http://news.yahoo.com/spy-chief-nominated-romanias-premier-182955470.html
Spy chief nominated as Romania's new premier
Spy chief nominated as Romania's new premier
Yep. RC is getting it, sol is wobbling, ben's got nothing, and Clinger has shown himself to be an ineffectual windbag who pretends he's dealt with the argument by posing homework questions.This is still here?
I didn't cut anything out, my sleight-of-hand retort was in response to your ad-hominem suggestion that I'd tried to hide something."Get away with a sleight of hand." How ironic indeed!
I didn't miss it. What we're talking about here is a frozen star. It isn't a singularity at all. There are no infinities, it's merely a c=0.It's as if I didn't hilite the most relevant part of post #51 just to make sure you couldn't possibly miss it...
It's as much a singularity as a sphere of ice is a singularity to a fish frozen into it.That quote by Einstein in that post shows quite clearly what he thought about the Schwarzschild horizon: that spacetime does not simply end at the horizon and that the vanishing of coefficient of dt at r=2m (ρ=0) does not imply a genuine, physical singularity. Both of these in direct contradiction of your claims.
Sol deserved the little lecture. Move on.Though that might have been fine if it wasn't you who have continually insisted on Einstein's opinions on the matter, painted himself as being "with" Einstein, and his opponents as cranks for going "against" him.
As above.Fine, I'll repeat it again:
I replied to it in detail, see post #88, it was simple stuff concerning maps.You are making a huge conceptual mistake. I suppose it's too much to ask for you to listen to W.D.Clinger's clear exposition on coordinates,
That's got nothing to do with it. A bullet drops the same amount in a second as a dropped ball.so I'll simply say this: if gravity was described by a scalar field, you might have been right. But gravity is a rank-2 tensor field: what's important is not just where you are, but how you are moving. This should have been clear from the metric, but it is especially explicit in the geodesic equation:
[latex]$\frac{d^2x^\alpha}{d\tau^2} = -\Gamma^{\alpha}_{\mu\nu}\frac{dx^\mu}{d\tau}\frac{dx^\nu}{d\tau}$[/latex]
giving the acceleration of a test particle in a gravitational field. This is not some modern invention. It's right there from the very genesis of GTR, in Einstein's first paper on the topic, and the Christoffel symbols themselves being called by Einstein the components of the gravitational field. Once one realizes that the effect of gravity depends not only on where the particle is but also how it is moving, it becomes clear that arguments like yours miss the mark completely.
Electromagnetic fields exist. Remember what Minkowski said: "Then in the description of the field produced by the electron we see that the separation of the field into electric and magnetic force is a relative one with regard to the underlying time axis...". It's one field and two forces. Sounds to be as if we need to have a separate discussion about electromagnetism. One for another day.It's like discussing the behavior of electric charges but forgetting that magnetic fields exist (which give EM velocity dependence as well).
Your simple proof was wrong. When 2M/r = 1 at r = 2M you've got a division by zero in [latex]\[ \frac{dt}{d\tau} = \frac{e}{1-2M/r} \][/latex]. That's an undefined result, an infinity. But you just sail on past it. The finite proper time demands an infinite coordinate time, so it hasn't happened yet, and it never ever will.I've outlined a simple proof from the geodesic equation that radial freefall matches Newtonian behavior in Schwarzschild r and proper time τ in post #64. More recently, ben m posted the cycloidal relations for this problem, which are again well-known for Newtonian gravitation (but obviously with ordinary radius and universal time for Newtonian case, rather than Schwarzschild r and proper time).
And even a blind man can see the problem with it.I've derived the above using nothing but what is found in Einstein's original paper plus knowledge of Schwarzschild metric.
Ditto.Uncle Albert says you are wrong in just about every possible way. If you've actually read and understood his paper, you wouldn't have these problems.
RC has always got it, sol has always been solid, ben got that you have nothing to support your position and Clinger has shown himself to be a competent mathematician.Yep. RC is getting it, sol is wobbling, ben's got nothing, and Clinger has shown himself to be an ineffectual windbag who pretends he's dealt with the argument by posing homework questions.
Good stuff. I'll check the crossover point re a discussion on another thread.sol invictus said:Yes, that looks right. I didn't remember where the crossover was (as you can see from that plot, for a very low orbit the net effect would be a slowing), but I checked another source and it is indeed the case that GPS clocks run fast.
