Moderated Iron sun with Aether batteries...

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I looked at every single image you liked to. All of them. The photosphere is not visible at all in any of those images.

Are you sure?. Its this page right here.
http://www.nasa.gov/centers/marshall/news/news/releases/2010/10-052.html

And then from the corresponding paper.

"The Solar Optical Telescope (SOT) of Hinode (Tsuneta et al. 2008; Suematsu et al. 2008; Shimizu et al. 2008; Ichimoto et al. 2008) makes observations in white light. Its broadband filter imager (BFI) take images in red (668.40 nm, width 0.4 nm), green (555.05 nm, width 0.4 nm) and blue (450.45 nm, width 0.4 nm) continuum ranges. Radiation at these – 3 – wavelengths comes from the photosphere and hence reflects the broadband continuum emission well. However, SOT normally obtains only infrequent images in these filters. More frequently, SOT takes images in the G-band (430.50 nm, width 0.83 nm), formed mainly from CH line opacity. Carlsson et al. (2007) show contribution functions for these filters; the G-band has a photospheric and an upper-photospheric contribution. It therefore serves well to define the morphology of white-light flares and it was also used in the Yohkoh observations (Hudson et al. 1992; Matthews et al. 2003)."
http://arxiv.org/PS_cache/arxiv/pdf/1004/1004.4259v1.pdf

Not every flare has x-rays during the white light flare. Because of the wavelength that HINODE sees at, we know the location of the white light flares which take place on the "ghost limb". We know that the uncertainty is big enough to say that the white light flare could be happening under the photosphere. HINODE cannot place them with only a z observation. You need a limb observation.

The offset is 2 arcseconds not 2 degrees; I already corrected you on this once before (The Solar "Ghost Limb" Is An Optical Artifact IV).

Yep. I keep meaning to say arcseconds.

If the ghost limb is a ghosting of the 1500A band then it is an event taking place at 1500A below the transition layer bleeding into the 1216A channel.
If it is ghosting from the 2 degree wedge in the filter then its either from the upper limb or lower limb. Combine the 2 to get both effects..
Then the only issue with that is the the arc of the curve does not look like its from the transition layer or the true limb (solar surface). And it cant be the transition layer because thats ~192A.
But assuming that it is, if you correct down it is the solar surface, if you correct up then it is the transition layer.
HINODE says its below the transition layer if you consider all these events to be white light flares. So does TRACE at 1216A.
HINODE places such events lower in the solar atmosphere than TRACE does.
A white light flares by definition takes place in the area of the solar atmosphere where that wavelength is visible in "white light".

Right now it appears that the white light flares are very close to photosphere.
I have already said that the footprints of the loops should be visible in white light like an arc lamp. And once we have the ability to place the events on the limb with enough resolution we will see where they are; above or below the photosphere.
 
[...] And once we have the ability to place the events on the limb with enough resolution we will see where they are; above or below the photosphere.


You cannot see below the photosphere. The photosphere is, by definition, the region where the Sun's atmosphere goes from being transparent to being opaque. Is there some particular argument you're trying to form by insisting on being wrong about this simple issue?
 
The Solar "Ghost Limb" Is An Optical Artifact VIII

I looked at every single image you liked to. All of them. The photosphere is not visible at all in any of those images.
Are you sure? ...
On second look, no. I only noticed the TRACE images at the bottom of your post ...
Below Photosphere
Again this is the image from TRACE is the loops on the solar surface below the photosphere. Notice the footprints of the loops. Notice the longitudinal features under the loops!!
http://trace.lmsal.com/POD/images/arcade_9_nov_2000.gif
http://trace.lmsal.com/POD/TRACEpodarchive6.html
More interesting images.
http://trace.lmsal.com/POD/images/T171_000404_183228.gif
http://trace.lmsal.com/POD/images/T171_000317_114103.gif
Of course the TRACE images do not see the photosphere. And equally "of course" the Hinode images do see the photosphere. My mistake, but one might still ask, so what? Why does it matter? You said, for instance, ...
In this image here it shows how the white light flare kernel is correlated with the center of a sun spot. Yep.
But all flares are correlated with sunspots, that is already well known. So what is your point supposed to be? That flares start below the photosphere? But we already know that flares commonly start below the photosphere in episodes of magnetic reconnection, so you are still not making any new point.

I have no idea at this stage of the discussion what point you are trying to make. What is it?

However, I do believe that you are still making the serious mistake of thinking that the ghost limb is some kind of real limb on the sun, when it is in fact and entirely, without question, beyond any shadow of a doubt, an optical artifact. I made that clear in my last post (The Solar "Ghost Limb" Is An Optical Artifact VII) and I note that you did not respond at all.

So, tell us, do you or do you not agree that the ghost limb is an artifact?

Do you claim that we can see below the photosphere? If so, at what wavelengths, and how is it physically possible?
 
There was an interesting article on the BBC about the Planck telescope. While the physics is off topic for this thread, there's a particularly relevant comment from one of the researchers involved:
However, such has been the anticipation for Planck data that one or two groups have already tried to make unauthorised interpretations simply from the images released to the media like the one on this page.

But Dr Tauber says this activity is pointless.

"The CMB is certainly visible but the image itself is colour-enhanced so you couldn't do any science with that," he explained.

"We have also reduced the resolution of the image to something which is more manageable for people to look at. Otherwise it would just be too big."
 
There was an interesting article on the BBC about the Planck telescope. While the physics is off topic for this thread, there's a particularly relevant comment from one of the researchers involved:
Quote:
However, such has been the anticipation for Planck data that one or two groups have already tried to make unauthorised interpretations simply from the images released to the media like the one on this page.

But Dr Tauber says this activity is pointless.

"The CMB is certainly visible but the image itself is colour-enhanced so you couldn't do any science with that," he explained.

Unfortunately, I have no doubt that within the next day or so, someone will be posting on the JREF Forum claiming that this image proves, once and for all, that (select all that apply)
- the speed of light has been decreasing over time
- the big bang never happened
- there was no inflation
- general relativity is wrong
- special relativity is wrong
- there is no such thing as dark matter
- there is no such thing as dark energy
- redshift is not due to the Doppler effect
- Earth is at a 'special' location in the universe
- stars are powered by electric currents
- galaxies are held together by magnetic fields
- GRB sources are within our galaxy
- life on Earth originated elsewhere
- the rest of the universe is uninhabited
- the universe was tailored for life by an external intelligence
 
You cannot see below the photosphere. The photosphere is, by definition, the region where the Sun's atmosphere goes from being transparent to being opaque. Is there some particular argument you're trying to form by insisting on being wrong about this simple issue?

In my model of the sun you can see below the cathode glow, which is equivalent in position in the solar atmosphere to your photosphere..
 
On second look, no. I only noticed the TRACE images at the bottom of your post ...

Of course the TRACE images do not see the photosphere. And equally "of course" the Hinode images do see the photosphere. My mistake, but one might still ask, so what? Why does it matter? You said, for instance, ...

But all flares are correlated with sunspots, that is already well known. So what is your point supposed to be? That flares start below the photosphere? But we already know that flares commonly start below the photosphere in episodes of magnetic reconnection, so you are still not making any new point.

I have no idea at this stage of the discussion what point you are trying to make. What is it?

However, I do believe that you are still making the serious mistake of thinking that the ghost limb is some kind of real limb on the sun, when it is in fact and entirely, without question, beyond any shadow of a doubt, an optical artifact. I made that clear in my last post (The Solar "Ghost Limb" Is An Optical Artifact VII) and I note that you did not respond at all.

