Bjarne
Philosopher
- Joined
- Oct 6, 2009
- Messages
- 5,087
Without context it doesn't seem to mean anything. If it is supposed to be a formula, it is incomplete.
Hans
Hans
I belive it mean "per year" backwards in time
Without context it doesn't seem to mean anything. If it is supposed to be a formula, it is incomplete.
Hans
Hans
I belive it mean "per year" backwards in time
And?
Let say the orbit of the Earth would change so that the distance to the Earth would be 30 km shorter by perihelion and 30 km longer by aphelion.
http://www.science27.com/forum/moonsun2.jpg
How much would that affect the Moons orbital eccentricity after one year.
As shown at the image now the moon would at PERIHELION (both towards apogee and towards perigee) always be 30 km. closer to the Sun. – And by APHELION (both towards apogee and towards perigee) is always be 30 km further away from the Sun.
It seems you have the A and P wrong in the lower right position.
That would depend on what changed Earth's orbit. Even such a small change would have to have a cause. I can't just now think of a cause that would not also affect the moon.
And how did you reach that conclusion?
RR affecting the Earth's orbit (pushing perihelion closer to the Sun and Aphelion further away) (36 km/year).
RR does affect the Earth but not the Moon in a way you can observe directly.
If RR was affecting the Moon directly the Moon would fall, - it does not happen.
So the tidal force must counteract the basic deceleration that would have been a result of RR, if the Earth did not had any tidal force.
Which mean; some of the force / energy from the tidal force (of the Moon) is used to overcome RR (not to be affected by RR ).
But the Earth do not have a tidal force strong enough, - so the Earth is affected, and due to that the Moon is indirectly affected as demonstrated by the illustration
So the ting is; because the Earth is changing its orbit, - the moon mustchange its orbital eccentricity. ( ekstension of the orbital eccentricity) .
How can that be calculated.
The eccentricity of the Earth's orbit is currently about 0.0167, meaning that the Earth's orbit is nearly circular, the semiminor axis is 99.98% of the semimajor axis. Over thousands of years, the eccentricity of the Earth's orbit varies from nearly 0.0034 to almost 0.058 as a result of gravitational attractions among the planets
So it is possible that the current change is 37km/year, but there is no indication that it is due to RR.
The Q is how much the Sun effect the orbit of the Moon.
Why did you wrote that. I thought you would belived that the distance to the Sun is as we belive it is ?
I just did, but I do not know the correct equationSay, Bjarne, when do you start to do your own homework?
Hans
Say, Bjarne, when do you start to do your own homework?
Priceless.I just did, but I do not know the correct equation
So here is what i did.
[snip]
But well I must have the right equation to get it correct.
When I have these , don’t worry I can do that piece of homework.
I belive it mean "per year" backwards in time
That appears to be tables of stuff you just made up.I just did
Then you haven't done your homework.but I do not know the correct equation
What about when it's not?The result only apply in that spilt second the moon is closer to the Sun (30 km closer)
You mean 0.00000000021144(in whatever units you used) is not a large number?so the exstra pull from the Sun do not cause a large extenion of the moons orbital eccentricity.
That would certainly help.But well I must have the right equation to get it correct.
I seem to remember you claiming to be able to produce equations before.When I have these , don’t worry I can do that piece of homework.
That appears to be tables of stuff you just made up.
You mean 0.00000000021144(in whatever units you used) is not a large number?
Yes, the way I compared in useless.
I cannot use this for anything.
The influence happens gradually.
Furthermore I am not sure the tidal effect is counteracting the RR of the Moon, but rather that due to a perihelion precession of the Moon = 1 year, - the influence is canceling out each one year, except that influence that is due to the further approach of the Earth to (the Suns) Perihelion and further distance increase to aphelion.
But as I wrote the Moons orbital eccentricity due to the orbít change of the Earth happens gradually and slowly. I must use the excact equation, no doubt about that.
I am willing to pay for getting that right ...
The result only apply in that spilt second the moon is closer to the Sun (30 km closer) - so the exstra pull from the Sun do not cause a large extenion of the moons orbital eccentricity.
I cannot use this for anything.
The influence happens gradually.
You seem to have already realized it, but it is so important that I want to point it out anyway:
You can never calculate a dynamic system as a series of steady stages. NEVER.
Hans
Bjarne, what exactly is it you are trying to figure out?
You keep referring to RR, but this phenomenon doesn't exist in the way you imagine, so if you're looking for the formular for that, you are not going to find it.
Hans
RR (Relativistic Resitance) exists without any doubt. (You too know that)..
The question is only whether that total brain-dead idea; - that is "should" disappear by constant speed, (without any evidence / logic for such rubbish-statement), - is true.
(Which seems to be impossible at least seen from the perspective of a cow concrete brain).
So now pretend RR always exist also by constant speed, - what would be the consequences;

Well first at all the evidence;
That Milankovitch was correct, - but Milankovitch just “forgot” a factor > RR influence.

Furthermore that all Space probes anomalies can be explained just based on that simple law of nature.
RR can explain why stars behave so “strange” – Ellipse galaxies do not “close” as expected and starts continues to “fall”.

In the end of the day RR tricker a BigChrunch and a BigBang.
RR must be suspected for being the ultimate cause of gravity. .

When RR affects the orbit of the Earth as shown above, there will be an small indirect effect on the Moons orbit too, simply because the Sun’s pull in the moon will change when the orbit the Earth is getting for example; 30-40 km closer to the Sun at perihelion and 30-40 km further away from the Sun at aphelion, - per year.
I think the Laser measurement programme not is programmed to detect changing’s at such small time-scale, but mainly only to detect long term variation.
And here is what that cow would answer you;- Wait, I'll try to give it a bovine angle; that may help you: As long as you push a cow, you will feel resistance. Stop pushing, and there is no resistance. Capisco?
That one day he (or what is left of him) would follow the rest of the Universe into a BigChrunch, - in that process he could be the fastest and heavies Santa Claus ever existing and ever contributing to a new Bigbang explosion (due to mad RR / gravity/ speed).’So now pretend that Santa Claus exists. - What would be the consequences?
All the Space probes anomalies are in the first places caused by deceleration + (in the follow wind zone) = acceleration (or more exact relative less deceleration).Unfortunately, they can't. Pioneer is being accelerated towards the sun, causing it to slow down, while the fly-by anomaly causes a speed up..
The effect on satellite is much weaker as of the Moon. These are apogee anomalies fast building up and cancel out. If you give me the duration of the apogee precession period, I can easy calculate the influence. Notice time of 1 orbit is always the same (not affected) only the distance to the Satellites by apogee and perigee. Let assume the influence is 5 cm per period (before it cancel out) - the only way of discovering this would be that the signal will come 0,05 / 300,000,000 later or sooner as expected. Who do you think would notice. I believe even not an atomic watch?And of course, all the communication and GPS satellites behave precisely as predicted. So, no evidence there
The evidence is clear in that moment you see it all from above the bush level.How would it explain the behavior of stars? Stars generally don't move at relativistic speeds. No evidence there
I am afraid there are no “rest”So, according to you, masses at rest have no gravity?
No, RR in or Solar system is the first place you must understand it.And, according to this, all your previous 'theories' about absorption of space, space vacuum, etc. are then wrong??
Seen form an overall perspective no, - you only get the results you want, - based on the uncompleted data you enter into the equations.Unfortunately, as shown in the link I gave you above, the eccentricity of Earth's orbit is currently getting smaller. In other words, the exact opposite is happening. - There is nothing as deadly for a thesis as direct observational evidence to the contrary.