doronshadmi
Penultimate Amazing
- Joined
- Mar 15, 2008
- Messages
- 13,320
Firstly, no, the elements stand for themselves, not other things. Secondly, what other options?
EDIT:
1) It is nothing by your decision.
2) Also by following your decision the following definition of powerset holds:
Let's improve again the more general definition of powersets,
A powerset P(S) is (a collection of 2^|S| distinguished elements, which are defined by collections with |S| distinguished elements, which share the same type of form with the distinguished elements of P(S)) OR (the elements of P(S) are constructed by the elements of a given S and the empty set is one of its distinct elements).
According to this definition cases like {0,6,@,!}{6,%} are avoided.
The second part of the more general definition (after the OR logical condition) is actually the traditional definition, but now the traditional definition is not the only option to define the concept of powerset.
Some examples are shown in http://www.internationalskeptics.com/forums/showpost.php?p=8165288&postcount=1069
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