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#201 |
Penultimate Amazing
Join Date: Mar 2008
Location: New Zealand
Posts: 28,521
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A vague or even concise philosophical reason cannot refute physics, TheAdversary.
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#202 |
Banned
Join Date: Jun 2013
Posts: 3,726
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Yeah...Yeah....bleah! Ok, You are right and Einstein and everyone else is wrong. Now, go publish a paper and pick up your Nobel Prize. Also, go invent a new Global Positioning System - one that doesn't rely on those bad 'ole relativistic equations. And tell the Chinese, Russians and Europeans that their Satellite Positioning Systems are screwed, too! You will be rich and famous. Girls with big boobs and shaply will throw themselves at you. Life will be good for you. |
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#203 | ||
ETcorngods survivor
Join Date: Dec 2005
Posts: 24,291
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A proud member of the Simpson 15+7, named in the suit, Simpson v. Zwinge, et al., and founder of the ET Corn Gods Survivors Group. "He's the greatest mod that never was!" -- Monketey Ghost |
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#204 |
Critical Thinker
Join Date: Apr 2007
Posts: 334
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Let us assume a closed water flow through four interconnected straight tubes forming a square. Each edge has a mirror so that light can change direction from one tube to the next, with a light path of each 3 m between two neighboring mirrors. With water at rest in the tubes, speed of light is c/n ≈ 2.25∙108 m/s relative to both the water and the laboratory (assumed at rest). After the water starts circulating at v = 1 m/s in direction of light propagation, the speed of the light relative to the laboratory will increase to only w = c/n + 0.44 m/s (instead of w = c/n + 1 m/s). This is an empirical fact confirmed by Fizeau's experiment. As the water moves at 1 m/s in the same direction as the light, from absolute simultaneity we conclude that relative to the water, light moves no longer with c/n but with w' = c/n + 0.44 m/s - 1 m/s = c/n - 0.56 m/s. Thus, we need relativity of simultaneity in order get again the original light speed w' = c/n relative to the water (instead of w' = c/n - 0.56 m/s): With respect to the water flowing on the closed light-path, time at each mirror in front must be Δt' = - 3m ∙ 1m/s / c2 = 3.34∙10-17 sec in the past with respect to the respective back mirror. Yet because the light comes back to the same mirror after having changed direction by means of the three other mirrors, each mirror should be four times 3.34∙10-17 sec in the past with respect to itself, which obviously is impossible.Every atom of both the moving water and the laboratory can be considered a clock. As the distances between all these clocks remain constant (apart from the 12 sec cycle of flowing water), we must apply absolute simultaneity. (Only if the distance between two clocks continuously decreases/ increases, relative simultaneity does not lead to contradictions, see also Simple Refutation of Special Relativity by Light Clock) Summary:
Cheers, Wolfgang Human faculty of reasoning is in principle much better adapted to the world we experience than modern science makes us believe. Dilemmas and paradoxes only point to an inadequacy of premises of our beliefs and theories, and not to an inadequacy of human reason itself. |
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#205 |
Penultimate Amazing
Join Date: Mar 2008
Location: New Zealand
Posts: 28,521
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Let us not ignore a post that does not refute special relativity, wogoga
![]() The Fizeau experiment
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23 November 2015 wogoga: The Fizeau experiment is explained by the relativistic formula for addition of velocities. Not that you will acknowledge a scientific fact: 29 October 2015 wogoga: Repeating a delusion about the Lorentz transformation not reducing to the Galilean transformation in the limit of v << c (or the classic limit of c goes to infinity) |
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#206 |
Graduate Poster
Join Date: Nov 2014
Posts: 1,413
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Maybe Wogoga is thinking about the dynamics rather than the kinematics. In other words, he is concerned about how the mechanical forces transform. The Lorentz transform for coordinates alone does reduce to the Galilean transform for coordinates alone when v<<c.