There was an optical artifact that appears in the telescope. This optical artifact appears between the transition layer and the photosphere and this position is called the Ghost Limb whether it is on the sun or in the scope...

Handy says that they corrected for it but "What is left evidently must be some form of limb brightening".
So your saying that they did not know what they were talking about. And you implying that they could not correct for it and return an empirical value. Because we just agreed that limb brightening takes place on the sun and not in the telescope..

I dont believe they made a mistake.

Now if TRACE is seeing white light flares in the wrong position(due to wedge as you are claiming that they could not remove the artifact completely) then TRACE is seeing under the photosphere with the image shifted up at 1216, which by the way coincides with the reported temperature of ~9400K degrees..

So, tell us, do you or do you not agree that the ghost limb is an artifact?

I would have thought you would have said that they made the correction and that the ghost limb is where it is.

If you want to say that the artifact that was removed can be called the ghost limb. But it clear that there is a limb at that position in between the transition layer and the photosphere that TRACE sees at 1216A. And on that limb in another paper there is an event that is time correlated with a flare that takes place in the transition layer. And those people say that it takes place on Handys Ghost limb. So is it a place or an artifact. If its a place then it is located below the transition layer.
If it is an artifact, it is a real event(associated with another real event at another wavelength) at the wrong position due to an incorrect correction..

If those white light flares that TRACE sees are taking place under the photosphere according to HINODE, then we know the correction is wrong and TRACE is seeing under the photosphere at 1216A.

Do you claim that we can see below the photosphere? If so, at what wavelengths, and how is it physically possible?

Using your model it is not possible.

I dont know if its intensity of source, density of photosphere or the composition of the photosphere but at 192 I'm sure it is under the photosphere. Look at the structures underneath the loops.
That is supposed to be a plasma. NOT!
Under the photosphere.
http://trace.lmsal.com/POD/images/arcade_9_nov_2000.gif
 
In my model of the sun you can see below the cathode glow, which is equivalent in position in the solar atmosphere to your photosphere..
The first problem is that your model of the sun is physically impossible as has been pointed out many times before.
This was usually refering to Micheal Mozina's equally impossible "iron sun" model but if you want we could just repost the simple physics involved with "brantc's iron sun model" substituted. I think that would need a moderator to adjudicate whether that is appropriate.

Alternately you could just read the posts:
We could stop there but...


The second problem is that the photosphere does not emit a cathode glow ("The luminous glow that covers all or part of the cathode in a glow-discharge cold-cathode tube").
  1. The photosphere emits a roughly blackbody spectrum with an effective temeratire of ~6000K. This rules out any solid surface (even if it is made of iron). So there is no solid cathode possible.
  2. You have not provided any evidence that there is a cathode glow from a plasma like the photosphere.
The third problem is that you are still ignoring the actual defintion of the photosphere:
You cannot see below the photosphere. The photosphere is, by definition, the region where the Sun's atmosphere goes from being transparent to being opaque. Is there some particular argument you're trying to form by insisting on being wrong about this simple issue?


To make it clearer:
  • We cannot see more deeply than a few hundred kilometers into the photosphere due to its optical depth.
  • This is also a defintion of the thickness of the photosphere, i.e. the bottom of the photosphere is the deepest that we can see into the sun.
  • Thus by definition we cannot see below the photosphere.
So even if you could show that there is a cathode glow, it would still be emitted from the photosphere, not from below it.
 
I dont know if its intensity of source, density of photosphere or the composition of the photosphere but at 192 I'm sure it is under the photosphere. Look at the structures underneath the loops.
That is supposed to be a plasma. NOT!
Under the photosphere.
http://trace.lmsal.com/POD/images/arcade_9_nov_2000.gif
A plasma YES!
Under the photosphere NOT!

Read the facts about the photosphere and understand that its definition is that it is where the light escapes the sun. By definition you cannot see under it.

Most of the TRACE filters are selected to detect light from the transition region and corona. In case you have forgotten or never known what TRACE stands for it is "Transition Region and Coronal Explorer".

Look at the "192" passband:
Trace passbands

http://trace.lmsal.com/TRACE/Images/pastext.gif

Edited by LashL: 
Removed hotlinked image. Please see Rule 5.



If you mean the 195A passband (perhaps you should give a link to the location where the image is described) then this is plasma at a temperature of 500,000K to 2,000,000K. That is not the photosphere.

But if you want the region below the photosphere to be at 500,000K to 2,000,000K and make your iron sun idea even more impossible than it already is at temperatures of > 9400K then who am I to deny you :)

It seems as if you are doing the same thing as Micheal Mozina - looking at the images without bothering to learn what they are showing.
 
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In my model of the sun you can see below the cathode glow, which is equivalent in position in the solar atmosphere to your photosphere..


But there is no evidence to suggest that your model of the Sun is any more than a fantasy. None. And there is an abundance of evidence, from several very well developed areas of science such as general relativity, helioseismology, and thermodynamics, to support the notion that your model is wrong. And not just maybe wrong or a little bit wrong, but utterly, completely, and impossibly wrong. And the only way you can continue to argue for your fictionalized version of the Sun's construction is by blindly ignoring virtually all legitimate solar research done for at least the past half century, your rather transparent attempts at cherry picking and distorting bits and pieces of it notwithstanding.
 
The Solar "Ghost Limb" Is An Optical Artifact IX

There was an optical artifact that appears in the telescope. This optical artifact appears between the transition layer and the photosphere and this position is called the Ghost Limb whether it is on the sun or in the scope ...
OK. So you agree that the "ghost limb" is an optical artifact.

Handy says that they corrected for it but "What is left evidently must be some form of limb brightening".
No, that is not what Handy, et al., say. What they say is this: "The correction mechanism described in this paper is able to remove part of the ghosted limb, but it is evident that corrected limb images are still not right. What is left is evidently some form of limb brightening that is not corrected by this method." (Handy, et al., 1999, page 360; this is the full text of the entire top paragraph on that page). You left off the first sentence, and cut the second one in half, putting a period at the end, as if that's where Handy, et al., actually stopped. You present a misleading view of what the paper actually says.

So your saying that they did not know what they were talking about. And you implying that they could not correct for it and return an empirical value.
In light of my statement above, this is all entirely wrong. I am simply repeating what the authors say. It is their correction algorithm, and it is their statement that it is incomplete. They should know better than either of us.

Now if TRACE is seeing white light flares in the wrong position (due to wedge as you are claiming that they could not remove the artifact completely) then TRACE is seeing under the photosphere with the image shifted up at 1216, which by the way coincides with the reported temperature of ~9400K degrees ..
Very wrong. You are making the same mistake Mozina made, which resulted in an extensive discussion of what should be obvious: The sun is not a 2-dimensional cross-section of itself. It is a fully 3-dimensional object (roughly spherical to first approximation). As seen from Earth, the chromosphere sits atop the transition region, which in turn sits atop the photosphere. This means that as seen from Earth, every physically possible line of sight will always intercept the chromosphere first, then the transition region, then the photosphere, except at the extreme limb, where your line of sight might pass above one or more of the lower layers.

So what actually happens is that the image of the sun at roughly 1550Å is shifted by 2 arcseconds relative to the image at 1216Å. The image at 1216Å is the desired H-alpha narrow-line emission, while the shifted image at roughly 1550Å is a broad band image that consists of UV continuum mixed with CIV line emission. The latter can be corrected for with some precision, but the former is not predictable so it cannot be corrected for with equal precision (see, e.g., Handy, et al., 1999, page 353). This is why, as the authors themselves say (not me), their algorithm does not fully correct the ghost limb.