Come on man, think. Nobody can see anything when the speed of light is zero. And it is a real property of that location: you know this from those parallel-mirror light clocks I keep showing you. And because a photon doesn't slow down like a cannonball whilst moving vertically up out of a gravitational field. We don't see photons travelling at some slower speed because they've been emitted by a giant star. In similar vein a photon emitted vertically from the event horizon isn't going to lose all its speed and obligingly fall back down. It isn't going to curve back down either, because it was emitted vertically. The black hole is black and the photon doesn't get out because its initial speed is zero.No we don't. If "speed of light is zero" were a real property of that location, it would be seen as such by anyone at that location. It's not.
It's no catch at all, merely cheap wordplay and obfuscation because the guy has no counter-argument. And if you want me to talk about the pole-in-the-barn paradox, it'll be my pleasure.Good catch. Farsight's saying "nothing has fallen into the black hole yet", and pretending it's an absolute statement, is basically the same mistake as saying "the back of the ladder hasn't entered the barn yet" in the famous thought-experiment.W.D.Clingewr said:What Farsight isn't telling you, and appears not even to know, is that relativity has no well-defined concept of "yet". Your concept of "yet", like your concept of time itself, is observer-dependent; it depends on the chart (aka coordinate system/frame/patch) you choose to use. That's why the theory of relativity is called the theory of relativity.
http://news.yahoo.com/spy-chief-nominated-romanias-premier-182955470.html
Spy chief nominated as Romania's new premier
This is going to be fun.Suppose someone falls into a black hole, holding a "light clock" (an arrangement of two mirrors held a fixed distance apart by a rigid piece of metal, with a light pulse bouncing back and forth between the mirrors).
The stock answer is no, but this misses the crucial point: she hasn't crossed the event horizon yet. Even if she fell into the black hole a billion years ago, she hasn't crossed the event horizon yet. As we speak she's at the event horizon, frozen along with her light pulse, and she isn't noticing anything. She is in the same situation as a person who has been accelerated to the speed of light, her biological processes have stopped. We all know we can't actually accelerate our victim to the speed of light, I say it's because we're made of the darn stuff whilst you doubtless say it's because it would take infinite energy, but set that aside. Just go with the flow and assume we can. The person travelling at c is subject to infinite time dilation. For light to enter her eyes orthogonal to the direction of travel, light would have to be travelling faster than light. It can't happen. Light can't move in her frame, and nor can electromagnetic or biological processes. So it's not a case of she doesn't notice anything unusual, it's a case of she doesn't see or think.Q1: Assuming our victim is inside a sealed container and cannot see out, will she notice anything when she crosses the horizon? Specifically, measured with respect to the time scale of her own biological processes (or any other clock or process inside the container), will the time it takes for the light in the light clock to bounce back and forth change?
See above.A1: Nope - not if the black hole is large enough that tidal forces are small at the horizon, at least.
Whoa. Let's have your observer open a porthole as she falls into the black hole. She's looking back at the universe. What does she see just as she reaches the event horizon?Q2: After having passed through the horizon, our intrepid investigator opens a porthole.
You still don't get this sol, and it's important: time doesn't move. Things move. Things like light. Can you see time moving? No. Can you see light moving? Yes. It isn't time that stops at the event horizon. It's light. And remember electron spin and diffraction, and annihilation. Everything stops.Can she still see stars etc. that are outside the hole? Can she receive signals sent by her friend in a spaceship hovering above the horizon?
A2: Yes to both. They might be distorted, but they are still visible. That would be quite hard to understand if time really stopped at the horizon...
Where above? It isn't hot at all. Heat is an emergent property of motion. Motion is time-dilated out of existence. And I'm off to bed.The truly fascinating this is how this is compatible with the description of the horizon as a hot membrane that I just gave above. Exercise for the reader: figure out how and why that's possible.
Come on man, think. Nobody can see anything when the speed of light is zero.
And it is a real property of that location: you know this from those parallel-mirror light clocks I keep showing you.
The stock answer is no, but this misses the crucial point: she hasn't crossed the event horizon yet.
Whoa. Let's have your observer open a porthole as she falls into the black hole. She's looking back at the universe. What does she see just as she reaches the event horizon?
You still don't get this sol, and it's important: time doesn't move. Things move. Things like light. Can you see time moving? No. Can you see light moving?
The stock answer is no, but this misses the crucial point: she hasn't crossed the event horizon yet.