The Lorentz transform for coordinates alone is not sufficient to make a well posed physical theory. The forces have to be treated a certain way that depends on the dynamics in the theory. In Einstein's 1905 article, Einstein goes into the dynamics of relativity. Principia is useful only because Newton describes the dynamics of the Galilean transform. The important issue is how the mechanical forces vary with observer. To understand this in special relativity, you have to understand the concept of proper acceleration. So I could go for the following amendments. 1) The Lorentz transformation does not reduce to the Galilean transformation when |ax|>>c^2, where a is the proper acceleration and x is the distance from observer to observation point, even when |v|<<c. -If |ax|<<c^2, the mechanical forces don't transform properly even if v<<c. 2) The Lorentz transformation reduces to the Galilean transformation when both v<<c AND |ax|<<c^2, where v is the relative velocity between observer and observed, x is the distance from observer to observed and a is the proper acceleration. - If |ax|<<c^2 AND |v|<<c, one may as well use Galilean transforms. The All differences between Lorentz transforms and Galilean transforms are negligible under those two joint conditions. |
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#207 |
Graduate Poster
Join Date: Oct 2014
Posts: 1,952
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Please note that this is two different reference frames, not one, as the water is moving in two different directions. Also you got the sign wrong.
In the first water's reference frame, the first front mirror will be in the future compared to the first back mirror, and the second back mirror will be in the future compared to the second front mirror, with "past" and "future" both being in comparison to the laboratory frame. In the second water's reference frame, the second front mirror will be in the future compared to the second back mirror, and the first back mirror will be in the future compared to the first front mirror, again with "past" and "future" both being in comparison to the laboratory frame.
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Yet again, most supposed "refutations" of special relativity are simply mistakes in math or in application of the transformations. |
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#208 |
Critical Thinker
Join Date: Apr 2007
Posts: 334
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From Fizeau's experiment as King's evidence (for Lorentz transformation not reducing to Galilei transformation):
As to my concrete example I would rather say the water moves in four different vectored directions, e.g. positive x-direction, positive y-direction, negative x-direction, negative y-direction, positive x-direction, and so on. Despite having dealt dozens of times with such problems in this life alone, I get confused every time anew. In any case, at v = 1 m/s the Lorentz factor is a negligible second-order effect (less than 10-17). Thus we can dismiss length and time interval differences, i.e. we can assume Δx' = Δx and Δt' = Δt. A time shift Δt < 0 means past, and a time shift Δt' > 0 means future. And if on the one hand we have "past" in front and "future" behind, then on another hand we have "future" in front and "past" behind. If the water (frame F') moves in positive x-direction in the laboratory (frame F) with v = 1 m/s, we get: Δx' = Δx – v Δt = Δx – 1 m/s ΔtThe 1.11∙10-17 s/m are not negligible because time intervals we are dealing with (i.e. propagation of light) are in the order of only Δx / c = 3 m / c = 10-8 (see also). Let us assume four observer-particles in the flowing water (in meter):
No. The effects do not reverse, they add up. Between particle 1 at x = 0 and particle 2 at x = 3 m, we have v = 1 m/s and Δx = Δx' = 3 m. On the way back between particle 3 at x = 3 and particle 4 at x = 0, we have v = –1 m/s and Δx = Δx' = –3 m. Thus –v/c2 Δx remains negative. For better understanding see:Cheers, Wolfgang |
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#209 |
Penultimate Amazing
Join Date: Mar 2008
Location: New Zealand
Posts: 28,521
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Linking to stupidity is not good, wogoga. Anyone with high school level mathematics knows that the Lorentz transformation reduces to the Galilei transformation when v << c.
Then there is abysmal ignorance about the Fizeau experiment which was not a test of whether Lorentz transformation reduces to the Galilei transformation for the simple reason that Fizeau did it in 1851 ![]() The Fizeau experiment is evidence for SR
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The links in the bottom of your post allow us to better understand your ignorance about SR, physics and and mathematics.