Now, the TRACE image will never see under the photosphere. The ghost limb is a UV image of the layers above the photosphere (the sun is 3-dimensional), shifted upwards by 2 arcseconds relative to the photosphere. That UV light never was "below" the photosphere.

I don't know if its intensity of source, density of photosphere or the composition of the photosphere but at 192 I'm sure it is under the photosphere. Look at the structures underneath the loops.
That is supposed to be a plasma. NOT Under the photosphere.
http://trace.lmsal.com/POD/images/arcade_9_nov_2000.gif
You are assuming that the dark base of the TRACE image is the photosphere, but absent corroborating evidence, it is only an arbitrary assumption. How do you know that the dark base of the image is not just the cooler base of the transition region?

But even if it actually is the photosphere, so what? As you like to say, look at the image. Let us suppose for the sake of argument, that the dark base of the image really is the photosphere. Where in that image do you see bright emission through the photosphere? The answer is "nowhere". The bright spots are all visible at the base of the valleys or depressions in the dark surface, all above the dark surface. So even if we give you every assumption you want, even your own image does not show any evidence of seeing UV emission through any appreciable or significant depth of photospheric material.
 
A plasma YES!
Under the photosphere NOT!

Read the facts about the photosphere and understand that its definition is that it is where the light escapes the sun. By definition you cannot see under it.

Dude!! I know what your definition of the photosphere is. Why do you keep assuming that I do not know. We already went over this. We are talking about my model. I use your words so that you can understand the location I'm talking about. Every time I use that word "photosphere" you must automatically substitute the words "surface glow".
As I said before my model is different than your model.
Why do you keep inserting your model into my discussion???

Most of the TRACE filters are selected to detect light from the transition region and corona. In case you have forgotten or never known what TRACE stands for it is "Transition Region and Coronal Explorer".

Look at the "192" passband:
Trace passbands

http://trace.lmsal.com/TRACE/Images/pastext.gif

Edited by LashL: 
Removed hotlinked image. Please see Rule 5.



If you mean the 195A passband (perhaps you should give a link to the location where the image is described) then this is plasma at a temperature of 500,000K to 2,000,000K. That is not the photosphere.

But if you want the region below the photosphere to be at 500,000K to 2,000,000K and make your iron sun idea even more impossible than it already is at temperatures of > 9400K then who am I to deny you :)

It seems as if you are doing the same thing as Micheal Mozina - looking at the images without bothering to learn what they are showing.

Check it out. The 195 passband is sensitive to LIGHT from plasma that is 500,000K to 2,000,000K. This same light REFLECTS off of surfaces like normal light.

Now if you look at that picture what do you see?????

The surface is dark. Not at 500,000K to 2,000,000K but still visible.
Why? because of the ambient light from the loop next to it emitting at 500,000K to 2,000,000K is reflecting off of the surface. Remember my drawing??

Look at the loop foot prints. The loop foot prints at the very base of the loop under the surface are hot solid iron. As you climb up the loop, the temperature goes from 3000K molten iron to 9400K boiling iron to 500,000K to 2,000,000K iron vapor/plasma within few hundred km. If the transition layer is only a few thousand km above the surface I'm sure its pretty bright to anyone sitting on the surface. So not only is TRACE looking through the transition layer but it is also seeing the reflected light from the highly luminous plasma in the loops..

Notice how the loop foot prints have space between then. If you take an average temperature reading of that surface from a distance the temperature will not be that of solid iron it will be somewhat higher depending on the average between the number of footprints(high temp) and solid surface area(low temp). Part of this is due to the solar moss(plage).

The black body of the sun is due to the combination of solid surface and surface glow discharge, just like a plasma(solid electrode) arc lamp.

As an aside.
Water cannot be treated as a blackbody both in microwave and white light.

"The emissivity of the water surface changes with the nadir angle of the sensor."
http://books.google.com/books?id=iC...wBA#v=onepage&q=nadir blackbody water&f=false
 
No, that is not what Handy, et al., say. What they say is this: "The correction mechanism described in this paper is able to remove part of the ghosted limb, but it is evident that corrected limb images are still not right. What is left is evidently some form of limb brightening that is not corrected by this method." (Handy, et al., 1999, page 360; this is the full text of the entire top paragraph on that page). You left off the first sentence, and cut the second one in half, putting a period at the end, as if that's where Handy, et al., actually stopped. You present a misleading view of what the paper actually says.

I only did that for brevity.

"What is left is evidently some form of limb brightening that is not corrected by this method."

Let us focus on this sentence for a moment.

"What is left is" So after all of their corrections there is still something left, that was apparently not corrected.
The corrected image are still not right, they have some form of limb brightening, which we have agreed takes place on the sun..

"evidently some form of" Here they are not sure what it is that is left, but they seems as though they are ruling out the instrument..

"limb brightening"
then instead of saying something like, We may need to examine the optical correction for errors or you may need to apply a 10% higher correction factor, or you may need to take an average of the brightness of you image and subtract that, they say it's "limb brightening"!!!
They dont even mention the instrument!!

Its happening on the sun, not in the telescope. Unless you're saying they did not know that limb brightening implied that the phenomena was taking place on the sun.

"that is not corrected by this method." So they must have tried a correction factor more extreme than the empirical one from the Viking probe but it did not go away, the limb brightening.
 
The Solar "Ghost Limb" Is An Optical Artifact X

Its happening on the sun, not in the telescope. Unless you're saying they did not know that limb brightening implied that the phenomena was taking place on the sun.
Of course the limb brightening is happening on the sun, I already said that ...
Limb brightening is a phenomenon of the sun, not of the telescope.
So what's your point?
I have no idea at this stage of the discussion what point you are trying to make. What is it?
 
Dude!! I know what your definition of the photosphere is. Why do you keep assuming that I do not know. We already went over this. We are talking about my model. I use your words so that you can understand the location I'm talking about. Every time I use that word "photosphere" you must automatically substitute the words "surface glow".
As I said before my model is different than your model.
Why do you keep inserting your model into my discussion???


Why do you and Mozina continue to insist that other people should accommodate your lack of ability and/or willingness to use proper terminology? The word "photosphere" already has a perfectly good definition which has nothing to do with a "surface glow" on a physically impossible iron surfaced Sun.
 
Dude!! I know what your definition of the photosphere is. Why do you keep assuming that I do not know. We already went over this. We are talking about my model. I use your words so that you can understand the location I'm talking about. Every time I use that word "photosphere" you must automatically substitute the words "surface glow".

No, if you mean "surface glow" then you must say "surface glow". See how easy that is?

As I said before my model is different than your model.

Then don’t try to obfuscate those differences by using the wrong terms and insisting we “must” acknowledge your difference, by substitution, for you.


Why do you keep inserting your model into my discussion???

Why do you keep interesting your model into the terminology of another model? No one here is insisting that when they say “surface glow” “you must automatically substitute the” word “photosphere".


I always find it a very telling sign of crank “models” when they insist on their differences from other models, but want to use the same terms with different meanings.

I imagine it is perceived as some kind of pseudo-validation of their “model”. That they use the same technical terms that appear in the other models. However this shtick always backfires when they insist that the meaning of the word must change to accommodate their “model”. Not surprising though as for the most part they also insist the whole of physics (or whatever the topic is) must also change in order to accommodate their “model”.
 
