that what Doron is saying is true, which I realize is not the current prevailing opinion amongst 99% of people here, and flies in the face of most mathematics - does this discovery actually perform any useful purpose?

I don't have the quote handy, but earlier Doron claimed he has been working on this theory for 30 years. Surely, in 30 years, there has been a demonstrable purpose given for this discovery? I've worked in science (chemistry) for the last fifteen years, and I rarely go into a project without some final purpose in mind, whether it be a new catalyst or a new drug candidate, etc. Even when doing very basic, non-applied research, those types of projects fizzle out after no more than a year if the results cannot be applied to some "real world" issue.

Maybe I'm more ignorant of mathematics than I thought, but in my field (organic chem), if I worked on a project for 30 years and had nothing to show for it in the end - if I couldn't even express my idea properly to other trained chemists - I'd be the laughing stock of my entire profession. I want to give doron the benefit of the doubt, and I'm truly curious...what does this "new system of math" really do for us? (What could it do, I mean - it obviously doesn't do much at the moment).

Welcome PiedPiper,

There are cases when one has a motivation for development even if there is no guarantee that his work will be accepted in his lifetime. I think that my efforts to develop what I call Organic Mathematics, is probably one of these cases.

For more details, please look at http://www.internationalskeptics.com/forums/showpost.php?p=6597986&postcount=12671

Thank you.
 
Welcome PiedPiper,

There are cases when one has a motivation for development even if there is no guarantee that his work will be accepted in his lifetime. I think that my efforts to develop what I call Organic Mathematics, is probably one of these cases.

Yes, Doron. The question was what is that motivation? Is it just that you won't get accepted in your lifetime? Good job then.
 
The weak version of the empty set:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​


The strong version of the empty set:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​

Oh... my. Do you seriously not understand that these two statements are equivalent? I would post a laughing dog here, but one laughing dog just wouldn't do this justice, nor would any finite number of laughing dogs.

Suppose we accept this statement as true: "if x is in z, then x is not equal to x". Now, suppose x is equal to x, is it possible for x to be in z then Doron?
 
Does this "discovery" - assuming it can one day be put into formal language - and assuming that what Doron is saying is true, which I realize is not the current prevailing opinion amongst 99% of people here, and flies in the face of most mathematics - does this discovery actually perform any useful purpose?

It's been mathematically proven in this thread that Doron's "discovery" is at odds with basic logic, so that's a big assumption. But, to answer your question: no, it does not provide any useful purpose. In fact, Doron claims that all of traditional mathematics, including calculus, is wrong. He also makes even more bizarre claims such as there being gaps on a line where we can't find points. So, it's actually counterproductive if anything.
 
Thing is, Doron is not a mathematician, AFAIK.

ftfy

He doesn't even get basic first order logic for crying out loud.

Now that we've managed to cut through all of his gibberish and narrow his foolishness down to his inability to grasp basic logic, I'm just waiting for him to claim that logic is wrong at this point.

He uses Direct PerceptionTM...

AKA mental illness.
 
It's been mathematically proven in this thread that Doron's "discovery" is at odds with basic logic, so that's a big assumption. But, to answer your question: no, it does not provide any useful purpose. In fact, Doron claims that all of traditional mathematics, including calculus, is wrong. He also makes even more bizarre claims such as there being gaps on a line where we can't find points. So, it's actually counterproductive if anything.

It is all the result of ones inability to logically grasp Non-locality.
 
You didn't answer my question Doron:

Suppose we accept this statement as true: "if x is in z, then x is not equal to x". Now, suppose x is equal to x, is it possible for x to be in z then Doron?

If x in z, then x does not exist (where "x does not exist" is equivalent to "x is not equal to x").

If x is equal to x (where "x is equal to x" is equivalent to "x exists"), then x is not in z.


Please open your mind to any detail in http://www.internationalskeptics.com/forums/showpost.php?p=6611705&postcount=12847 in order to understand exactly why you are wrong.
 
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The weak version of the empty set:...The strong version of the empty set:

Did you mean "the Axiom of the Empty Set"? Either way, though, there is no weak or strong versions. Just the one.

By this axiom there exists z such that for all x, x is a member of z only if x does no exist.

In other words, since z exists, then nothing else exists.

Where do you get this nonsense? The statement says that nothing is a member of the set Z. The "nothing else exists" is complete balderdash you made up because you insist on misunderstanding, ignoring, and redefining the important bits.

By this axiom there exists z such that for all x, x exists only if x is not a member of z.

It says nothing of the kind. More misunderstanding, ignoring, and redefining, I see. It says nothing is a member of the set Z.