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#210 |
Critical Thinker
Join Date: Apr 2007
Posts: 334
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I have revised the link Simple Refutation of Special Relativity by Light Clock. Here three extracts: Fig. 1: On the left, two light-clocks circling horizontally a common center with each speed v = 0.9 c relative to the opposite clock. On the right, the vertical light-speed signals within both clocks with respect to the red clock assumed at rest. Light-speed c within and for the blue clock seems for the red clock only u = c /γ with Lorentz factor y= 0.44, due to time-slowing of the blue clock. Vector addition of vectored u und v then results in signal speed c =√(v2 + u2). Thus for the red clock during 1 sec, only 0.44 sec of the blue clock elapse. Fig. 2: Leap in time from t' = 5 to t' = 995 of the blue light-clock with respect to the red clock at t = 500. Summary: In the case of hexagonal movement, constancy of light-speed is possible for both light-clocks during straight movement, because mutual time slowing is possible. Yet every change in direction leads to a time-leap-into-the-future of the opposite clock. The combination of continuous time slowing and discontinuous time-leaps leads on average to t' = t. In the case of circular movement, time slowing of the opposite clock is continuously compensated by a continuous drift into the future due to continuous own direction-changes. This is in agreement with the requirement of symmetry between t and t', but it obviously violates constancy of light-speed for both light-clocks. Special Relativity became thriving because it explains light-speed constancy on Earth, despite the Earth's orbit around the Sun at v = 0.0001 c (e.g. Michelson and Morley's experiment). The SR explanation is essentially based on the light-clock reasoning. If the latter cannot explain light-speed constancy for both Earth and Sun, then SR is simply wrong, despite being based on effective and prolific scientific hypotheses. This reasoning so clear and simple that "skeptics" should not whine that it must be crackpottery since it contradicts all they devoutly believe in: orthodoxy, authority and mainstream. Cheers, Wolfgang |
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#212 |
Critical Thinker
Join Date: Apr 2007
Posts: 334
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People feigning or honestly trying to rescue Special Relativity from logical contradictions by claiming its inapplicability in case of accelerated movements are completely inconsequential and have no idea about the history of physics. The most important prediction resp. explanation of SR was just: Light-speed constancy in all directions despite the Earth's orbit around the Sun at v = 30 km/s = 4p3 m/s. Inertial frames do not exist, nowhere in the Universe. Only accelerated movements do exist, such as e.g. the movement of a laboratory on Earth. Thus, if Special Relativity is only valid in the absence of accelerations, then the theory's range of validity is practically zero in the real world! The movement of a laboratory near the equator consists of at least three accelerated movements:
Unfortunately these two crucial experiments have not been repeated. Instead, the next generation of "light-speed isotropy" experiments has been designed in such a way that a light-speed anisotropy due to the diurnal rotation cannot show up and spoil the desired result of an "isotropy" (constancy in all directions) as high as possible. Also possible isotropy-deviations due to our movement relative to the sun are removed right at the outset of such experiments (mostly by averaging techniques). And the huge light-speed anisotropy which must occur on the International Space Station (light-speed ranging from around c – 7.5 km/s ≈ 8p3 m/s – 3p75 m/s to c + 7.5 km/s ≈ 8p3 m/s + 3p75 m/s) has never been examined, or is kept quiet, or assumed an unimportant Sagnac effect. In order to make the problem of my previous post #210 even more explicit and vivid, let us imagine two spacecrafts each moving at v = 0.995 c = 9n995 c (with Lorentz-factor γ = 10) towards Meeting point: The red spacecraft moves on a circular orbit around Rotation center (in the absence of gravitation). The blue spacecraft moves on a straight line in such a way that the two spacecrafts will be side by side at Meeting point. According to the by far most widespread interpretation of SR (already advocated by Einstein 1905), a clock at Rotation center must run fast by factor 10 with respect to the circling spacecraft. Yet with respect to the blue spacecraft, the same clock at Rotation center goes slowly by factor 10. Yet on the other hand, since both spacecrafts are side by side and move in the same direction, clock rate at Rotation center must be the same with respect to both spacecrafts and cannot differ by factor 100 = γ2. Cheers, Wolfgang (a confident pandualist, crackpot physicist and conspiracy theorist) Fundamental scientific progress works by restructuring previous knowledge and not by incremental addition of new findings and theories |
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#213 |
Penultimate Amazing
Join Date: Mar 2008
Location: New Zealand
Posts: 28,521
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25 August 2016 wogoga: Insulting people who understand SR does not hide your ignorance about SR which has no logical contradictions.
No one claims that "perfectly" inertial frames of reference exist in the physical universe. The inertial frames of reference in SR are more physically accelerating frames of reverence where the acceleration is negligible. The scientific theory of SR that has been and enormously verified by experiments treats these as inertial frames of reference ![]() For example, SR is applicable and tested to a high degree of accuracy everywhere on the surface of the Earth even in the presence of Earth's gravitational field. For example, an SR formula of E=mc2 applies throughout the observable universe where we see stars functioning through fusion ![]() 25 August 2016 wogoga: Idiotic examples that are not about SR do show SR is wrong, e.g. objects in orbits. It is stupid to put the red spacecraft in a circular orbit with or without gravitation because the red spacecraft is then accelerating! 25 August 2016 wogoga: The delusion that "reference frames for light-speed are dragged by the Earth's mass". Photons do not have frames of reference - observers have frames of reference. You cited the Michelson–Gale–Pearson experiment which measured the Sagnac effect due to the Earth's rotation.
