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Old 30th May 2023, 02:51 PM   #3521
MarkCorrigan
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Originally Posted by junkshop View Post
You may have misidentified the element of this thread that some see as a joke.
This is the person who accused several others of making callous jokes about the dead when no such thing happened though.
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Old 30th May 2023, 10:29 PM   #3522
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Originally Posted by JayUtah View Post
Generally, any deck angle greater than 20° defeats ordinary locomotion. You shift into a different kind of movement that's slower and more awkward.
As a kid, my favorite attraction at an amusement park was the tunnel that was a spinning tube. Hours of fun though I had many bruises afterword. I can't imagine what the passengers went through in those final minutes, but the idea that the command crew not making it out is a mystery, is laughable. If anything, it means they were trying to do their jobs.
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Old 31st May 2023, 05:21 AM   #3523
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Originally Posted by Steve View Post
But what about the conspiracies? sabotage? murders? nukes? disappeared crew? Surely they must all be mentioned prominently?
Originally Posted by Axxman300 View Post
How many Volvos did she see?
And Volvos. Volvo is Latin for I roll. Suspicious.

Finally made it to the end of the threads!
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Old 31st May 2023, 06:01 AM   #3524
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Originally Posted by The Common Potato View Post
And Volvos. Volvo is Latin for I roll. Suspicious.

Finally made it to the end of the threads!

Welcome to the end of the threads!
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Old 31st May 2023, 06:31 AM   #3525
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Originally Posted by The Common Potato View Post
And Volvos. Volvo is Latin for I roll. Suspicious.

Finally made it to the end of the threads!
Originally Posted by Mojo View Post
Welcome to the end of the threads!
The thread never ends. Unless Vixen actually sticks to "I am out".
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Old 31st May 2023, 06:33 AM   #3526
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Originally Posted by Steve View Post
The thread never ends. Unless Vixen actually sticks to "I am out".
Until tomorrow, then, at least.
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Last edited by junkshop; 31st May 2023 at 06:33 AM. Reason: Typo
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Old 31st May 2023, 07:21 AM   #3527
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Originally Posted by junkshop View Post
Until tomorrow, then, at least.
I think that's a pretty safe bet

http://www.internationalskeptics.com...0#post14084030
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Old 31st May 2023, 09:48 AM   #3528
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Mod WarningThe following post was created using a generative AI system but was not labelled as such as per Rule 4. Unfortunately we do not know which one nor the prompt used, when we do I'll update this post.
Responding to this modbox in thread will be off topic Posted By:Darat
Originally Posted by Vixen View Post
Are you sure about that?


To determine the force exerted when a ship hits the seabed, we need to consider the concept of pressure. Pressure is defined as force per unit area. We can calculate the force exerted by the ship using the formula:

Force = Pressure × Area

Given that the ship hits the seabed at a depth of 80 meters, we need to calculate the pressure at that depth. The pressure in a fluid increases with depth due to the weight of the fluid above. The pressure at a specific depth can be calculated using the formula:

Pressure = Density × Gravitational acceleration × Depth

The density of seawater is typically around 1,025 kilograms per cubic meter, and the gravitational acceleration is approximately 9.8 meters per second squared.

Let's calculate the force exerted by the ship:

Pressure = Density × Gravitational acceleration × Depth
= 1,025 kg/m³ × 9.8 m/s² × 80 m
≈ 803,600 Pa (Pascals)

Next, we need to determine the area over which the force is distributed. Without additional information about the shape or size of the ship's contact area, it is difficult to provide an exact value. However, we can assume a simple approximation that the area of contact is the same as the ship's bottom surface area.

Let's say the ship has a bottom surface area of 1000 square meters (just for illustration purposes).

Force = Pressure × Area
= 803,600 Pa × 1000 m²
= 803,600,000 N (Newtons)

Therefore, if the ship weighs 15,000 tonnes and hits the seabed at a depth of 80 meters, it exerts an approximate force of 803,600,000 Newtons (or 803.6 meganewtons) on the seabed. Please note that these calculations are based on estimations and assumptions, and the actual force may vary depending on the ship's design and the specific circumstances of the impact.
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