Oh... my. Do you seriously not understand that these two statements are equivalent?

This time open your mind to any detail in http://www.internationalskeptics.com/forums/showpost.php?p=6611705&postcount=12847 in order to understand exactly why you are wrong.

Well, let's see:
[latex]$$$
\exists z \, \forall x \, (x \in z) \Rightarrow (x \ne x) \equiv \\
\exists z \, \forall x \, (\lnot (x \in z)) \vee (x \ne x) \equiv \\
\exists z \, \forall x \, (\lnot (x \in z)) \vee \lnot (x = x) \equiv \\
\exists z \, \forall x \, (x \notin z) \vee \lnot (x = x) \equiv \\
\exists z \, \forall x \, (\lnot (x = x)) \vee (x \notin z) \equiv \\
\exists z \, \forall x \, (x = x) \Rightarrow (x \notin z)
$$$[/latex]​

Wow, look at that. HatRack was correct; Doron was wrong.
 
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If x in z, then x does not exist (where "x does not exist" is equivalent to "x is not equal to x").

If x is equal to x (where "x is equal to x" is equivalent to "x exists"), then x is not a member of z.

So you admit then that the "weak" and "strong" versions of the empty set are equivalent:

The weak version of the empty set:

[latex]$$$\exists z \, \forall x \, (x \in z \rightarrow (x \ne x))$$$[/latex]​

The strong version of the empty set:

[latex]$$$\exists z \, \forall x \, ((x = x) \rightarrow x \notin z)$$$[/latex]​
 
[latex]$$ \, \exists z \, \forall x\, (x \in z) \Rightarrow (x \ne x) $$[/latex]

That is, there exists a set we'll call Z such at for any set X, X being a member of Z implies X is not equal to itself. Since this simple translation has escaped exactly one individual, let's break it down into kindergarten-size steps:

English || Math
There exists a set Z || [latex]$$ \, \underline{\exists z} \, \forall x\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
such that for any set X || [latex]$$ \, \exists z \, \underline{\forall x}\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
X being a member of Z || [latex]$$ \, \exists z \, \forall x\, \underline{(x \in z)} \Rightarrow (x \ne x) $$[/latex]
implies || [latex]$$ \, \exists z \, \forall x\, (x \in z)\, \underline{\Rightarrow}\, (x \ne x) $$[/latex]
X is not equal to itself ||[latex]$$ \, \exists z \, \forall x\, (x \in z) \Rightarrow \underline{(x \ne x)} $$[/latex]

Within the implication, the consequence (that X is not equal to itself) is never true, and therefore the premise of the implication (that X is a member of Z) must be never true for the implication to be valid. So, in it's own way, the implication establishes that X is not a member of Z. Thus, the statement is directly convertible to:

[latex]$$ \exists z\, \forall x\, \lnot (x \in z) $$[/latex]
 
For all persons posting in this thread, person is not doron if and only if the person is right.

Better?
;)

Weak axiom of rightness:
[latex]$$$\forall p, p \in Posters\ Right(p) \rightarrow Doron \neq p$$$[/latex]

Strong axiom of rightness:
[latex]$$$\forall p, p \in Posters\ Doron \neq p \rightarrow Right(p)$$$[/latex]

I don't know if I can accept the strong axiom of rightness. :D
 
No Doron, they are not. jsfisher rigorously proved that they are the same right here http://www.internationalskeptics.com/forums/showthread.php?postid=6612258 in case you missed it.

If calling X "nonsense" (by avoiding any further details that support ones argument) is a rigorous proof, then jsfisher indeed rigorously proved his argument.

I see that you can't get the difference between the weak and the storng version, so let us try a simpler way:

By the weak version the empty set exists because only the non-existing (xx) is its member, but then all existing cases (x=x) that are not its members are not considered and as a result there is no guarantee that being empty is a tautology.

By the strong version the empty set exists because the existing (x=x) is not its member, but then one of the existing cases is the empty set itself. In this case, the defined if a factor of its own definition.

Since any existing thing is uniquely identified by a definition, then any use of X as a part of the definition of X, is known as circular reasoning, which is an invalid reasoning.
 
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EDIT:

(X = X) means: "X exists"

(X ≠ X) means: "X does not exist"



English || Math
There exists a set Z || [latex]$$ \, \underline{\exists z} \, \forall x\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
such that for any set X || [latex]$$ \, \exists z \, \underline{\forall x}\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
X being a member of Z || [latex]$$ \, \exists z \, \forall x\, \underline{(x \in z)} \Rightarrow (x \ne x) $$[/latex]
implies || [latex]$$ \, \exists z \, \forall x\, (x \in z)\, \underline{\Rightarrow}\, (x \ne x) $$[/latex]
X does not exist||[latex]$$ \, \exists z \, \forall x\, (x \in z) \Rightarrow \underline{(x \ne x)} $$[/latex]

It has to be clear that if (X ≠ X) does not mean "X does not exist", then Z is not empty.
 