Dude!! I know what your definition of the photosphere is. Why do you keep assuming that I do not know. We already went over this. We are talking about my model. I use your words so that you can understand the location I'm talking about. Every time I use that word "photosphere" you must automatically substitute the words "surface glow".
As I said before my model is different than your model.
Why do you keep inserting your model into my discussion???
Dude!!
I keep telling you the definition of the phososphere because yiou keep ignoring it.
Your "model" is that there is a physically impossible iron? surface.
The first problem is that your model of the sun is physically impossible as has been pointed out many times before.
This was usually refering to Micheal Mozina's equally impossible "iron sun" model but if you want we could just repost the simple physics involved with "brantc's iron sun model" substituted. I think that would need a moderator to adjudicate whether that is appropriate.


Alternately you could just read the posts:
So there is not point in discussing it.

If you want to discuss an impossible idea then I suggest that you ask for the thread to be moved out of the Science area, e.g. into the Religion and Philosophy area.

Check it out. The 195 passband is sensitive to LIGHT from plasma that is 500,000K to 2,000,000K. This same light REFLECTS off of surfaces like normal light.
There is no reflection off a physically impossible surface.

Now if you look at that picture what do you see?????
...snipped...
I see an image of light emitted from material at a temperature of 500,000K to 2,000,000K. That is the quite basic physics involved in taking these images. A passband that only detects light from material at a certain temperature .... only detects light from material at the temperature :eye-poppi !
 
I see an image of light emitted from material at a temperature of 500,000K to 2,000,000K. That is the quite basic physics involved in taking these images. A passband that only detects light from material at a certain temperature .... only detects light from material at the temperature :eye-poppi !

Or it will detect 192/5A light from reflections off of solid material at a lower temperature. Like the mirror in TRACE'S telescope.:eye-poppi
That mirror is no where near 1 million degrees. Same with the solar surface.

Basic physics.

So if the surface did exist then there is no problem with the reflection part.

We will get to the thermodynamic considerations.

It is your contention using your photosphere model that not enough energy escapes to allow a solid iron surface to exist under "your photosphere model".
And I'm sure your model requires complete coverage of the lower surface to achieve your goals(molten iron/plasma).

It is my contention that enough energy escapes from under the surface glow to allow a solid surface to exist in my surface glow model.

Your assumption is that the photosphere is the only surface that is emitting energy.
And there are various energy release mechanisms to prevent the iron surface from heating up..
Sun spots(holes), CME, coronal loops, IR from the solid surface below the glow, Solar wind, polar plumes, and not all of the visible comes from the photosphere. And neither does the UV which is the most energetic and variable part of the solar spectrum.
 
Or it will detect 192/5A light from reflections off of solid material at a lower temperature. Like the mirror in TRACE'S telescope.:eye-poppi
That mirror is no where near 1 million degrees. Same with the solar surface.

Basic physics.

So if the surface did exist then there is no problem with the reflection part.

We will get to the thermodynamic considerations.
So we are on the same page at last: Any light can reflect off a reflective surface.
The problem is that the Sun is too hot for any such surface to exist.

It is your contention using your photosphere model that not enough energy escapes to allow a solid iron surface to exist under "your photosphere model".
And I'm sure your model requires complete coverage of the lower surface to achieve your goals(molten iron/plasma).
I have no "contention".
The facts are that
  1. There is overwhelming evidence that Sun is internally heated through fusion. The observed neutrinos types are a fingerprint of fusion. The observed neutrino flux matches enough fusion to produce the energy output of the Sun.
    This means that the temperature of the photosphere is the minimum temperature of the Sun before light escapes from it. This is simple thermodynamics - the closer you get to a source of heat the hotter you get.
  2. The photosphere is at a temperature of ~6000 K. The temperature increases with depth to ~9400 K at a depth of a few hundred kilometers. This supports pont 1.
Thus the Sun is too hot for any solid surface to exist.

So that finishes the thermodynamic considerations.
 
Iron Sun Surface Thermodynamically Impossible VI

Dude!!I see an image of light emitted from material at a temperature of 500,000K to 2,000,000K. That is the quite basic physics involved in taking these images. A passband that only detects light from material at a certain temperature .... only detects light from material at the temperature :eye-poppi !
Or it will detect 192/5A light from reflections off of solid material at a lower temperature. Like the mirror in TRACE'S telescope.:eye-poppi
That mirror is no where near 1 million degrees. Same with the solar surface.

Basic physics.

So if the surface did exist then there is no problem with the reflection part.

Well, now, let's talk about basic physics and see if there really is "no problem".

First, what about "just like the mirror in TRACE'S telescope". The mirrors in TRACE, like any other astronomical mirror, are highly polished to enhance reflectivity. Is the "surface" of the sun (whatever it might be made of) highly polished? Unlikely, I think. And in the case of TRACE, the primary mirror is coated with special, normal incidence coatings that further enhance reflectivity at UV & EUV wavelengths, and to narrow the passband. Are there any reflectivity enhancing coatings on the surface of the sun? I think that too is unlikely.

Next, let's ask what this reflective surface is made of. In keeping with the primary consideration of this thread, let's just assume the surface is iron (or at least mostly iron). I don't know how iron reflects EUV wavelengths, but in a moment I will guess. Meanwhile, I do know that iron reflects visible light about 62% at the red end (7000Å) down to 52% at the blue end (4000Å). If we simply assume a linear trend to shorter wavelengths, we would get about 35% reflectivity around 192Å or 195Å. But that does assume a specular surface and we know that dispersion off of a non-specular surface will degrade the reflectivity, so 35% would be a best-case scenario guess.

But here comes that basic physics. Photons that ionize iron don't reflect off of an iron surface, they ionize it and disappear in the process. Likewise, photons that carry enough energy to melt iron don't reflect off of an iron surface, they melt it and disappear in the process. The 192/5Å passband represents Fe XII (11-times ionized iron). So we would expect photons at that wavelength to preferentially not reflect off of an iron surface, but rather to ionize it. Furthermore, the 192/5Å passband represents the peak of thermal emission in the broad range of temperatures 500,000 - 2,000,000 Kelvins. Since the melting point of iron is 1811 Kelvins, and its boiling point is 3134 Kelvins, we would expect photons in the 192/5Å passband to melt & vaporize the iron surface and disappear in the process, and not to reflect off of the surface.

So, why does the mirror on TRACE not melt in the face of melting photons in the 192/5Å passband? It's all about intensity. The TRACE mirror has to deal with a few photons. One at a time, we don't necessarily expect the photons to ionize or melt anything (although the coatings are intended in part to prevent degradation of the primary mirror). But when photons gang up on a surface, they can and will provide enough thermal energy to melt & vaporize that surface, and then ionize the resulting vapor. Here at Earth, where we find TRACE, the incident solar EUV flux will be about 2 erg cm-2 sec-1, whereas at the sun we are looking at roughly 600,000 erg cm-2 sec-1 (which will be much higher near active regions). And do note this is EUV flux only, the bolometric flux at the photosphere is about 60,000,000,000 erg cm-2 sec-1. That's a lot of photons, and we cannot simply pretend that any solid surface is immune to the effect of that kind of photon bath.

So basic physics presents a problem after all. No, TRACE should not see any photons in the 192/5Å passband reflecting off of any iron surface. Rather, all of those photons should disappear in the process of melting, vaporizing and ionizing that surface. Furthermore, a little consideration shows that this should be the case no matter what the surface is made out of, since the temperature range 500,000 - 2,000,000 Kelvins vastly exceeds the boiling point of all known materials. So photons of the 192/5Å passband should not reflect off of any surface on the sun, regardless of its chemical/physical makeup.

We will get to the thermodynamic considerations.