The stock answer is nosol invictus said:Q1: Assuming our victim is inside a sealed container and cannot see out, will she notice anything when she crosses the horizon? Specifically, measured with respect to the time scale of her own biological processes (or any other clock or process inside the container), will the time it takes for the light in the light clock to bounce back and forth change?
No. She experiences what she'd experience if she was moving at c. She experiences nothing.So you agree that she experiences nothing at all unusual.
That moment hasn't come yet. Let's you and me wait a billion years, and that moment still hasn't come yet. It never comes. She's sitting there in front of her light clock, but light isn't moving in the clock, it isn't moving towards her eyes, and electromagnetic processes aren't moving in her instruments and in her brain.She's sitting there looking at her light clock, and it's behaving exactly as it always did, she feels no forces, none of the other instruments inside her sealed lab read anything. For her, the moment when she arrives at the horizon...
Those finite number of light bounces takes an infinite coordinate time to occur. They never happen.(or let's say when she arrives at 0.0000000000000000000000000000000000001 mm outside it) is just a perfectly normal moment, after a finite number of light-clock-bounces.
Not so. The moment never comes. The supposed time after that moment is time after the end of time. Come on sol, look at the lefthand chart on post 135. The chopped-off top goes up to infinity. There's no getting past it.But according to you we have to cut time off right at that perfectly ordinary, unremarkable moment. You can't ask what comes after that moment.
Stop talking about stopping time. make the leap to stopping light, and then there's nothing bizarre about it at all. Think back to the optical clocks losing synchronisation at different elevations, simplified to parallel-mirror light clocks.You can't ask what bizarre law of physics could stop time right then, with nothing unusual happening, in a vacuum region of space.
I don't fight shy of asking questions. I examined my own convictions long ago, and I work hard not to have any. Show me some scientific evidence that disproves something I say, and I will readily put my hands up, hang my head in shame, and say Sorry, I was wrong. I've done it before and I'll do it again. But that's what it takes, not some wan accusation concerning psychology.You can't ask any of those questions, because you won't let yourself.
Not so. I challenge the use of neverneverland coordinates in cloud-cuckoo land. What we have here is an inverted version of Zeno's paradox: It takes an arrow one second to move half the distance between it and the target, and the arrow doesn't know it's slowing down. It never hits the target. The arrow's finite proper time is a fairytale.You refuse to use any system of coordinates other than the Schwarzschild coordinates.
Spacetime isn't something real, sol. Space is real, that black stuff between the stars. The thing that sustains waves and fields. Motion through it is real. Spacetime is a mathematical space in which there is no motion. You don't move through it. And when light doesn't move at the event horizon, all worldlines go straight up. Come on sol, we're nearly there with this. Examine your own psychology. You can't elucidate a clear explanation of why I'm wrong. Why not? Because I'm not. And I'm not some "my theory" guy pushing some damn fool hypothesis, this is just frozen-star stuff that you've never thought through. Think it through for yourself. Ask yourself whether the time really flows and whether the speed of light is really constant, and what gravitational time dilation really is. Don't stay locked in a position whereby you can't ask any of those questions, because you won't let yourself.And that (arbitrary and unjustified) choice prevents you from asking or answering any such question, because those coordinates only cover part of the spacetime.
There are no frames ben. They don't exist. A reference frame isn't something you can point to up in the sky. Your observations and your measurements are affected by your motion, and by the thing we call gravitational potential, that's all.The speed of light isn't actually zero. There is a particular frame in which a particular ratio of coordinates equates to zero. That ratio is observer-dependent, and except in special contexts it doesn't actually represent the speed of light.
It's a good idea because frames aren't real whilst gravitational potential is. Light clocks tick slower when you're lower, and so do you. That's what actually happens, and light doesn't escape from a black hole. Now come on, address this:Nope. You keep analyzing that clock from the frame of special observers---one inertial observer in flat space, another maximally-accelerating observer near the horizon---and ignoring others. I have no idea why you think this is a good idea, or why you think that these observers get "the right answer" while my falling observer is somehow wrong.
The issue isn't whether it's real GR, ben, but whether the solution is real.Remember, Farsight, real GR can handle any observer, and can give consistent answers no matter what observer is chosen.