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If calling X "nonsense" (by avoiding any further details that support ones argument) is a rigorous proof, then jsfisher indeed rigorously proved his argument.

...

Congratulations Doron, you managed to completely ignore jsfisher's rigorous proof that your "weak" and "strong" versions are one and the same. Here it is again:

[latex]$$$
\exists z \, \forall x \, (x \in z) \Rightarrow (x \ne x) \equiv \\
\exists z \, \forall x \, (\lnot (x \in z)) \vee (x \ne x) \equiv \\
\exists z \, \forall x \, (\lnot (x \in z)) \vee \lnot (x = x) \equiv \\
\exists z \, \forall x \, (x \notin z) \vee \lnot (x = x) \equiv \\
\exists z \, \forall x \, (\lnot (x = x)) \vee (x \notin z) \equiv \\
\exists z \, \forall x \, (x = x) \Rightarrow (x \notin z)
$$$[/latex]​

What is your response to this formal, rigorous proof?
 

That does not answer my question. jsfisher provided a rigorous, formal proof in post #12860 which was repeated again in post #12870. There is no flaw in the proof, it follows from the basic axioms of first-order predicate calculus. It demonstrates without a doubt that the two statements, the "weak" and "strong" version as you call them, are logically equivalent. What is your response? Are you now going to claim that the axioms of logic are incorrect?
 
That does not answer my question. jsfisher provided a rigorous, formal proof in post #12860 which was repeated again in post #12870.

Please read vary carefully all of this post, then "hold your horses" and think about it and only then reply to it.


-----------------------------


(X = X) means: "X exists"

(X ≠ X) means: "X does not exist"

English || Math
There exists a set Z || [latex]$$ \, \underline{\exists z} \, \forall x\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
such that for any set X || [latex]$$ \, \exists z \, \underline{\forall x}\, (x \in z) \Rightarrow (x \ne x) $$[/latex]
X being a member of Z || [latex]$$ \, \exists z \, \forall x\, \underline{(x \in z)} \Rightarrow (x \ne x) $$[/latex]
implies || [latex]$$ \, \exists z \, \forall x\, (x \in z)\, \underline{\Rightarrow}\, (x \ne x) $$[/latex]
X does not exist||[latex]$$ \, \exists z \, \forall x\, (x \in z) \Rightarrow \underline{(x \ne x)} $$[/latex]

It has to be clear that if (X ≠ X) does not mean "X does not exist", then Z is not empty.


-----------------------------


I see that you can't get the difference between the weak and the storng version, so let us try a simpler way:

By the weak version the empty set exists because only the non-existing (xx) is its member, but then all existing cases (x=x) that are not its members are not considered and as a result there is no guarantee that being empty is a tautology.

By the strong version the empty set exists because the existing (x=x) is not its member, but then one of the existing cases is the empty set itself. In this case, the defined is some factor of its own definition.

Since any existing thing is uniquely identified by a definition, then any use of X as a part of the definition of X, is known as circular reasoning, which is an invalid reasoning.
 
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Please read vary carefully all of this post, then "hold your horses" and think about it and only then reply to it.

I already did read it very carefully, it adds nothing of substance.

(X = X) means: "X exists"

That's not what it means. Although, it is true for all existent sets.

(X ≠ X) means: "X does not exist"

That's not what it means, it means that a set does not have the same elements as itself, and it is false for all existent sets.

It has to be clear that if (X ≠ X) does not mean "X does not exist", then Z is not empty.

See above.

I see that you can't get the difference between the weak and the storng version:

There is no difference, as has been proven formally.

By the weak version the empty set exists because only the non-existing (xx) is its member, but then all existing cases (x=x) that are not its members are not considered and as a result there is no guarantee that being empty is a tautology.

By the strong version the empty set exists because the existing (x=x) is not its member, but then one of the existing cases is the empty set itself. In this case, the defined is some factor of its own definition.

Since any existing thing is uniquely identified by a definition, then any use of X as a part of the definition of X, is known as circular reasoning, which is an invalid reasoning.

All of this is irrelevant, because jsfisher has proven, using formal and precise language, as opposed to this informal nonsense, that the two versions are one and the same. Thus, we come back to my original question: what is the flaw in jsfisher's proof?
 