It is your contention using your photosphere model that not enough energy escapes to allow a solid iron surface to exist under "your photosphere model". And I'm sure your model requires complete coverage of the lower surface to achieve your goals(molten iron/plasma).
You may be sure, but you are still wrong. The only thing required is that enough incident radiation falls on the surface to prevent it from being solid, and that radiation can come from any direction. So ever if the hot stuff is "way over there", if it covers a sufficient fraction of the sky, it will melt the surface.

It is my contention that enough energy escapes from under the surface glow to allow a solid surface to exist in my surface glow model.
Earth's atmosphere emits rather less radiation upwards than it does downwards, because the upper layers are cooler then the lower layers (the average annual Earth surface temperature is 288 Kelvins, but the radiative temperature of the top of the atmosphere is 254 Kelvins). We know from limb observations of the sun that, as deep as we can make direct measurements, the solar plasma is warmer at the bottom than at the top; the photosphere, to the extent that we can see it, reaches almost 10,000 Kelvins at the bottom, which is already well in excess of the vaporizing temperature of iron. So, as is the case for Earth, the photosphere of the sun is brighter & hotter at the bottom than at the top.

No spontaneous thermal process can cool the surface under that plasma to a temperature cooler than the plasma without violating the 2nd law of thermodynamics. You need a non-thermal heat pump (like a refrigerator) to pull that off. So what is the non-thrmal heat pump that you hypothesize as a "cooling mechanism" for your iron surface?
 
Or it will detect 192/5A light from reflections off of solid material at a lower temperature. Like the mirror in TRACE'S telescope.:eye-poppi
That mirror is no where near 1 million degrees. Same with the solar surface.

Basic physics.

So if the surface did exist then there is no problem with the reflection part.

We will get to the thermodynamic considerations.

It is your contention using your photosphere model that not enough energy escapes to allow a solid iron surface to exist under "your photosphere model".
And I'm sure your model requires complete coverage of the lower surface to achieve your goals(molten iron/plasma).

It is my contention that enough energy escapes from under the surface glow to allow a solid surface to exist in my surface glow model.

Your assumption is that the photosphere is the only surface that is emitting energy.
And there are various energy release mechanisms to prevent the iron surface from heating up..
Sun spots(holes), CME, coronal loops, IR from the solid surface below the glow, Solar wind, polar plumes, and not all of the visible comes from the photosphere. And neither does the UV which is the most energetic and variable part of the solar spectrum.

You really don't understand thermodynamics.

Absorptivity equals emissivity. There's no getting around that, it's a requirement for the 2nd law of thermodynamics. Violating it is equivalent to perpetual motion.

In order for your solid surface to emit IR radiation, it must also absorb IR radiation. That means that your solid surface will absorb more energy in the IR band than it emits, unless it's hotter than the photosphere. And sun spots don't help you out either, both because they're NOT black in the IR region (they're still quite bright, indicating temperatures well above any solids), and because they cover far too small a fraction of the sun's surface to be a significant factor in radiative loss. CME and coronal loops are also irrelevant, since they can't transport heat away from the surface. I've been through the numbers on solar wind, and it doesn't work. And UV? Sorry, but if your surface is cool, then it's not going to radiate any significant heat in the UV. And before you start blabbing about cathode discharge or other such nonsense, keep in mind that what the surface needs to do to keep from melting is get rid of heat, not just energy. The difference is critical for thermodynamics. The various cathode explanations are akin to claiming that you can cool off a can of gasoline by setting it on fire, since that releases energy.

There are no cooling mechanisms for your solid surface.
 
So we are on the same page at last: Any light can reflect off a reflective surface.
The problem is that the Sun is too hot for any such surface to exist.


I have no "contention".
The facts are that
  1. There is overwhelming evidence that Sun is internally heated through fusion. The observed neutrinos types are a fingerprint of fusion. The observed neutrino flux matches enough fusion to produce the energy output of the Sun.
    This means that the temperature of the photosphere is the minimum temperature of the Sun before light escapes from it. This is simple thermodynamics - the closer you get to a source of heat the hotter you get.
  2. The photosphere is at a temperature of ~6000 K. The temperature increases with depth to ~9400 K at a depth of a few hundred kilometers. This supports pont 1.
Thus the Sun is too hot for any solid surface to exist.

So that finishes the thermodynamic considerations.

The only "evidence" you have for fusion is supposedly neutrinos that change in certain ways(that you cant really see) on the way to the earth.

As far as your claim for a thermodynamically impossible(my model) model.
Your model has more problems than mine.

You have a cool layer that is heated from BOTH SIDES.

Mine is only heated from one side.

If you want to invoke some mechanism for heat transfer, then you can apply that same mechanism to my model.
 
Well, now, let's talk about basic physics and see if there really is "no problem".

First, what about "just like the mirror in TRACE'S telescope". The mirrors in TRACE, like any other astronomical mirror, are highly polished to enhance reflectivity. Is the "surface" of the sun (whatever it might be made of) highly polished? Unlikely, I think. And in the case of TRACE, the primary mirror is coated with special, normal incidence coatings that further enhance reflectivity at UV & EUV wavelengths, and to narrow the passband. Are there any reflectivity enhancing coatings on the surface of the sun? I think that too is unlikely.

Next, let's ask what this reflective surface is made of. In keeping with the primary consideration of this thread, let's just assume the surface is iron (or at least mostly iron). I don't know how iron reflects EUV wavelengths, but in a moment I will guess. Meanwhile, I do know that iron reflects visible light about 62% at the red end (7000Å) down to 52% at the blue end (4000Å). If we simply assume a linear trend to shorter wavelengths, we would get about 35% reflectivity around 192Å or 195Å. But that does assume a specular surface and we know that dispersion off of a non-specular surface will degrade the reflectivity, so 35% would be a best-case scenario guess.

But here comes that basic physics. Photons that ionize iron don't reflect off of an iron surface, they ionize it and disappear in the process. Likewise, photons that carry enough energy to melt iron don't reflect off of an iron surface, they melt it and disappear in the process. The 192/5Å passband represents Fe XII (11-times ionized iron). So we would expect photons at that wavelength to preferentially not reflect off of an iron surface, but rather to ionize it. Furthermore, the 192/5Å passband represents the peak of thermal emission in the broad range of temperatures 500,000 - 2,000,000 Kelvins. Since the melting point of iron is 1811 Kelvins, and its boiling point is 3134 Kelvins, we would expect photons in the 192/5Å passband to melt & vaporize the iron surface and disappear in the process, and not to reflect off of the surface.

So, why does the mirror on TRACE not melt in the face of melting photons in the 192/5Å passband? It's all about intensity. The TRACE mirror has to deal with a few photons. One at a time, we don't necessarily expect the photons to ionize or melt anything (although the coatings are intended in part to prevent degradation of the primary mirror). But when photons gang up on a surface, they can and will provide enough thermal energy to melt & vaporize that surface, and then ionize the resulting vapor. Here at Earth, where we find TRACE, the incident solar EUV flux will be about 2 erg cm-2 sec-1, whereas at the sun we are looking at roughly 600,000 erg cm-2 sec-1 (which will be much higher near active regions). And do note this is EUV flux only, the bolometric flux at the photosphere is about 60,000,000,000 erg cm-2 sec-1. That's a lot of photons, and we cannot simply pretend that any solid surface is immune to the effect of that kind of photon bath.