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"Brillet and Hall, 1978" is not a citation. A. Brillet and J.L. Hall, “Improved Laser Test of the Isotropy of Space”, Phys. Rev. Lett. 42 549–552 (1979) did not confirm the Sagnac effect - the residual signal was probably misalignment
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Modern searches for Lorentz violation
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23 November 2015 wogoga: The Fizeau experiment is explained by the relativistic formula for addition of velocities. 8 August 2016 wogoga: A "derivation" of the Lorentz transformation that rather idiotically does not derive the Lorentz transformation! 8 August 2016 wogoga: A totally ignorant "refutation" of SR based on personal incredibility or ignorance. 8 August 2016 wogoga: A web page that starts with a lie in the title ("Why Special Relativity does not explain Michelson and Morley's experiment") 8 August 2016 wogoga: A web page that starts with really bad ignorance of SR in the first sentence (the Lorentz factor only includes speed, not velocity). 15 August 2016 wogoga: "Simple Refutation of Special Relativity by Light Clock" is still a lie based on ignorance. |
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#214 |
Critical Thinker
Join Date: Apr 2007
Posts: 334
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In pre-relativistic physics, photons (resp. electromagnetic waves) had reference frames in the same way as sound has. In case of sound, the relevant reference frame is the movement of the sound propagation medium (e.g. air in a closed bus). Since an alternative theory is not constrained by the premises of Relativity, such a theory can again be based in this respect on classical physics, where electromagnetic radiation has such a reference-frame in the form of a propagation-medium resp. ether. Photons always move within gravitational fields and potentials of masses affecting the photons (e.g. leading to gravitational redshift and to deflection). The hypothesis that in line with Mach's principle these fields created by masses also provide or represent the medium for photon propagation is reasonable. The hypothesis simply means that all particles gravitationally attracting a photon also drag resp. tie the photon to themselves. The result is that the photons move at c relative to an averaged gravitational field. The stronger a gravitational effect on a photon, the stronger the photon is bound (dragged, entrained) by the mass causing this effect. The gravitational field caused by the Earth is zero at its center. However frame-dragging, i.e. the effect on photon-propagation velocity is maximal at the mass center (despite also being a 1/r2 effect). A gravitational attraction from the left on the center is nullified by analogous attraction from the right. Yet both left and right side drag resp. tie the photon-reference-frame to the movement of the Earth, so the effects add up. See also: Ether Drift Experiments & Aberration & Relationality vs. Relativity Cheers, Wolfgang "Einstein once hoped that Relativity would become the strict relationist theory Mach had called for." (Source) |
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#215 |
Graduate Poster
Join Date: Nov 2014
Posts: 1,413
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What you just said wis completely consistent with General Relativity. You left something out, though.
The effect of the gravitational potential accumulates, not the affect of the gravitational field. The gravitational field cancels out at the center of the earth. However, the gravitational potential is at a maximum. The same idea applies both the Newtonian gravitation and Einstein gravitation. The gravitational potential caused by different masses add up in the same direction. Hence, the gravitational potential accumulates. A difference between Newtonian and Einsteinian gravitation lies in the type of field. In Newtonian gravitation, gravity is represented by a vector field. In Einsteinian gravitation, the gravity is represented by a tensor field. In both theories, the gravitational potential is derived from both types of field. Mach's Principle implies that inertia is associated with some type of frame dragging. So it is the gravitational potential relative to the observer that determines the observed speed of light. General relativity uses a 'weak' form of Mach's Principle. There are other theories that use a 'stronger' version of Mach's Principle. What you said is consistent with both the weak and strong versions of Mach's Principle. Your last post just barely made sense. I hypothesize that this is a temporary situation, whose time span is limited by Heisenberg's Uncertainty Principle. You were unclear as to the difference between field and potential, so what you said about frame dragging was clear. Your clarity won't be repeated for a while. Talk about quantum fluctuations! |
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#216 |
Penultimate Amazing
Join Date: Mar 2008
Location: New Zealand
Posts: 28,521
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Which is nothing to do with my post about basic modern physics, wogoga. I am sure that you will agree that it would be stupid to throw away centuries of physic s
![]() The basic modern physics is that treating electromagnetic waves like sound waves, i.e. propagating in a medium, does not work. This was suspected as soon as it was proposed because that medium (the luminiferous aether) would have contradictory properties. The Mickelson-Morley experiments in 1886 were the nail in the coffin of a luminiferous aether. For all physics (relativistic and pre-relativistic) it is observers who have frames of reference. We can have an observer travelling with a photon but this has no physical relevance, e.g. they always measure no time between events and so for them velocities are undefined. The web page Ether Drift Experiments & Aberration & Relationality vs. Relativity basically lies.