Don't give me laws, give me scientific evidence and logic. It's the law just won't do.The actual laws of GR include your rope-observer and his infinite blueshift, and your outside-observer and his nothing-has-fallen-in-yet redshift ... and it does so without contradicting, or ignoring, or devalueing, the experiences of my falling-straight-in observer
Point it out or repeat it and I'll knock it down like the rest of them....the one who, according to a calculation you have failed to criticize or notice or debunk in any way, goes through the horizon in a finite proper time and can do local speed-of-light measurements all the way down.
But in an infinite time according to my clock and your clock, and ET's clock. So she never crosses the horizon.ben m said:Not "yet" according to a clock at rest. She crosses the horizon in a finite time according to her own clock (and many other possible moving clocks).
And MTW is wrong. That's what this whole discussion is about. Your good book is wrong. Look at that lefthand chart and the chopped off infinity. A clock going infinitely slow along with an observer observing infinitely slow doesn't get you past the end of time. Hop skippity jump!ben m said:Dammit, Farsight, this is an explicit solution of GR. It's in Misner Thorne and Wheeler with all of the coordinates, algebra, etc. laid out.
Yes!ben m said:I gave you the exact equation of motion---what do you think I did, made that up by throwing darts at a keyboard? Is there an error in the MTW derivation? Did they make a bad starting assumption?
That moment hasn't come yet. Let's you and me wait a billion years, and that moment still hasn't come yet. It never comes.
She's sitting there in front of her light clock,
Those finite number of light bounces takes an infinite coordinate time to occur. They never happen.
The arrow's finite proper time is a fairytale.
No. She experiences what she'd experience if she was moving at c. She experiences nothing.
That moment hasn't come yet. Let's you and me wait a billion years, and that moment still hasn't come yet. It never comes. She's sitting there in front of her light clock, but light isn't moving in the clock, it isn't moving towards her eyes, and electromagnetic processes aren't moving in her instruments and in her brain.
Those finite number of light bounces takes an infinite coordinate time to occur. They never happen.
Lemaître said:In Section 11, we remove an apparent contradiction between Friedmann's theory and the solution of Schwarzschild's exterior problem. [...] We show that the singularity of the Schwarzschild exterior is an apparent singularity due to the fact that one has imposed a static solution and that it can be eliminated by a change of coordinates.
Lemaître said:We intend to prove that the singularity of the field is not real and arises simply because one wanted to use coordinates for which the field is static.
Lemaître said:The singularity of the Schwarzschild field is thus a fictitious singularity, analogous to that which appears at the horizon of the centre in the original form of the de Sitter universe.
Farsight hasn't done his homework. As shown in exercises 20 and 21, that division by zero occurs only when the metric is expressed in Schwarzschild coordinates. When exactly the same metric is expressed in Lemaître coordinates, there is no division by zero at the event horizon.When 2M/r = 1 at r = 2M you've got a division by zero in [latex]\[ \frac{dt}{d\tau} = \frac{e}{1-2M/r} \][/latex]. That's an undefined result, an infinity. But you just sail on past it. The finite proper time demands an infinite coordinate time, so it hasn't happened yet, and it never ever will.
Farsight hasn't done his homework, so he's using the wrong coordinate system here. As shown in exercise 23, Schwarzschild coordinates describe the situation as observed by an observer at infinity (or by an observer who's undergoing an outward acceleration that exactly counteracts the gravitational attraction of the black hole). As shown in exercise 22, Lemaître coordinates describe the situation as observed by the unfortunate woman who's free-falling into the black hole.That moment hasn't come yet. Let's you and me wait a billion years, and that moment still hasn't come yet. It never comes. She's sitting there in front of her light clock, but light isn't moving in the clock, it isn't moving towards her eyes, and electromagnetic processes aren't moving in her instruments and in her brain.
Farsight hasn't done his homework. As shown in exercises 20 and 21, the spacetime manifold extends beyond the open set on which Schwarzschild coordinates are defined. Had Farsight done his homework, he'd know Lemaître coordinates are finite and perfectly smooth at the event horizon, where Schwarzschild coordinates blow up because of a mere coordinate singularity.Not so. The moment never comes. The supposed time after that moment is time after the end of time. Come on sol, look at the lefthand chart on post 135. The chopped-off top goes up to infinity. There's no getting past it.