So basic physics presents a problem after all. No, TRACE should not see any photons in the 192/5Å passband reflecting off of any iron surface. Rather, all of those photons should disappear in the process of melting, vaporizing and ionizing that surface. Furthermore, a little consideration shows that this should be the case no matter what the surface is made out of, since the temperature range 500,000 - 2,000,000 Kelvins vastly exceeds the boiling point of all known materials. So photons of the 192/5Å passband should not reflect off of any surface on the sun, regardless of its chemical/physical makeup.


EUV microscope explores nanoscale

A team of US, Russian and Ukrainian scientists is using a table-top extreme ultraviolet (EUV) illumination source to create an optical microscope that can image features as small as 100 nm. Operating in reflection mode and requiring little sample preparation, the EUV microscope can rapidly characterize the topography of microelectronic circuits, lithography masks and other material surfaces. (OPTICS EXPRESS 13 3983)
http://nanotechweb.org/cws/article/tech/22552

I never said the surface was immune to that flux of photons. But that doesnt mean the surface is not visible at those wavelengths. And its probably sputtering off great amounts of iron. But we know how much from the heavy atoms in the solar wind.
 
The only "evidence" you have for fusion is supposedly neutrinos that change in certain ways(that you cant really see) on the way to the earth.
The evidence for fusion is that fusion has a specific signature, i.e. gives off certain neutrinos. These neutrinos are detected in the types and amount that show that the sun is powered by fusion.
As for neutrino oscillation - the evidence for this has been established both from solar observations, atmospheric neutrinos, neutrinos from nuclear reactors and neutrino beams from particle accelerators.

The basic concepts behind the neutrino oscillation experiments are really simple, e.g.
  1. Create a beam containing neutrinos of a known type.
  2. Point the beam at a neutrino observatoriy some distance away.
  3. Detect the neutrinos and determine what type they are.
  4. If neutrino oscillation does not exist then you should only detect the original type of neutrino.
  5. The experiments do not thus neutrino oscillation does exist.
The details though are quite complex.

As far as your claim for a thermodynamically impossible(my model) model.
Your model has more problems than mine.
The only problem is with your model of the sun is that it is physically impossible as has been pointed out many times before. That makes any assertions you make about it moot. You should read the posts:
The current solar model does describe the sun well in general. It has many problems like all scientific theories, e.g. the several theories to explain the coronal heating problem do not quite work (yet).
N.B. there is no problem with fusion powering the sun in the current solar model.

You have a cool layer that is heated from BOTH SIDES.

Mine is only heated from one side.

If you want to invoke some mechanism for heat transfer, then you can apply that same mechanism to my model.
Yours is also heated from both sides enough to melt
  • Fusion from below: ~13,000,000 K at the core.
  • Plasma above whatever depth you have arbitrarily placed your surface:
    • ~5700 K at the top of the photosphere.
    • ~9400 K a few hundred kilometers below the top of the photosphere.
The minimum temperature at both sides of your layer is ~5700 K. And since we do not see a solid surface at the top of the photosphere your layer is heated by much more.

You need to specify the mechanism that stops your model's layer from exploding!
 
I never said the surface was immune to that flux of photons. But that doesnt mean the surface is not visible at those wavelengths. And its probably sputtering off great amounts of iron. But we know how much from the heavy atoms in the solar wind.


The surface is not visible because the surface does not exist. That fact has been explained dozens, maybe hundreds of times in this thread alone, and is irrefutably supported by several very well developed branches of astrophysical and related sciences including thermodynamics, general relativity, and helioseismology. Your continued arguments from incredulity and ignorance do not support your claim.
 
As far as your claim for a thermodynamically impossible(my model) model.
Your model has more problems than mine.

You have a cool layer that is heated from BOTH SIDES.

No, it isn't. The corona is a higher temperature, but it's also transparent, which means that it doesn't stop outgoing radiation and provides very little ingoing radiation. The photosphere radiatively couples to deep space, not the corona. But anything under the photosphere cannot radiatively couple to deep space, but only to the photosphere. Again, basic thermodynamics fail.

Mine is only heated from one side.

No, brantc. Your model is heated from ALL sides.

If you want to invoke some mechanism for heat transfer, then you can apply that same mechanism to my model.

Obviously not, since the corona is transparent but the 5700K photosphere is not. Thanks for demonstrating that you haven't learned a thing.
 
The surface is not visible because the surface does not exist. That fact has been explained dozens, maybe hundreds of times in this thread alone, and is irrefutably supported by several very well developed branches of astrophysical and related sciences including thermodynamics, general relativity, and helioseismology. Your continued arguments from incredulity and ignorance do not support your claim.

No. I dont think so.

For instance lets do a little media surfing.

"Science News"
By Alexandra Witze
July 31st, 2010; Vol.178 #3 (p. 18)

Physicists do know a lot about the sun and how it works: Hydrogen atoms fuse in its core, forging helium and heavier elements and spewing out energy in the process. But over the past several years, scientists have dramatically overhauled estimates of the sun’s chemical makeup. In particular, they say there may be far less of key elements such as oxygen, carbon and nitrogen than previously thought. These changes are major enough to throw into question other basic assumptions about the sun, such as ideas about how sound waves travel through its interior, ringing it like a gong."

More like a bounded sphere as opposed to a decreasing density plasma sphere. They had to change the model from a plasma sphere to a gong sphere.

"These recalculations seemed to improve things, by tightening estimates for the abundances of elements like iron and silicon. “It was only when we started applying it to more important elements like oxygen and carbon, the most abundant metals in the sun, that we quite quickly realized our results were going to be very different,” says Martin Asplund, an astronomer at the Max Planck Institute for Astrophysics in Garching, Germany.

Asplund’s team published estimates of solar photospheric oxygen abundance that were 30 to 40 percent lower than commonly accepted values, with similar changes for carbon, nitrogen and neon. The researchers also analyzed the other elements in the sun, most of which required only minor revisions. In all, the team found a solar metal content not of 2 percent, but of 1.4 percent. The researchers summarized their latest work last year in the Annual Review of Astronomy and Astrophysics."

"The work of Asplund’s team throws a wrench in that picture. If models of the solar interior are adjusted to fit the 30 to 40 percent lower oxygen abundance in the photosphere, then they no longer match up with helioseismologists’ observations. For instance, the models now calculate incorrect values for the speed of sound and the density within the sun, as compared with those actually measured."
http://www.sciencenews.org/view/feature/id/61127/title/Beneath_that_blazing_facade

So what that means is that with less heavier elements the sound speed does not match calculations. That means a model that has a heavier "core" fits better.

In addition to that from Nature;

The proton shrinks in size

Tiny change in radius has huge implications.

http://www.nature.com/news/2010/100707/full/news.2010.337.html


Particle physics: 'Honey, I shrunk the proton'

"Even if the deviation is negligible on a day-to-day scale, it possibly has significant consequences. Researchers are unable to say precisely what these may be, however. What is certain is that this changes the Rydberg constant. Quantum physicists use this constant to calculate which energy packets atoms and molecules absorb and emit when they change their states. These energy packets correspond to the spectral lines of the elements. The calculations for the spectral lines now shift noticeably and no longer match the experimental findings."
http://www.physorg.com/news197727820.html

This means that spectral calculations may also be off.

That means that calculated opacities will be off. That means photospheric opacities may be wrong. Or that my model is more likely to be right.

So what I am seeing is that as the measurements get more accurate the models, accepted models("very well developed branches"), break.

So I wonder how much heat energy is actually put out by my surface glow layer if it is a layer . How much heat/light is put out by the surface?
10-7 g/cm3 is the density of the photosphere. How much heat do you think a vacuum puts out?