There is also the bad act of ignoring current research. That web page seems to date from 1999 but in 1997 a more accurate "Brillet and Hall" type experiment was done:
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29 October 2015 wogoga: Repeating a delusion about the Lorentz transformation not reducing to the Galilean transformation in the limit of v << c (or the classic limit of c goes to infinity) 23 November 2015 wogoga: The Fizeau experiment is explained by the relativistic formula for addition of velocities. 8 August 2016 wogoga: A "derivation" of the Lorentz transformation that rather idiotically does not derive the Lorentz transformation! 8 August 2016 wogoga: A totally ignorant "refutation" of SR based on personal incredibility or ignorance. 8 August 2016 wogoga: A web page that starts with a lie in the title ("Why Special Relativity does not explain Michelson and Morley's experiment") 8 August 2016 wogoga: A web page that starts with really bad ignorance of SR in the first sentence (the Lorentz factor only includes speed, not velocity). 15 August 2016 wogoga: "Simple Refutation of Special Relativity by Light Clock" is still a lie based on ignorance. 25 August 2016 wogoga: Insulting people who understand SR does not hide your ignorance about SR which has no logical contradictions. 25 August 2016 wogoga: Examples that are not about SR do show SR is wrong, e.g. objects in orbits. 25 August 2016 wogoga: The gibberish that "reference frames for light-speed are dragged by the Earth's mass" (photons are not observers). 25 August 2016 wogoga: A lie about light-speed isotropy experiments being designed to avoid "diurnal rotation", i.e. faked! |
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#217 |
Graduate Poster
Join Date: Nov 2014
Posts: 1,413
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No. This is wrong. You conflated partial derivative for full derivatives.
∂t'/∂v = -x/c2In order to calculate the full derivative, you would have had to expand the derivative of the product of x and v. The result would have had a proper acceleration (a=dv/dt) in it. This is where the mechanical force comes into special relativity. The mechanical force is defined by F=γm(dv/dt) where m is the rest mass. I was arguing with Wogoga in an 'Antirelativity Forum' when I realized they did not know the difference between a partial derivative and a full derivative. I vaguely remembered arguing with him overSo I reviewed some of my previous posts to see who else made such a mistake. No one else in the 'Antirelativity Forum' seemed to know the difference between a partial derivative and a full derivative. No one else acknowledged that Wogoga made a mistake. So I present this to the Skeptics Forum. Does dt'/dv = -x/c2or ∂t'/∂v = -x/c2or both? ![]() |
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#218 |
Illuminator
Join Date: Jul 2008
Posts: 4,852
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Quote:
t' = γ(t - vx/c^2) If so, neither is the correct derivative since v appears in γ. In any case, since X is also a variable, I would suggest a partial derivative is more appropriate. |
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It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong. - Richard P. Feynman ξ |
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#219 |
Philosopher
Join Date: Oct 2009
Posts: 5,515
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It sounds as though their main problem is ignorance of the chain rule.
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#220 |
Illuminator
Join Date: Jul 2008
Posts: 4,852
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It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong. - Richard P. Feynman ξ |
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#221 |
Graduate Poster
Join Date: Nov 2014
Posts: 1,413
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Yes. You are right and I was wrong. Neither can be correct.
Yes again. You are right and Wogoga was wrong.The partial derivative is more appropriate in this case. Wogoga used a full derivative where he should have used a partial derivative. BTW: I may have been wrong in another way. I am not sure that Wogoga posted on the Antirelativity Forum. I may have gotten him and Cryptic mixed up. |
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#222 |
Illuminator
Join Date: Jul 2008
Posts: 4,852
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__________________
It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong. - Richard P. Feynman ξ |
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