Farsight hasn't done his homework. Had he worked through the exercises, he'd know Lemaître coordinates describe exactly the same spacetime manifold whose outer portion is described by the Schwarzschild coordinates. He'd also know that Lemaître coordinates cover more of that manifold because they don't suffer from the coordinate singularity that limits Schwarzschild charts to the submanifold that lies outside the event horizon. Lemaître charts provide a perfectly smooth description that goes all the way down to the physical singularity at the heart of the black hole.Not so. I challenge the use of neverneverland coordinates in cloud-cuckoo land.
Farsight hasn't done his homework. He flat-out refused to work through a simple set of exercises that would have taught him a few basic facts about general relativity and the spacetime manifold surrounding a black hole.And MTW is wrong. That's what this whole discussion is about. Your good book is wrong. Look at that lefthand chart and the chopped off infinity. A clock going infinitely slow along with an observer observing infinitely slow doesn't get you past the end of time. Hop skippity jump!
We sit here watching our clocks and looking through our telescopes, and we adopt the thing we call a coordinate system for our measurements. I've just been out for a cigarette, and I looked up at the night sky. I saw stars. They exist. The space between them exists too, and we're sure enough that black holes exist too. But coordinate systems don't. Here we are 13.7 billion years after what appears to be the beginning of the universe, at 18:22 GMT on 11th February 2012, and she hasn't got there yet. Let's call her Alice. There is no situation or coordinate system in which she has got there yet.Yes, there are coordinate systems in which she never gets there. The coordinate system where you and I are sitting still watching our clocks? That's one of them. Einstein's GR includes that.
Whoa yourself. You said She crosses the horizon in a finite time according to her own clock, in post #156. I merely said She's sitting there in front of her light clock, so don't clutch at straws suggesting I forgot something. It doesn't matter what coordinate system you use, and regardless of transformations from one to another, you can't make Alice's collision event happen yet and not happen yet.Hey, whoa! That's a different clock, in a different location, moving at a different speed. Why did you take results from your clock and decide that they would be true on this one? You forgot to do the transformation.
No, but some of the things people ascribe to GR are.... according to some clocks, and not others. Why don't you use GR to do this frame transformation? Is GR wrong?
The point singularity in the middle of the black hole. It's always in the future.Sorry, Farsight, Einstein appears to disagree with you. I have a spacetime that Einstein says is valid, a coordinate system in that metric that Einstein's math says is valid, and an equation of motion following Einstein's prescription. Which part is the "fairytale"?
It doesn't. The interpretation of the maths goes wrong when people sweep an infinity under the carpet. Now where's that expression of yours?When else does Einstein's math go so far wrong? How did, e.g., Hulse and Taylor predict the pulsar spindown rate? They used Einstein's math, straight out of the box, without doing a separate, nonmathematical "fairytale check" using the Farsight ask-a-distant-observer-and-don't-transform method?
and regardless of transformations from one to another, you can't make Alice's collision event happen yet and not happen yet.
OK.I didn't ask about the moment she crosses the horizon. I asked about the moment just before (say, 1 microsecond as measured by her clock), which does take place even in the coordinates you insist on.
Agreed. But as she approaches the event horizon, she's subject to increasing gravitational time dilation. Her awareness is slowing down, and she doesn't notice it. She doesn't notice anything unusual as she stops noticing everything.You've agreed that our intrepid explorer will live up to that moment, and moreover will notice nothing whatsoever unusual. Not only will she not notice anything unusual, she won't be able to measure anything unusual, no matter how precise an experiment she does (again, apart from tidal forces - but even those don't necessarily tell her she's crossed a horizon). For her, up until that moment all clocks are ticking as usual, she's getting hungry at the usual rate, she can play tennis or a game of billiards as usual.
There's some issues with this, but let's come back to it another time.She can even open a porthole and look outside at the stars behind her - for a large black hole she'll see nothing unusual, just some displacement of their location due to lensing.
I told you that the motion of light ceases due to total vacuum impedance in post #159. Please don't try to suggest that I'm advancing wild hypotheses without scientific support. For your convenience I'll reiterate what I said:So here we have this experimenter, living normally, noticing nothing - and yet, according to you, at some random instant that she cannot possibly determine by any experiment, time just..... stops. One can't ask about any moment afterwards. You even assert that there is no moment afterwards. According to you, time literally comes to an end, with no warning and no physical mechanism.
It isn't manifestly wrong. Those coordinate systems are abstract mathematical artefacts. Black holes exist, space exists, light exists, gravitational fields exist. All these things are manifest. Coordinate systems are not.That's a totally absurd position on its face. (And let me point out again that it's also manifestly wrong, because any location in space is on the horizon in some set of coordinates.)