So if I do an experiment where I levitate a iron slug with a magnetic field in a 6K plasma, do you think the slug will eventually melt?
Or do you think it will re-radiate enough energy in IR to prevent it from melting....

The Levitated Dipole eXperiment
http://www.psfc.mit.edu/ldx/

The surface glow may put out a spectrum that says 5.8K but a large percentage of white light, UV, IR comes from the surface in the form of flares.


From a paper that I dont necessarily agree with the conclusions but he has some interesting things to say.

"Seismology:
The Sun is a laboratory of seismology [17]. Yet, on Earth, seismology is a science of the condensed state. It is interesting to highlight how the gaseous models of the Sun fail to properly fit seismological data. In the work by Bahcall et. al. [18] for instance, experimental and theoretical siesmological findings are compared as a function of Solar radius. Precise fits are obtained for most of the solar sphere. In fact, it is surprising how the interior of the Sun can be so accurately fitted, given that all the data is being acquired from the solar surface. At the same time, this work is unable to fit the data
in the exterior 5% of the Sun [18]. Yet, this is precisely the point from which all the data is being collected. The reason that this region cannot be fitted is that the gaseous models are claiming that the photosphere has a density on the order of 10-7 g/cm3. This is lower than practical vacuums on Earth.
Thus, the gaseous models are trying to conduct seismology in a vacuum by insisting on a photospheric density unable to sustain seismic activity."
http://thermalphysics.org/Sun.evidence.1.pdf
 
No. I dont think so.

For instance lets do a little media surfing
...various news reports...
No. I don't think that any of these news reports address the fact that your idea is physically impossible according to quite basic physics as pointed out to you in many posts.

All you have is a list of normal science using the normal scientific process, i.e.. as more evidence the models break and better models that fit the evidence are created.


The composition of the photosphere does not matter.
  • It's temperature is measured to be ~5700 K at the top and increase with depth (~9400 K at a few 100 kilometers).
  • There is overwhelming evidence that the Sun is has a core undergoing fusion and and the models predict a temperature of ~13,000,000 K.
This evidence rules out any solid surface. Thus your idea is not only broken because of the existing evidence - it is totally vaporized!

That means that calculated opacities will be off. That means photospheric opacities may be wrong. Or that my model is more likely to be right.
You do not have a "model" - that suggests that you can produce numeric predictions like the scientific solar model.
What you have is an idea that is easily seen to be physically impossible.
 
From a paper that I dont necessarily agree with the conclusions but he has some interesting things to say.
...
http://thermalphysics.org/Sun.evidence.1.pdf
The author is distinguished but has no formal background in astronomy: "Pierre-Marie L. Robitaille, Ph.D. is currently a Professor of Radiology at The Ohio State University in Columbus, Ohio.".

You gave no evidence of the PDF ever being published. However it was published in Progress in Physics which has a dubious reputation. The paper by itself makes the journal quite dubious.

Pierre-Marie L. Robitaille makes basic mistakes, e.g.
  • "The fact that this spectrum is continuous in nature leads to difficulties for the gaseous models [1]. This is because gases are known to emit radiation only in discrete bands [12]".
    Plasma is known to emit continuous spectrum due to free electrons.
  • "The atmosphere of the Earth does not collapse due to the relatively rigid oceanic and continental surfaces. Within the gaseous models of the stars however, there is no mechanism to introduce the rigid surface required to maintain gas pressure."
    There is no solid surface needed to maintain pressure in any body of gas (or plasma). All you need is a force to keep the body of gas together - like gravity.
 
Hi Brantc!
http://thermalphysics.org/Sun.evidence.1.pdf

Really? he claims to have disporoved the universality of black body radiation, in a paper that references his papre that references another paper, one of which was published.

Um sure whatever.

A true blackbody spectrum comes only from a solid body. That box in kirchoffs experiment will never be thermally equilibrated.

Plasma only emits lines. Water is not a blackbody as the emission changes with the nadir angle.


Thats his basic argument.

And its true.

Thats why the solar spectrum is the result of a solid body + arc overlayed with plasma.
 
No, it isn't. The corona is a higher temperature, but it's also transparent, which means that it doesn't stop outgoing radiation and provides very little ingoing radiation. The photosphere radiatively couples to deep space, not the corona. But anything under the photosphere cannot radiatively couple to deep space, but only to the photosphere. Again, basic thermodynamics fail.
No, brantc. Your model is heated from ALL sides.

Obviously not, since the corona is transparent but the 5700K photosphere is not. Thanks for demonstrating that you haven't learned a thing.

Sure. With your model of the photosphere. But we are not talking about that are we.

Since the loop foot prints are visible in white light then you can see through the photosphere which is just a layer of plasma about 200 to 400km thick.

Not your surface of last scattering after photons have traveled ten bizillion years randomly to the surface. And then the have emerged with exactly the right spectrum to simulate a perfect blackbody.
LOL.... Its a decreasing density plasma ball with a "convection" and some other kind of layer. And like thats not going to show up in the spectrum....:p


As far as the photosphere goes its so thin that its thermodynamically impossible for that layer to trap 100% of all out going radiation.

Its so thin that its total heat emission is lower than the total heat emission from the solid surface below.


Here let me say that again.


Its so thin that its total heat emission is lower than the total heat emission from the solid surface below.



RC...

The thermosphere is 1500K- 2500K how come the earth doesnt overheat???????


"The thermosphere is the biggest of all the layers of the earth's atmosphere directly above the mesosphere and directly below the exosphere. Within this layer, ultraviolet radiation causes ionization.

The highly diluted gas in this layer can reach 2,500 °C (4,530 °F) during the day. Even though the temperature is so high, one would not feel warm in the thermosphere, because it is so near vacuum that there is not enough contact with the few atoms of gas to transfer much heat. A normal thermometer would read significantly below 0 °C (32 °F), due to the energy lost by thermal radiation overtaking the energy acquired from the atmospheric gas by direct contact."
http://en.wikipedia.org/wiki/Thermosphere


Dont you get this yet?????? The photosphere on the sun is of lower density than the thermosphere......
 
Solar Photosphere vs Terrestrial Thermosphere

Don't you get this yet?????? The photosphere on the sun is of lower density than the thermosphere ......
Not really. The thermosphere mass density, in the high temperature regions you are talking about, ranges between 10-8 and 10-9 gm/cm3, whereas the mass density of the solar photosphere, at optical depth 1 and temperature 6520 Kelvins, is about 3x10-7 gm/cm3, 30 to 300 times the mass density of the thermosphere. The solar photosphere does not get that tenuous until about 400 km above the optical depth 1 layer, where its mass density reaches about 10-8 gm/cm3 and its temperature falls to about 4600 Kelvins (it falls to a local minimum of about 4400 Kelvins at 500 km and then increases again to over 6000 Kelvins at the top, where the mass density is a meager 10-11 gm/cm3). So you are off by at least an order of magnitude there.

As far as the photosphere goes its so thin that its thermodynamically impossible for that layer to trap 100% of all out going radiation.
That does not really make any physical sense. Anything that is in thermal equilibrium, whether thin or thick, will not trap any of the out going radiation, not even 1%, let alone 100%. It will absorb energy on one side, and emit the same amount of energy on the other side, minus the energy needed to maintain its kinetic temperature. Now, I suspect what you think you are saying (in which case you should actually say it instead of something else), is that the photosphere is transparent at some wavelength. That's an easy assertion to make, but not to prove. If you think it is, all you have to do is specify the constituent gases, their density & temperature, and compute the opacity/transparency at a given wavelength. The trick is that if your model photosphere is not consistent with observations, then nobody will believe you, and for good reason.