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...
Does this "discovery" - assuming it can one day be put into formal language - and assuming that what Doron is saying is true, which I realize is not the current prevailing opinion amongst 99% of people here, and flies in the face of most mathematics - does this discovery actually perform any useful purpose?

I don't have the quote handy, but earlier Doron claimed he has been working on this theory for 30 years. Surely, in 30 years, there has been a demonstrable purpose given for this discovery? I've worked in science (chemistry) for the last fifteen years, and I rarely go into a project without some final purpose in mind, whether it be a new catalyst or a new drug candidate, etc. Even when doing very basic, non-applied research, those types of projects fizzle out after no more than a year if the results cannot be applied to some "real world" issue.

Many moons ago, when the Earth herself was young, when all this was fields, and this thread was but a sapling, Doron claimed that OM could revolutionise teaching and bring peace to the world (yes!). We asked him many times if he could provide one single worked example of any practical or hypothetical use for OM, and he never responded.

The problem is, that to profit from OM apparently requires an ability (Direct Perceptiontm) to instinctively perceive and understand Non-Localitytm. So far, it would appear that Doron is the unique exponent of this ability. Unfortunately, while some of us feel we have an idea of what Doron means by Non-Localitytm, the maths still looks wrong.

The chances of OM being used to teach the world's children and bring universal peace are somewhat hampered by it being intelligible only to Doron himself. I'm not sure whether we should be grateful for this small mercy, or not... ;)
 
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So, according to Doron, the simple expression, A = B, does not mean that A is equal to be.

Good to know. Mathematical notation can be so confusing.
 
So, according to Doron, the simple expression, A = B, does not mean that A is equal to be.

Good to know. Mathematical notation can be so confusing.

Yeah, it is good to know. We're closed under the concept of collection so we can't possibly know the true meaning of mathematical notation. Good thing Doron and his Direct Perception are here to save the day. I've been thinking this whole time that defining something doesn't prove its existence, silly me! The set of all sets that do not contain themselves exists after all.
 
Please start here:

~URL removed because I cannot post URLs until I have 15 posts~


I am open to your your criticism.

Ah, thank you.

I apologize in advance for the length and depth of this post, I had originally meant to be succinct; however, I wanted to make sure that I was clear when explaining both the things I didn't quite understand and the assumptions that I made while reading this paper.

I know this isn't currently the topic at hand in the thread; however, I was reading Organic Mathematics - The Science of Direct Perception, and I had a few questions.

I guess the first one is, what exactly do we mean when we say "1-dimensional?"

The informal definition with which I am familiar would be something along the lines of "An object is n-dimensional if a minimum on n coordinates is required to describe the location of a point on this object."

Thus a point would be 0-dimensional (how many coordinates do you need to specify one point out of one point?)

A curve (e.g. a line, circle, whatever) would be 1-dimensional because, given a start point, we need only to describe how "far" along this line we need to move to reach our point.

And so on, and so forth.

So, that's all fine and dandy... but what happens when we talk about the set {0,1} consisting of two points on the real number line? Its clearly not 0-dim, (at least by my definition) because if we wish to specify a single point of this set, then we need one coordinate to distinguish which of the two points we mean.

So, if this is 1-dim, then this seems like it would be a counterexample to the claim that "No collection of 0-dim elements may cover a 1-dim element," because the points 0 & 1 cover the subset of the number line consisting of the points {0,1}.

So, I guess my first question boils down to:

If this isn't a 1-dim element, why isn't it? Is it because my definition of an n-dimensional element is incorrect/insufficient? If so, what definition should I use? Is it because the kind of object I described (an object consisting of two discrete points) is not something we can talk about the dimensionality of? If this is the case, for what kind of objects can we talk about dimensionality? Do they need to be simply connected? Or, is there some other reason as to why my reasoning is flawed?

A second question I have, is about the concepts of locality/non-locality. I just want to make sure I understand what you mean.

A point is an example of locality, because a point exists only in one specific location, correct?

A line on the other hand, would have a non-local property, because it exists in more than one specific location at once; e.g. In the XY plane, the line y = 0 exists at the points (1,0) and (2,0) (and at many other points) and therefore does not exist in one specific location... giving it its non-local property? Is that the correct line of reasoning?

Likewise, would the object I described earlier (consisting of the points {0,1} along the number line) be an example of something with a non-local property?

Another thing, is a point the only element with the local-property? If not, what other elements may have that property?