Please don't try to suggest that I'm advancing wild hypotheses without scientific support.
Those coordinate systems are abstract mathematical artefacts. Black holes exist, space exists, light exists, gravitational fields exist. All these things are manifest. Coordinate systems are not.
What's with the eleastic? See this article re gravitomagnetism.
I'm not, you are. I'm showing you the variable speed of light, you're refusing to look, preferring instead to wallow in mathematical abstraction and erudition and to believe that for a stopped observer a stopped clock carries on ticking. And please, spare me your not-qualified to judge pomposity. You have no counter-argument, and it shows.[W.D.Clinger said:Farsight's like the guy who's got his atlas open to a chart that shows only the 48 contiguous states, and is using that chart to deny the existence of Hawaii and Alaska. When we tell him the next page contains a chart of all 50 states plus Mexico and Canada, he refuses to look.
Look in the mirror, ben. You have no counterargument, remember?...As for Farsight, I think Upton Sinclair said the right thing. "It is difficult to get a man to understand something, when hissalaryego depends upon his not understanding it."
Look in the mirror, ben. You have no counterargument, remember?
What's with the eleastic? See this article re gravitomagnetism.
Look in the mirror, ben. You have no counterargument, remember?
Misner Thorne and Wheeler page 11 said:In summary, there is nothing strange about the geometry at the dotted line; all the singularity lies in the coordinate system ... no confusion should be permitted to arise from the accidental circumstance that the t coordinate attains an infinite value on the dotted line.
Stop talking about stopping time. Make the leap to stopping light. There's nothing bizarre or mysterious. Think back to the optical clocks losing synchronisation at different elevations, simplified to parallel-mirror light clocks.
|------------------|
|------------------|
One light beam is going slower than the other, and c = √(1/ε0μ0). The vacuum impedance of space Z0 = √(μ0/ε0) is increasing. Increase it so that it totally impedes the motion of light, and you stop light. Then nothing moves and clocks don't tick. Waves can't propagate through space any more. It's that simple.
No I'm not. I'm advocating the "frozen star" concept that dates back to Oppenheimer as mentioned here: http://arxiv.org/abs/1003.1359 . The author of this paper says "matter can indeed fall across the event horizon within a finite time" but disagreeing with that really isn't some wild hypothesis. Come on sol, you do yourself a disservice by trying to portray it as so.That's precisely what you are doing.
I'm not choosing any coordinate system, I'm pointing out the hard scientific evidence of optical clocks and giving a chain of logic saying the speed of light really does vary like Einstein said, and that light doesn't get out of that massive thing at the centre of the galaxy with stars swinging around it for a simple reason. You know full well that light going straight up from a black hole doesn't curve back down, just as light passing between two stars isn't curved. The light doesn't get out because it's stopped. You don't need a coordinate system to see the bleedin' obvious that leads you to this: parallel-mirror light clocks at different elevations lose synchronisation because the speed of light isn't constant. Not the coordinate speed of light isn't constant. You've got light moving between two mirrors, that's what's actually there, not the human convention of a non-inertial reference frame, and not time flowing. Just light, moving through the space between mirrors.That's exactly the point. Coordinate systems are human conventions, they have no bearing on reality. You can choose any coordinates you like - and it's only in the coordinate system you insist on always using that light slows down or time stops at the horizon. In an infinite number of other coordinate systems, all equally as valid as yours, nothing unusual happens at the horizon.
No I'm not. I'm advocating the "frozen star" concept that dates back to Oppenheimer as mentioned here: http://arxiv.org/abs/1003.1359 . The author of this paper says "matter can indeed fall across the event horizon within a finite time" but disagreeing with that really isn't some wild hypothesis. Come on sol, you do yourself a disservice by trying to portray it as so.
The total time of collapse for an observer comoving with the stellar matter is finite ... An external observer (O hereafter) sees the star
asymptotically shrinking to its gravitational radius.
Would you like to reiterate his pretty clear counter-argument? Didn't think so.It's pretty clear that he does, and I don't understand why you quote that bit rather than addressing it.
I can't detail it without going into electromagnetic four-potential and displacement current and the nature of the photon, and that would take a long time. Please start a thread if you want me to talk about it it. But meanwhile have at displacement current on wiki and note the Maxwell quotes where elastic is mentioned:Daylightstar said:I asked you to detail your 'elastic response', your claimed 'method' for space ('that black stuff between the stars') to sustain/hold/support waves and fields. If you'd be so kind, please do so now.