Since the loop foot prints are visible in white light then you can see through the photosphere which is just a layer of plasma about 200 to 400km thick.
Non-sequitor. What does being visible in white light, or any other light, have to do with "through the photosphere"? how do you know that that the bright patches do not originate where they appear to originate, namely above the photosphere, where they appear in the images?

The thermosphere is 1500K- 2500K how come the earth doesnt overheat???????
First, get the temperatures right. Zero Celsius is +273.5 Kelvin (let's call it 273 for simplicity), so 1500 - 2500 Celsius from the Wikipedia page is 1227 - 2227 Kelvins, a difference of 11% at the high end, which is significant.

Second, you have to realize that there are two different kinds of temperature here. The quoted temperature for the thermosphere is a kinetic temperature, derived from the kinetic energy of the molecules in the atmosphere. A thermometer in that dilute gas does not register the high temperature because only a few molecules hit it per second. So the actual energy transfer from the gas to any object in the gas is miniscule, despite the high temperature. However, the quoted temperature for the solar photosphere is not a kinetic temperature, it is a radiative temperature, which means it represents the energy of the photons, not the kinetic energy of the particles. Radiative temperature & kinetic temperature are not at all the same thing, but you are treating them as such, and that is wrong.

If you hold a thermometer in the thermosphere gas, it gains energy from infrequent molecular collisions, and the photons of sunlight at the Earth (about 1365 Watts/meter2, the solar constant). However, if you hold a thermometer in the gas of the solar photosphere, it gains energy from more frequent atomic collisions (at least 10 times the mass density) and the photons of sunlight at the photosphere (about 63,000,000 Watts/meter2). That's why the Earth does not over heat, the power in the photon bath at the solar photosphere is 46,154 times more intense per unit area than here on Earth. Put Earth in the photosphere, and you can bet it will overheat.
 
A true blackbody spectrum comes only from a solid body. That box in kirchoffs experiment will never be thermally equilibrated.

Plasma only emits lines. Water is not a blackbody as the emission changes with the nadir angle.


Thats his basic argument.

And its true.

Thats why the solar spectrum is the result of a solid body + arc overlayed with plasma.

And if you ignore what has been said before about the emission of free electrons, then it makes you look like you don't really know much about plasma or physics.

Seriously Brantc, you got served on this issue before.
 
Sure. With your model of the photosphere. But we are not talking about that are we.


Apparently you are talking about a model which isn't based in physical reality.

Since the loop foot prints are visible in white light then you can see through the photosphere which is just a layer of plasma about 200 to 400km thick.


You can't see through the photosphere.

Not your surface of last scattering after photons have traveled ten bizillion years randomly to the surface. And then the have emerged with exactly the right spectrum to simulate a perfect blackbody.
LOL.... Its a decreasing density plasma ball with a "convection" and some other kind of layer. And like thats not going to show up in the spectrum....:p


As far as the photosphere goes its so thin that its thermodynamically impossible for that layer to trap 100% of all out going radiation.

Its so thin that its total heat emission is lower than the total heat emission from the solid surface below.


The photosphere is, by definition, the region in the Sun's atmosphere where the plasma goes from being transparent to being opaque. You can't see through the photosphere.

Here let me say that again.


Its so thin that its total heat emission is lower than the total heat emission from the solid surface below.


Here, let me say that again. The photosphere is defined as the region where the solar atmosphere transitions from being transparent to being opaque. You cannot see through it. Nobody can. Is there some particular reason you insist on trying to change the perfectly good, valid, legitimately scientific definition of the word?

You're continuing to try to describe a fantasy Sun, one whose existence has been demonstrated time and again to be impossible. There are several very highly developed branches of physics which show, to the satisfaction of every professional solar physicist on Earth, that your claim is false, your incessant arguments from incredulity and ignorance notwithstanding.
 
RC...

The thermosphere is 1500K- 2500K how come the earth doesnt overheat???????

brantc...
So obvous that I am going to leave it as anexercise for you (hints: inverse square law & 93 milloion miles)

Dont you get this yet?????? The photosphere on the sun is of lower density than the thermosphere......
The photosphere is also of lower density than:
  • The surface of the Earth.
  • The core of the Earth.
  • The computer that I am writing this post on.
  • Me :) !
Your point is??????

There is the Wikipedia quote without your strange highlighting
Thermosphere
The thermosphere is the biggest of all the layers of the earth's atmosphere directly above the mesosphere and directly below the exosphere. Within this layer, ultraviolet radiation causes ionization.
...
The highly diluted gas in this layer can reach 2,500 °C (4,530 °F) during the day. Even though the temperature is so high, one would not feel warm in the thermosphere, because it is so near vacuum that there is not enough contact with the few atoms of gas to transfer much heat. A normal thermometer would read significantly below 0 °C (32 °F), due to the energy lost by thermal radiation overtaking the energy acquired from the atmospheric gas by direct contact.
Fairly standard physics:
  • The thermosphere is a rarefied gas with particles moving at a high speed. This corresponds with a temperature of 2,500 °C during the day.
  • A normal thermometer would lose a lot of heat through radiation and gain a little heat through contact and so will have a low temperature reading.
 
And if you ignore what has been said before about the emission of free electrons, then it makes you look like you don't really know much about plasma or physics.

Seriously Brantc, you got served on this issue before.

Ok. Refresh me. Serve me again.
 
Apparently you are talking about a model which isn't based in physical reality.
You can't see through the photosphere.

The photosphere is, by definition, the region in the Sun's atmosphere where the plasma goes from being transparent to being opaque. You can't see through the photosphere.

I know what your definition is. And just because you say it doesn't make it so.

My model is different than your definition.


Here, let me say that again. The photosphere is defined as the region where the solar atmosphere transitions from being transparent to being opaque. You cannot see through it. Nobody can. Is there some particular reason you insist on trying to change the perfectly good, valid, legitimately scientific definition of the word?
I am not changing your definition of the word.
My definition of the luminous region that covers the surface of the sun is surface glow. You can use the word photosphere however you want.

You're continuing to try to describe a fantasy Sun, one whose existence has been demonstrated time and again to be impossible. There are several very highly developed branches of physics which show, to the satisfaction of every professional solar physicist on Earth, that your claim is false, your incessant arguments from incredulity and ignorance notwithstanding.
The internal fusion model is dead.

You have not demonstrated that my model is impossible. Far from it.

As a matter of fact the latest data I have showed indicates that your model is not heavy enough. Metals do not match helioseismology data.
According to the latest measurements of the proton there are problems with opacity calculations as well.

You know nothing about your model except from what you see on the surface(maybe neutrinos)...
 
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You can't see through the photosphere.

It has already been agreed that the footprint of the loops are below the photosphere.

TRACE observes white light flares above the limb at the base of certain loops. According to Tim this Ghost limb, where the flare footprints take place is an artifact of the telescope.

So if this is an artifact and then if you correct for the artifact (2 degree wedge) then that places the white light flares under the photosphere at the loops footprints. I have already said that the loop footprints should produce white light flares.


Here again are pictures of the loop footprints which emit from IR to EUV.
Notice the solar moss also emits at EUV.
http://trace.lmsal.com/POD/images/T171_001017_033928.jpg
http://trace.lmsal.com/POD/images/arcade_9_nov_2000.gif

The loops are 50,000 to 75,000km high. That means the structure under them is higher than the transition region, photosphere and chromosphere.

So we have loop footprints, solar moss and structures under the loops in these pictures.
 
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