And finally, you say that "no collection of 0-dim elements can completely cover a 1-dim element." Which, if I understand you correctly, would imply such things as "The real number line is not completely covered by points." Unless I am misinterpreting what you mean, of course.

Statements such as "The real number line is not completely covered by points" are directly contrary to my intuition. That is to say, I read the statement "The real number line is not completely covered by points" and I think of it as its contrapositive: "There exists at least one spot on the real number line which is not covered by a point."

The way with which I am familiar with constructing the real numbers is the following.

We begin with our additive identity and our multiplicative identity. {0,1}

From here we obtain the ordinals by inductively adding one. That is to say, we define 1+1=2 then we define 2+1=3 and so on and so forth. We get the natural numbers. {0,1,2,3,...}

Next for each ordinal number, we adjoin an additive inverse, and we obtain the integers. {...,-3,-2,-1,0,1,2,3,...}

From here, we adjoin the multiplicative inverses of each number and we get: {...,-3,-2,-1,-1/2,-1/3,...,0,...,1/3,1/2,1,2,3,...}

Next, we adjoin the products and sums of all of the elements we currently have with each other to obtain the rational numbers.

There are several intermediary steps between here and the entirety of the reals that one could take (the constructable numbers, the algebraic numbers);however, they are immaterial as the next step encompasses them both.

To adjoin the irrationals, we proceed in the manner of Dedekind. I find it helps to take a step back and visualize what we are about to do before we do it, for clarity's sake.

Imagine, if you will, the XY plane. The X-axis shall serve as our real number line. Imagine, if you will, that we draw a straight line - any line- so that it intersects the X-axis somewhere, anywhere. Maybe it intersects at one of these nice rational points that we know about. But maybe it doesn't. For our purposes we will assume that the line we drew, did not intersect the X-axis at a rational point.

If we look at all of the rational numbers on the X-axis, we find that this line splits them into two groups. There are those rational numbers to the left of this line, we will call them, collectively, A. There are also those rational numbers to the right of this line, we will call them, collectively, B. Because, for the purposes of our imaginings, this line did not intersect the X-axis at a rational point, we must have that all rational numbers are contained in either A or B. (We know all rational numbers must either fall to the left of this point of intersection, to the right of this point of intersection or they must be exactly on this point of intersection, and since we are assuming that no rational numbers are on this point of intersection they must all belong to either A or B). Further, with a little thought it becomes clear that A has no greatest element and B has no least element.

Now, with this physical intuition in mind, we turn our attention back to the problem at hand (constructing the rest of the reals from the rationals).

We divide the Rationals up into two sets, A and B. Where A has the property that it has no greatest element, and further that given any choice of an element a in A, every rational number less than our chosen a is also in A. Likewise we choose B so that it has the property that it has no least element, and further that given any choice of an element b in B, every rational number greater than that chosen b is also in B.

This is a very verbose way of saying that we are doing fundamentally the same thing as when we were discussing lines intersecting the X-axis in the XY plane. The sets A and B we formed from those intersections have the same properties as the ones we described.

Armed with our sets A and B, we look and we see that the elements of the two sets A and B get arbitrarily close together, but they never actually meet. So we take the point on the real line, that lies between all of the members of A and all of the members of B, and we adjoin it to the real numbers. And so, we have our first irrational number.

For every possible choice of our sets A and B, we adjoin the numbers between all of the members of those sets as well; This is how we construct the irrational numbers.

This is the method I am familiar with, and it seems to me as if that gives us a real number line which is entirely covered by points.

Going back to what I said earlier, this would not be true if "There exists at least one spot on the real number line which is not covered by a point."

However, if we posit that such a spot exists, we can clearly dismiss the possibility that it is a rational number, because we know those to be on the real line because of how they were constructed.

Since this uncovered spot on the real line is not a rational, we must have that it splits the rationals into two groups A, consisting of those rationals to the left of this uncovered spot and B, consisting of those rationals to the right of this uncovered spot. However, if this uncovered spot partitions the rationals in the described manner, then this spot fits the criteria set forth when we were constructing the irrationals, and therefore must be one of the irrationals that we adjoined.

Therefore, such an "uncovered spot" must not exist.

That argument seems to me as if it suffices to describe a 1-dimensional object which is completely covered by 0-dimensional objects. Although perhaps you may find a flaw with the method of construction, or you may be able to demonstrate the existence of a point that is not covered.

I do have some further questions about the specifics of locality/non-locality linkage; however, it seems to me that I should wait until I am sure I understand locality and non-locality before I decide that I do not understand their linkage.

Once again, I apologize for the tremendous length of this post. And thanks in advance for clearing these issues up for me.
 
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