The author of this paper says "matter can indeed fall across the event horizon within a finite time" but disagreeing with that really isn't some wild hypothesis.
I'm not choosing any coordinate system
I'm not choosing any coordinate system, I'm pointing out the hard scientific evidence ... You've got light moving between two mirrors, that's what's actually there
No I'm not. I'm advocating the "frozen star" concept that dates back to Oppenheimer as mentioned here: http://arxiv.org/abs/1003.1359 . The author of this paper says "matter can indeed fall across the event horizon within a finite time" but disagreeing with that really isn't some wild hypothesis. Come on sol, you do yourself a disservice by trying to portray it as so.
Shuang-Nan Zhang said:...
Finally these questions are answered definitely and the above “frozen star” paradox is solved completely by Liu & Zhang[4]. As shown in Figs. 2 and 3 taken from Ref. 4, matter cannot accumulate outside RH, due to the increase of RH which swallows the matter falling in. The fundamental reason for the asymptotic behavior of a test particle is due to the negligence of the influence of the test particle to the global properties of the whole gravitating system, therefore RH would not change during the infalling process of the test particle. Therefore a BH can indeed be formed from gravitational collapse, and “frozen stars” cannot exist in the physical universe.
Yes, Farsight, it is a wild hypothesis to imagine that some parts of GR are correct except that this one particular coordinate-singularity is "real" and observer-independent. That's standard crackpot physics.
Yes I did and no it doesn't, because it says this:Did you read the paper? It quotes Oppenheimer himself agreeing with us and disagreeing with you.
Yeah yeah, I give you the frozen star and it's some wild hypothesis? And now crackpot physics? Sheesh, come on, hurl some more abuse at me. Call me feather-spitting names, as much as you like. It only makes it even more patently obvious that you've got no counter-argument whatsoever. LOL.ben m said:Yes, Farsight, it is a wild hypothesis to imagine that some parts of GR are correct except that this one particular coordinate-singularity is "real" and observer-independent. That's standard crackpot physics.
Is that all you're left with? That the frozen star disagrees with all established science? To hell with the light and the mirrors, to hell with my post #177, you're going to ignore the scientific evidence and start bleating about all established science. Sol, I am disappointed with you. I expected rather more. I expected a rational discussion, not evasion.Of course it is. It disagrees with all established science, including the very same science you claim to be using to reach your conclusion.
What part of I'm not choosing any coordinate system did you fail to understand? Coordinate systems don't exist, remember? Coordinate systems are human conventions, they have no bearing on reality. What's real is light moving through space. Or not moving through space.Then you should be happy with a choice of coordinates in which the coordinate speed of light does nothing unusual at the horizon.Farsight said:I'm not choosing any coordinate system
I'm sorry sol, but there are no "fundamental truths", and the general relativity you've been taught is a corrupted version of the real thing. Einstein told you the speed of light varied, and the scientific evidence is right there under your nose. Get used to it.But you're not, you refuse to accept that. Ergo, you're insisting on one specific coordinate system. That's precisely the contrary of the fundamental truth general relativity is based on - that choices of coordinates are meaningless and arbitrary.
Oh slings and arrows. I don't need a coordinate system to see two optical clocks losing synchronisation, I just look at the numbers. And I don't have to be the Brain of Britain to work out that the speed of light isn't constant, or come across Einstein telling everybody about it. Then when I hear people saying Einstein told us the speed of light is constant I can laugh and say, Ooh, lookie here, two racehorses running at the same speed:You're such a GR novice that you don't even notice when you're using a coordinate system.
Um, I did say The author of this paper says "matter can indeed fall across the event horizon within a finite time" but disagreeing with that really isn't some wild hypothesis..Um, the paper you linked to disagrees with you explicitly. From pp. 5-6:
“An external observer [O hereafter] sees the star asymptotically shrinking to its gravitational radius [the radius of the event horizon of the BH of the same mass, RH = 2GM/c2 hereafter.].” This means that O will never witness the formation of an astrophysical BH. Given the finite age of the universe and the fact that all observers are necessarily external, the last conclusion of Ref. 1 seems to indicate that astrophysical BHs cannot be formed in the physical universe through gravitational collapse.